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Laravel csrf token mismatch for ajax POST Request

I am trying to delete data from database via ajax.

HTML:

@foreach($a as $lis)
  //some code
  <a href="#" class="delteadd" id="{{$lis['id']}}">Delete</a>
  //click action perform on this link                  
@endforeach

My ajax code:

$('body').on('click', '.delteadd', function (e) {
e.preventDefault();
//alert('am i here');
if (confirm('Are you sure you want to Delete Ad ?')) {
    var id = $(this).attr('id');
    $.ajax({
        method: "POST",
        url: "{{url()}}/delteadd",
        }).done(function( msg ) {
        if(msg.error == 0){
            //$('.sucess-status-update').html(msg.message);
            alert(msg.message);
        }else{
            alert(msg.message);
            //$('.error-favourite-message').html(msg.message);
        }
    });
} else {
    return false;
}
});

This is my query to fetch data from database...

$a = Test::with('hitsCount')->where('userid', $id)->get()->toArray();

But when i click on Delete link data not deleted and show csrf_token mismatch...

you should add success and error to your ajax code. the error will show the problem. stackoverflow.com/questions/45668337/…
use the following link Laravel official site

z
zarpio

The best way to solve this problem "X-CSRF-TOKEN" is to add the following code to your main layout, and continue making your ajax calls normally:

In header

<meta name="csrf-token" content="{{ csrf_token() }}" />

In script

<script type="text/javascript">
$.ajaxSetup({
    headers: {
        'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
    }
});
</script>

This is the better solution because you can use it inside .js files
what if "global:false"?
How the csrf can be updated after each call? the first call works great, subsecuent calls fails due to CSRF token.
@zarpio I am doing with the same method. However, token mismatch error over there in my ajax call. Kindly help me.
D
Deepak saini

You have to add data in your ajax request. I hope so it will be work.

data: {
        "_token": "{{ csrf_token() }}",
        "id": id
        }

What if the ajax function is located in .js file?
It doesn't works on Laravel 5.7. zarpio's answer is correct.
@Brane send the token as a param in the function
This doesn't work in Laravel 5.8. It still says token mismatch. Check my answer below for a simple solution
does laravel change csrf token after a json request? do you need to send the new one to main page?
l
lewis4u

I just added headers: in ajax call:

  headers: {'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')},

in view:

<div id = 'msg'>
     This message will be replaced using Ajax. Click the button to replace the message.
</div>

{!! Form::submit('Change', array('id' => 'ajax')) !!}

ajax function:

<script>
 $(document).ready(function() {
    $(document).on('click', '#ajax', function () {
      $.ajax({
         type:'POST',
         url:'/ajax',
         headers: {'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')},
         success:function(data){
            $("#msg").html(data.msg);
         }
      });
    });
});
</script>

in controller:

public function call(){
    $msg = "This is a simple message.";
    return response()->json(array('msg'=> $msg), 200);
}

in routes.php

Route::post('ajax', 'AjaxController@call');

Laravel 8^

Route::post('ajax', [AjaxController::class, 'call']);

yeah this is the correct solution i guess $.ajaxSetup() makes the global configuration for every request
c
cmnardi

I think is better put the token in the form, and get this token by id

<input type="hidden" name="_token" id="token" value="{{ csrf_token() }}">

And the JQUery :

var data = {
        "_token": $('#token').val()
    };

this way, your JS don't need to be in your blade files.


B
Brane

If you are using template files, than you can put your meta tag in the head section (or whatever you name it) which contain your meta tags.

@section('head')
<meta name="csrf_token" content="{{ csrf_token() }}" />
@endsection

Next thing, you need to put the headers attribute to your ajax(in my example, I am using datatable with server-side processing:

"headers": {'X-CSRF-TOKEN': $('meta[name="csrf_token"]').attr('content')}

Here is the full datatable ajax example:

$('#datatable_users').DataTable({
        "responsive": true,
        "serverSide": true,
        "processing": true,
        "paging": true,
        "searching": { "regex": true },
        "lengthMenu": [ [10, 25, 50, 100, -1], [10, 25, 50, 100, "All"] ],
        "pageLength": 10,
        "ajax": {
            "type": "POST",
            "headers": {'X-CSRF-TOKEN': $('meta[name="csrf_token"]').attr('content')},
            "url": "/getUsers",
            "dataType": "json",
            "contentType": 'application/json; charset=utf-8',
            "data": function (data) {
                console.log(data);
            },
            "complete": function(response) {
                console.log(response);
           }
        }
    });

After doing this, you should get 200 status for your ajax request.


G
Gjaa

Add an id to the meta element that holds the token

<meta name="csrf-token" id="csrf-token" content="{{ csrf_token() }}">

And then you can get it in your Javascript

$.ajax({
  url : "your_url",
  method:"post",
  data : {
    "_token": $('#csrf-token')[0].content  //pass the CSRF_TOKEN()
  },  
  ...
});

EDIT: Easier way without changing the meta line.

data : { 
    _token: "{{ csrf_token() }}" 
}

Or

data : { 
    _token: @json(csrf_token()), 
}

Thanks to @martin-hartmann


If you don't want to add an id, just use: $("[name=csrf-token]").attr("content") instead. It will fetch the right element by the name attribute.
It's also possible to just ad in the data field: data : { "_token": "{{ csrf_token() }}" //pass the CSRF_TOKEN() },
M
Mohamed Allal

Know that there is an X-XSRF-TOKEN cookie that is set for convenience. Framework like Angular and others set it by default. Check this in the doc https://laravel.com/docs/5.7/csrf#csrf-x-xsrf-token You may like to use it.

The best way is to use the meta, case the cookies are deactivated.

    var xsrfToken = decodeURIComponent(readCookie('XSRF-TOKEN'));
    if (xsrfToken) {
        $.ajaxSetup({
            headers: {
                'X-XSRF-TOKEN': xsrfToken
            }
        });
    } else console.error('....');

Here the recommended meta way (you can put the field any way, but meta is quiet nice):

$.ajaxSetup({
    headers: {
        'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
    }
});   

Note the use of decodeURIComponent(), it's decode from uri format which is used to store the cookie. [otherwise you will get an invalid payload exception in laravel].

Here the section about the csrf cookie in the doc to check : https://laravel.com/docs/5.7/csrf#csrf-x-csrf-token

Also here how laravel (bootstrap.js) is setting it for axios by default:

let token = document.head.querySelector('meta[name="csrf-token"]');

if (token) {
    window.axios.defaults.headers.common['X-CSRF-TOKEN'] = token.content;
} else {
    console.error('CSRF token not found: https://laravel.com/docs/csrf#csrf-x-csrf-token');
} 

you can go check resources/js/bootstrap.js.

And here read cookie function:

   function readCookie(name) {
        var nameEQ = name + "=";
        var ca = document.cookie.split(';');
        for (var i = 0; i < ca.length; i++) {
            var c = ca[i];
            while (c.charAt(0) == ' ') c = c.substring(1, c.length);
            if (c.indexOf(nameEQ) == 0) return c.substring(nameEQ.length, c.length);
       }
        return null;
    }

V
Vignesh

you have to include this line in master file

<meta name="csrf-token" content="{{ csrf_token() }}" />

and while calling ajax you have to implement csrf token ,

$.ajax({
url:url,
data:{
 _token:"{{ csrf_token() }}"
},
success:function(result){
 //success message after the controller is done..
}
})

A
AMIB

if you are using jQuery to send AJAX Posts, add this code to all views:

$( document ).on( 'ajaxSend', addLaravelCSRF );

function addLaravelCSRF( event, jqxhr, settings ) {
    jqxhr.setRequestHeader( 'X-XSRF-TOKEN', getCookie( 'XSRF-TOKEN' ) );
}

function getCookie(name) {
    function escape(s) { return s.replace(/([.*+?\^${}()|\[\]\/\\])/g, '\\$1'); };
    var match = document.cookie.match(RegExp('(?:^|;\\s*)' + escape(name) + '=([^;]*)'));
    return match ? match[1] : null;
}

Laravel adds a XSRF cookie to all requests, and we automatically append it to all AJAX requests just before submit.

You may replace getCookie function if there is another function or jQuery plugin to do the same thing.


M
Mrudul Addipalli

who ever is getting problem with the accepted answer @Deepak saini, try to remove

cache:false,
processData:false,
contentType:false,

for ajax call.

use

dataType:"json",

S
Sahil Jain

In case your session expires, you can use this, to login again

$(document).ajaxComplete(function(e, xhr, opt){
  if(xhr.status===419){
    if(xhr.responseJSON && xhr.responseJSON.message=='CSRF token mismatch.') window.location.reload();
  }
});

M
Michael Asefon

If you are work on laravel 7.0 project and facing this error

Adding a token as part of the parameter to be sent to the controller would solve the problem just like the answers given above. This is as a result of Laravel protecting your site against cross-site attack. which requires you to generate a unique token on every form submission.

"_token": "{{ csrf_token() }}"

You can now have;

      const postFormData = {
            'name'     : $('input[name=name]').val(),
            "_token": "{{ csrf_token() }}"
        }; 
         
      $.ajax({
          url: 'pooling'
          , type: 'post'
          , data: postFormData
          , dataType: 'json'
          , success: function(response) { consolel.log(response) }
        });

N
Nava Bogatee

You should include a hidden CSRF (cross site request forgery) token field in the form so that the CSRF protection middleware can validate the request.

Laravel automatically generates a CSRF "token" for each active user session managed by the application. This token is used to verify that the authenticated user is the one actually making the requests to the application.

So when doing ajax requests, you'll need to pass the csrf token via data parameter.

Here's the sample code.

var request = $.ajax({
    url : "http://localhost/some/action",
    method:"post",
    data : {"_token":"{{ csrf_token() }}"}  //pass the CSRF_TOKEN()
  });

U
Udo E.

xxxxxxxOld answer deletedxxxxxxx

CLARIFICATION/UPDATE

The csrf token in the meta header is used for session management

Laravel automatically generates a CSRF "token" for each active user session managed by the application.

It is the same value as that contained in:

@csrf directive inside a form or anywhere else in a Blade template (this generates the _token hidden input field). csrf_token() global helper function used anywhere in a controller or Blade template.

Important

For sessions that are not yet authenticated, the CSRF token is regenerated/different for every served page - i.e. new session data is generated for every loaded page. For a session that is authenticated, the CSRF token is the same for all pages - i.e. session data is maintained across all loaded pages.

Conclusion

Include the CSRF token in Ajax request in the following way:

from the meta header or the generated hidden _token input field - useful when sending Ajax POST request with a form:

<script> 
    $(document).ready(function() { 
        let token = $('meta[name="csrf_token"]').attr('content');
        // let token = $('form').find('input[name="_token"]').val(); // this will also work
        let myData = $('form').find('input[name="my_data"]').val();
        $('form').submit(function() { 
            $.ajax({ 
                type:'POST', 
                url:'/ajax', 
                data: {_token: token, my_data: myData}
                // other ajax settings
            }); 
            return false;
        }); 
    }); 
</script>

Call csrf_token() in a hidden element in Blade template and get the token in js - useful when sending Ajax POST request without a form:

Blade:

<span id='csrf' style='display:none'>{{ csrf_token() }}<span>

JavaScript:

<script> 
    $(document).ready(function() { 
        let token = $('#csrf').html();
        $.ajax({ 
            type:'POST', 
            url:'/ajax', 
            data: {_token: token, my_data: 'john'}
            // other ajax settings
        }); 
    }); 
</script>

m
myself

I just use @csrf inside the form and its working fine


J
Joundill

I always encounter this error recently. Make sure to use a more specific selector when referring to a value. for example instead of $('#firstname') use $('form').find('#firstname');


ids are meant to be unique anyway, so you can't get anything more specific than the #firstname selector.
well.. in my case.. i do have multiple modals.. that's where the conflict begins
That's invalid HTML. From the docs: "The id attribute specifies its element's unique identifier (ID). The value must be unique amongst all the IDs in the element's home subtree and must contain at least one character." The element's home subtree in a webpage is the page.
Ow.. thank you for that.. i think that causes the error. by the way.. $('#myform1').find('#firstname') is not same as $('#myform2').find('#firstname')... so i got an error when only using ('#firstname').. that is why im saying you need to be more specific.
M
Martin Brisiak

Laravel 5.8 use the csrf in the ajax url(separate js file)

$.ajax({
    url: "/addCart" + "?_token=" + productCSRF,
    type: "POST",
    ..
})

r
rameezmeans

guys in new laravel you just need to do this anywhere. in JS or blade file and you will have csrf token.

var csrf = document.querySelector('meta[name="csrf-token"]').content;

it is vanilla JS. For Ajax you need to do this.

var csrf = document.querySelector('meta[name="csrf-token"]').content;
    $.ajax({
        url: 'my-own-url',
        type: "POST",
        data: { 'value': value, '_token': csrf },
        success: function (response) {
            console.log(response);
        }
    });

A
Ashish Singh

Simply putting csrfmiddlewaretoken: '{{ csrf_token }}' inside data works well!!

$.ajax({
    url : "url where you want to send data"
    type : "POST", // http method
    data : {
      name:"...",
      csrfmiddlewaretoken: '{{ csrf_token }}' , #this works for me
    },

    // handle a successful response
    success : function(data){
      alert('......');
    },
    error : function() {
     ..............
    }

});

K
Kolya Slisarenko

There also could be a case when you define your $middlewareGroups

You should use the following format:

protected $middlewareGroups = [
    'web'   => [],
    'api'   => [
        'web',
        'throttle:500,1'
    ],
    'basic' => [
        'auth:basic',
    ]
];

g
glinda93

If you're upgrading laravel from 5 to 8, and face this error, add following to app/Http/Middleware/VerifyCsrfToken.php:

public static function serialized()
{
    return true;
}

M
MUHINDO

In script tag in your blade file, do like this to generate a valid form token and get it in jQuery

<script>
    $(document).ready(function() {
        $("#my-upload-button").click(function() {

            var token = "{{ csrf_token() }}";//here getting token from blade

            $.post('my-url', {
                    _token: token,
                    datra: ...
                },
                function(data) {
                    alert(data); 
                });
        });         

});


Y
Yasser CHENIK

I this problem was resolved for me just by removing processData: false

$.ajax({
                url: '{{ route('login') }}' ,
                method: 'POST',
                data: {
                    _token : {{ csrf_token() }},
                    data : other_data,
                },
                cache: false,
                //processData: false, // remove this

                ...

                success: function(res){
                   ...
                }
});

E
Earth Lander

In your main page (someViewsName.blade.php), declare a global variable

<script>
    var token = "{{ csrf_token() }}";
</script>

<script src="/path/to/your_file.js"></script>

Then, in your_file.js

$.ajax({
        type: "post",
        url: "http://your.url/end/point",
        data: {
                _token:token,
                data:your_data,
              },
        dataType: "json",
        success: function (response) {
            // code some stuff
        }
    });

D
Dlaugh14

I actually had this error and could not find a solution. I actually ended up not doing an ajax request. I don't know if this issue was due to this being sub domain on my server or what. Here's my jquery.

            $('#deleteMeal').click(function(event) {
                var theId = $(event.currentTarget).attr("data-mealId");
                  $(function() {
                    $( "#filler" ).dialog({
                      resizable: false,
                      height:140,
                      modal: true,
                      buttons: {
                      "Are you sure you want to delete this Meal? Doing so will also delete this meal from other users Saved Meals.": function() {
                           $('#deleteMealLink').click();
//                         jQuery.ajax({
//                              url : 'http://www.mealog.com/mealtrist/meals/delete/' + theId,
//                              type : 'POST',
//                              success : function( response ) {
//                                  $("#container").replaceWith("<h1 style='color:red'>Your Meal Has Been Deleted</h1>");
//                              }
//                          });
                        // similar behavior as clicking on a link
                           window.location.href = 'http://www.mealog.com/mealtrist/meals/delete/' + theId;
                          $( this ).dialog( "close" );
                        },
                        Cancel: function() {
                          $( this ).dialog( "close" );
                        }
                      }
                    });
                  });
                });

So I actually set up an anchor to go to my API rather than doing a post request, which is what I figure most applications do.

  <p><a href="http://<?php echo $domain; ?>/mealtrist/meals/delete/{{ $meal->id }}" id="deleteMealLink" data-mealId="{{$meal->id}}" ></a></p>