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如何让 UILabel 响应点击?

我发现我可以比 UITextField 更快地创建 UILabel,并且我计划大部分时间都将 UILabel 用于我的数据显示应用程序。

长话短说,我希望让用户点击 UILabel 并让我的回调响应它。那可能吗?

谢谢。

您需要指定 userInteractionEnabled = true

H
Hemang

您可以将 UITapGestureRecognizer 实例添加到您的 UILabel。

例如:

UITapGestureRecognizer *tapGestureRecognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(labelTapped)];
tapGestureRecognizer.numberOfTapsRequired = 1;
[myLabel addGestureRecognizer:tapGestureRecognizer];
myLabel.userInteractionEnabled = YES;

啊哈,这里的“userInteractionEnabled”属性是关键(因为其他配置可以而且应该最好在情节提要中设置)。标签默认关闭交互,以便通过它们传递触摸 - 但在这种情况下,它们需要观察触摸以激活手势识别器。谢谢!
好东西!我只是在标签上轻按一下,完全忘记了启用用户交互。谢谢!
l
leenyburger

如果您使用情节提要,您可以在情节提要中完成整个过程,而无需额外的代码。向情节提要添加标签,然后向标签添加点击手势。在“实用程序”窗格中,确保为标签选中“已启用用户交互”。从点击手势(在情节提要中视图控制器的底部),ctrl+单击并拖动到您的 ViewController.h 文件并创建一个动作。然后在 ViewController.m 文件中实现动作。


方法也可单独使用界面构建器,无需情节提要
确保在“属性”检查器的“视图”部分下选中“已启用用户交互”,而不仅仅是可访问性特征。
K
Koushik

斯威夫特 3.0

初始化 tempLabel 的手势

tempLabel?.text = "Label"
let tapAction = UITapGestureRecognizer(target: self, action: #selector(self.actionTapped(_:)))
tempLabel?.isUserInteractionEnabled = true
tempLabel?.addGestureRecognizer(tapAction)

动作接收器

func actionTapped(_ sender: UITapGestureRecognizer) {
    // code here
}

斯威夫特 4.0

初始化 tempLabel 的手势

tempLabel?.text = "Label"
let tapAction = UITapGestureRecognizer(target: self, action:@selector(actionTapped(_:)))
tempLabel?.isUserInteractionEnabled = true
tempLabel?.addGestureRecognizer(tapAction)

动作接收器

func actionTapped(_ sender: UITapGestureRecognizer) {
    // code here
}

如何从发件人对象中获取标签文本?换句话说,如何识别发件人?
Swift 4 版本有@selector 而不是#selector。
A
Alvin George

斯威夫特 2.0:

我正在添加一个 nsmutable 字符串作为 sampleLabel 的文本,启用用户交互,添加一个点击手势并触发一个方法。

override func viewDidLoad() {
    super.viewDidLoad()

    let newsString: NSMutableAttributedString = NSMutableAttributedString(string: "Tap here to read the latest Football News.")
    newsString.addAttributes([NSUnderlineStyleAttributeName: NSUnderlineStyle.StyleDouble.rawValue], range: NSMakeRange(4, 4))
    sampleLabel.attributedText = newsString.copy() as? NSAttributedString

    let tapGesture: UITapGestureRecognizer = UITapGestureRecognizer(target: self, action: "tapResponse:")
    tapGesture.numberOfTapsRequired = 1
    sampleLabel.userInteractionEnabled =  true
    sampleLabel.addGestureRecognizer(tapGesture)

}
func tapResponse(recognizer: UITapGestureRecognizer) {
    print("tap")
}

M
Matt S.

您可以改用 UIButton 并将文本设置为您想要的。如果您不想,按钮不必看起来像按钮


关于这一点,我一直遇到 UIButton 左对齐多行文本的问题。即使我将左对齐设置为居中,它仍然会发生。
我确实给了 UIButton 一个尝试,它非常好。只是多行按钮有问题。谢谢。
H
Hardik Thakkar

在 UILable 上添加 Tap 手势

UITapGestureRecognizer *tapAction = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(lblClick:)];
tapAction.delegate =self;
tapAction.numberOfTapsRequired = 1;

//Enable the lable UserIntraction
lblAction.userInteractionEnabled = YES;
[lblAction addGestureRecognizer:tapAction];   

并评估选择器方法

- (void)lblClick:(UITapGestureRecognizer *)tapGesture {

}

注意:在 .h 文件中添加 UIGestureRecognizerDelegate


C
Community

Swift 版本: var tapGesture : UITapGestureRecognizer = UITapGestureRecognizer()

然后在 viewDidLoad() 中添加:

  let yourLbl=UILabel(frame: CGRectMake(x,y,width,height)) as UILabel!

    yourLbl.text = "SignUp"
    tapGesture.numberOfTapsRequired = 1
    yourLbl.addGestureRecognizer(tapGesture)
    yourLbl.userInteractionEnabled = true
    tapGesture.addTarget(self, action: "yourLblTapped:")

H
Hemang

如果您想在按钮中使用多行文本,则使用多行文本创建一个 UILabel,并将其作为子视图添加到您的按钮中。

例如:

yourLabel=[Uilabel alloc]init];
yourLabel.frame=yourButtom.Frame;//(frame size should be equal to your button's frame)
[yourButton addSubView:yourLabel]

M
MRustamzade

来自阿尔文乔治的 Swift 3

override func viewDidLoad() {
    super.viewDidLoad()
    let newsString: NSMutableAttributedString = NSMutableAttributedString(string: "Tap here to read the latest Football News.")
    newsString.addAttributes([NSUnderlineStyleAttributeName: NSUnderlineStyle.styleDouble.rawValue], range: NSMakeRange(4, 4))
    sampleLabel.attributedText = newsString.copy() as? NSAttributedString

    let tapGesture: UITapGestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(ViewController.tapResponse))
    tapGesture.numberOfTapsRequired = 1
    sampleLabel.isUserInteractionEnabled =  true
    sampleLabel.addGestureRecognizer(tapGesture)
}

func tapResponse(recognizer: UITapGestureRecognizer) {
    print("tap")
}

P
Prashant Gaikwad

这在 Xcode 12 和 Swift 5 中效果很好

let tapAction = UITapGestureRecognizer(target: self,action:#selector(actionTapped(_:)))

userLabel?.isUserInteractionEnabled = true

userLabel?.addGestureRecognizer(tapAction)

以及动作方法,例如-

@objc func actionTapped(_ sender: UITapGestureRecognizer) {
        print("tapped")
    }

L
LeoGalante

Swift 版本如下所示:

func addGestureRecognizerLabel(){
    //Create a instance, in this case I used UITapGestureRecognizer,
    //in the docs you can see all kinds of gestures
    let gestureRecognizer = UITapGestureRecognizer()

    //Gesture configuration
    gestureRecognizer.numberOfTapsRequired = 1
    gestureRecognizer.numberOfTouchesRequired = 1
    /*Add the target (You can use UITapGestureRecognizer's init() for this)
    This method receives two arguments, a target(in this case is my ViewController) 
    and the callback, or function that you want to invoke when the user tap it view)*/
    gestureRecognizer.addTarget(self, action: "showDatePicker")

    //Add this gesture to your view, and "turn on" user interaction
    dateLabel.addGestureRecognizer(gestureRecognizer)
    dateLabel.userInteractionEnabled = true
}

//How you can see, this function is my "callback"
func showDatePicker(){
    //Your code here
    print("Hi, was clicked")
}

//To end just invoke to addGestureRecognizerLabel() when
//your viewDidLoad() method is called

override func viewDidLoad() {
    super.viewDidLoad()
    addGestureRecognizerLabel()
}

N
Nathan F.

我个人更喜欢为 UILabel 编写扩展的方法。这就是我使用的。

import UIKit

extension UILabel {
    /**
     * A map of actions, mapped as [ instanceIdentifier : action ].
     */
    private static var _tapHandlers = [String:(()->Void)]()

    /**
     * Retrieve the address for this UILabel as a String.
     */
    private func getAddressAsString() -> String {
        let addr = Unmanaged.passUnretained(self).toOpaque()
        return "\(addr)"
    }

    /**
     * Set the on tapped event for the label
     */
    func setOnTapped(_ handler: @escaping (()->Void)) {
        UILabel._tapHandlers[getAddressAsString()] = handler
        let gr = UITapGestureRecognizer(target: self, action: #selector(onTapped))
        gr.numberOfTapsRequired = 1
        self.addGestureRecognizer(gr)
        self.isUserInteractionEnabled = true
    }

    /**
     * Handle the tap event.
     */
    @objc private func onTapped() {
        UILabel._tapHandlers[self.getAddressAsString()]?()
    }
}

然后,您将在任何 UILabel 实例中像这样使用它:

myLabel.setOnTapped {
    // do something
}

我相信这可能会导致一些内存泄漏,但我还没有确定如何最好地解决它们。