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如何列出引用 SQL Server 中给定表的所有外键?

我需要删除 SQL Server 数据库中高度引用的表。如何获取删除表所需删除的所有外键约束的列表?

(SQL 回答比在管理工作室的 GUI 中单击 about 更可取。)

请参阅 How to Script Out all The Foreign Keys of a Table 获取帮助。 更新:链接不再可用,但相关 SQL 已作为 an answer 复制到相关问题。您还可以通过 GUI 查看依赖关系。

S
Seth Flowers

不知道为什么没有人建议,但我使用 sp_fkeys 来查询给定表的外键:

EXEC sp_fkeys 'TableName'

您还可以指定架构:

EXEC sp_fkeys @pktable_name = 'TableName', @pktable_owner = 'dbo'

在不指定架构的情况下,docs 声明以下内容:

如果未指定 pktable_owner,则应用底层 DBMS 的默认表可见性规则。在 SQL Server 中,如果当前用户拥有具有指定名称的表,则返回该表的列。如果未指定 pktable_owner 并且当前用户不拥有具有指定 pktable_name 的表,则该过程将查找数据库所有者拥有的具有指定 pktable_name 的表。如果存在,则返回该表的列。


由于某种原因,这对我在 sql 2008 数据库上不起作用。 sp_help 显示关系,但此命令不会。
@tbone:我遇到了同样的问题,这与未完全指定参数有关。给定由 O 拥有的表 T,在数据库 D 中,您需要执行 EXEC sp_fkeys \@pktable_name='T', \@pktable_owner='O', \@pktable_qualifier='D' 尝试查看 EXEC sp_tables \@ 的输出table_name ='T' 来确定参数值应该是什么。
@JustinRusso您可以通过创建一个表来解决这个问题,将结果存储到表中,然后选择特定的列。查看 this link 以获取示例:)。
在 SSMS 2014 中运行良好。谢谢。
它已经在上面的评论中得到了回答:但只是为了清楚起见 - EXEC sp_fkeys @pktable_name = N'Department' ,@pktable_owner = N'dbo'; msdn.microsoft.com/en-NZ/library/ms175090.aspx
G
Gustavo Rubio

这给了你:

FK 本身

FK所属的Schema

“参考表”或具有 FK 的表

“引用列”或引用表中指向 FK 的列

“引用表”或具有 FK 指向的键列的表

“引用列”或您的 FK 指向的键的列

下面的代码:

SELECT  obj.name AS FK_NAME,
    sch.name AS [schema_name],
    tab1.name AS [table],
    col1.name AS [column],
    tab2.name AS [referenced_table],
    col2.name AS [referenced_column]
FROM sys.foreign_key_columns fkc
INNER JOIN sys.objects obj
    ON obj.object_id = fkc.constraint_object_id
INNER JOIN sys.tables tab1
    ON tab1.object_id = fkc.parent_object_id
INNER JOIN sys.schemas sch
    ON tab1.schema_id = sch.schema_id
INNER JOIN sys.columns col1
    ON col1.column_id = parent_column_id AND col1.object_id = tab1.object_id
INNER JOIN sys.tables tab2
    ON tab2.object_id = fkc.referenced_object_id
INNER JOIN sys.columns col2
    ON col2.column_id = referenced_column_id AND col2.object_id = tab2.object_id

如果您想在之后过滤结果,这是我认为的最佳答案。
效果很好!如果您:a)在所有列名前加上“Fk”/“Key”,b)在所有列名后加上“Name”,c)删除下划线,d)添加 KeyTableSchemaName,e)添加默认值会更好order by:KeyTableSchemaName、KeyTableName、KeyColumnName、FkTableSchemaName、FkTableName、FkName 和 f) 将列顺序更改为:KeyTableSchemaName、KeyTableName、KeyColumnName、FkTableSchemaName、FkTableName、FkName、FkColumnName、a/b/c/d 以保持一致性/最常见最可能使用的最佳实践命名约定和 d/e(列出 Table 的 FK 依赖项)。
如此出色的答案和有用的查询。谢谢
如果您没有任何多列外键,则此查询效果最佳。
这应该是公认的答案,并非所有 FK 场景都包含在其他答案中
m
marc_s

我会使用 SQL Server Management Studio 中的数据库图表功能,但由于您排除了这一点 - 这在 SQL Server 2008 中对我有用(没有 2005)。

要获取引用表和列名的列表...

select 
    t.name as TableWithForeignKey, 
    fk.constraint_column_id as FK_PartNo, c.
    name as ForeignKeyColumn 
from 
    sys.foreign_key_columns as fk
inner join 
    sys.tables as t on fk.parent_object_id = t.object_id
inner join 
    sys.columns as c on fk.parent_object_id = c.object_id and fk.parent_column_id = c.column_id
where 
    fk.referenced_object_id = (select object_id 
                               from sys.tables 
                               where name = 'TableOthersForeignKeyInto')
order by 
    TableWithForeignKey, FK_PartNo

获取外键约束的名称

select distinct name from sys.objects where object_id in 
(   select fk.constraint_object_id from sys.foreign_key_columns as fk
    where fk.referenced_object_id = 
        (select object_id from sys.tables where name = 'TableOthersForeignKeyInto')
)

很好,尽管使用了 referenced_object_id 而不是 parent。 select distinct name from sys.objects where object_id in ( select fk.constraint_object_id from sys.foreign_key_columns as fk where fk.referenced_object_id = (select object_id from sys.tables where name = 'tablename') )
您可以通过将“object_name(constraint_object_id)”添加到第一个查询的选择来获取 FK 的名称。
您可以获得对象 id object_id('TableOthersForeignKeyInto')
T
Tushar Gupta - curioustushar

尝试这个 :

sp_help 'TableName'

了解您是否正在手动探索数据库的好帮手方法。此外,它适用于 Azure SQL Server 。
M
Mspaja

您还应该注意对其他对象的引用。

如果该表被其他表高度引用,则它可能也被其他对象(例如视图、存储过程、函数等)高度引用。

我真的会推荐 GUI 工具,例如 SSMS 中的“查看依赖项”对话框或像 ApexSQL Search 这样的免费工具,因为如果您只想使用 SQL 搜索其他对象中的依赖项,则可能容易出错。

如果 SQL 是唯一的选择,您可以尝试这样做。

select O.name as [Object_Name], C.text as [Object_Definition]
from sys.syscomments C
inner join sys.all_objects O ON C.id = O.object_id
where C.text like '%table_name%'

Ω
ΩmegaMan

最初的问题要求将所有外键的列表放入一个高度引用的表中,以便可以删除该表。

这个小查询返回将所有外键删除到特定表中所需的所有“删除外键”命令:

SELECT 
   'ALTER TABLE ['+sch.name+'].['+referencingTable.Name+'] DROP CONSTRAINT ['+foreignKey.name+']' '[DropCommand]'
FROM sys.foreign_key_columns fk
    JOIN sys.tables referencingTable ON fk.parent_object_id = referencingTable.object_id
    JOIN sys.schemas sch ON referencingTable.schema_id = sch.schema_id
    JOIN sys.objects foreignKey ON foreignKey.object_id = fk.constraint_object_id
    JOIN sys.tables referencedTable ON fk.referenced_object_id = referencedTable.object_id
WHERE referencedTable.name = 'MyTableName'

示例输出:

[DropCommand]
ALTER TABLE [dbo].[OtherTable1] DROP CONSTRAINT [FK_OtherTable1_MyTable]
ALTER TABLE [dbo].[OtherTable2] DROP CONSTRAINT [FK_OtherTable2_MyTable]

省略 WHERE 子句以获取当前数据库中所有外键的删除命令。


您能否为这应该做什么/应该如何工作添加一些解释?
不适用于 Oracle
M
Mike Gledhill

这是我将使用的 SQL 代码。

SELECT 
   f.name AS 'Name of Foreign Key',
   OBJECT_NAME(f.parent_object_id) AS 'Table name',
   COL_NAME(fc.parent_object_id,fc.parent_column_id) AS 'Fieldname',
   OBJECT_NAME(t.object_id) AS 'References Table name',
   COL_NAME(t.object_id,fc.referenced_column_id) AS 'References fieldname',

   'ALTER TABLE [' + OBJECT_NAME(f.parent_object_id) + ']  DROP CONSTRAINT [' + f.name + ']' AS 'Delete foreign key',

   'ALTER TABLE [' + OBJECT_NAME(f.parent_object_id) + ']  WITH NOCHECK ADD CONSTRAINT [' + 
        f.name + '] FOREIGN KEY([' + COL_NAME(fc.parent_object_id,fc.parent_column_id) + ']) REFERENCES ' + 
        '[' + OBJECT_NAME(t.object_id) + '] ([' +
        COL_NAME(t.object_id,fc.referenced_column_id) + '])' AS 'Create foreign key'
    -- , delete_referential_action_desc AS 'UsesCascadeDelete'
FROM sys.foreign_keys AS f,
     sys.foreign_key_columns AS fc,
     sys.tables t 
WHERE f.OBJECT_ID = fc.constraint_object_id
AND t.OBJECT_ID = fc.referenced_object_id
AND OBJECT_NAME(t.object_id) = 'Employees'      --  Just show the FKs which reference a particular table
ORDER BY 2

不是特别清楚SQL,我们来看一个例子。

因此,假设我想删除 Microsoft 钟爱的 Northwind 数据库中的 Employees 表,但 SQL Server 告诉我有一个或多个外键阻止我这样做。

上面的 SQL 命令将返回这些结果...

https://i.stack.imgur.com/qDHxZ.png

它显示有 3 个外键引用 Employees 表。换句话说,在这三个外键首先被删除之前,我不会被允许删除(删除)这个表。

在结果中,第一行是以下外键约束在结果中的显示方式。

ALTER TABLE [dbo].[Employees]  WITH NOCHECK 
ADD CONSTRAINT [FK_Employees_Employees] FOREIGN KEY([ReportsTo])
REFERENCES [dbo].[Employees] ([EmployeeID])

倒数第二列显示了我需要用来删除这些外键之一的 SQL 命令,例如:

ALTER TABLE [Employees] DROP CONSTRAINT [FK_Employees_Employees]

...并且右侧的列显示了创建它的 SQL...

ALTER TABLE [Employees] WITH NOCHECK 
ADD CONSTRAINT [FK_Employees_Employees] 
FOREIGN KEY([ReportsTo]) REFERENCES [Employees] ([EmployeeID])

使用所有这些命令,您就拥有了删除相关外键以允许您删除表,然后稍后重新创建它们所需的一切。

呸。希望这可以帮助。


如果您使用内部连接和 on 子句而不是交叉连接会更清楚。但这仍然很有帮助!
G
Garuda prasad K

最简单的一种是在 SQL 中使用 sys.foreign_keys_columns。在这里,该表包含所有外键的对象 ID,包括它们的引用列 ID 引用表 ID 以及引用列和表。由于 Id 保持不变,因此结果对于 Schema 和表中的进一步修改将是可靠的。

询问:

SELECT    
OBJECT_NAME(fkeys.constraint_object_id) foreign_key_name
,OBJECT_NAME(fkeys.parent_object_id) referencing_table_name
,COL_NAME(fkeys.parent_object_id, fkeys.parent_column_id) referencing_column_name
,OBJECT_SCHEMA_NAME(fkeys.parent_object_id) referencing_schema_name
,OBJECT_NAME (fkeys.referenced_object_id) referenced_table_name
,COL_NAME(fkeys.referenced_object_id, fkeys.referenced_column_id) 
referenced_column_name
,OBJECT_SCHEMA_NAME(fkeys.referenced_object_id) referenced_schema_name
FROM sys.foreign_key_columns AS fkeys

我们也可以使用 'where' 添加过滤器

WHERE OBJECT_NAME(fkeys.parent_object_id) = 'table_name' AND 
OBJECT_SCHEMA_NAME(fkeys.parent_object_id) = 'schema_name'

当您需要删除整个数据库结构/引用表集时,这非常有用。
s
sth
SELECT PKTABLE_QUALIFIER = CONVERT(SYSNAME,DB_NAME()),
       PKTABLE_OWNER = CONVERT(SYSNAME,SCHEMA_NAME(O1.SCHEMA_ID)),
       PKTABLE_NAME = CONVERT(SYSNAME,O1.NAME),
       PKCOLUMN_NAME = CONVERT(SYSNAME,C1.NAME),
       FKTABLE_QUALIFIER = CONVERT(SYSNAME,DB_NAME()),
       FKTABLE_OWNER = CONVERT(SYSNAME,SCHEMA_NAME(O2.SCHEMA_ID)),
       FKTABLE_NAME = CONVERT(SYSNAME,O2.NAME),
       FKCOLUMN_NAME = CONVERT(SYSNAME,C2.NAME),
       -- Force the column to be non-nullable (see SQL BU 325751)
       --KEY_SEQ             = isnull(convert(smallint,k.constraint_column_id), sysconv(smallint,0)),
       UPDATE_RULE = CONVERT(SMALLINT,CASE OBJECTPROPERTY(F.OBJECT_ID,'CnstIsUpdateCascade') 
                                        WHEN 1 THEN 0
                                        ELSE 1
                                      END),
       DELETE_RULE = CONVERT(SMALLINT,CASE OBJECTPROPERTY(F.OBJECT_ID,'CnstIsDeleteCascade') 
                                        WHEN 1 THEN 0
                                        ELSE 1
                                      END),
       FK_NAME = CONVERT(SYSNAME,OBJECT_NAME(F.OBJECT_ID)),
       PK_NAME = CONVERT(SYSNAME,I.NAME),
       DEFERRABILITY = CONVERT(SMALLINT,7)   -- SQL_NOT_DEFERRABLE
FROM   SYS.ALL_OBJECTS O1,
       SYS.ALL_OBJECTS O2,
       SYS.ALL_COLUMNS C1,
       SYS.ALL_COLUMNS C2,
       SYS.FOREIGN_KEYS F
       INNER JOIN SYS.FOREIGN_KEY_COLUMNS K
         ON (K.CONSTRAINT_OBJECT_ID = F.OBJECT_ID)
       INNER JOIN SYS.INDEXES I
         ON (F.REFERENCED_OBJECT_ID = I.OBJECT_ID
             AND F.KEY_INDEX_ID = I.INDEX_ID)
WHERE  O1.OBJECT_ID = F.REFERENCED_OBJECT_ID
       AND O2.OBJECT_ID = F.PARENT_OBJECT_ID
       AND C1.OBJECT_ID = F.REFERENCED_OBJECT_ID
       AND C2.OBJECT_ID = F.PARENT_OBJECT_ID
       AND C1.COLUMN_ID = K.REFERENCED_COLUMN_ID
       AND C2.COLUMN_ID = K.PARENT_COLUMN_ID

b
burning_LEGION
SELECT
  object_name(parent_object_id),
  object_name(referenced_object_id),
  name 
FROM sys.foreign_keys
WHERE parent_object_id = object_id('Table Name')

M
Matt

我正在使用此脚本来查找与外键相关的所有详细信息。我正在使用 INFORMATION.SCHEMA。下面是一个 SQL 脚本:

SELECT 
    ccu.table_name AS SourceTable
    ,ccu.constraint_name AS SourceConstraint
    ,ccu.column_name AS SourceColumn
    ,kcu.table_name AS TargetTable
    ,kcu.column_name AS TargetColumn
FROM INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE ccu
    INNER JOIN INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS rc
        ON ccu.CONSTRAINT_NAME = rc.CONSTRAINT_NAME 
    INNER JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE kcu 
        ON kcu.CONSTRAINT_NAME = rc.UNIQUE_CONSTRAINT_NAME  
ORDER BY ccu.table_name

我不知道应该如何使用它。请添加说明
M
Manish Kumar Gurjar

引用 SQL Server 中给定表的所有外键列表:

您可以通过以下查询获取引用表名和列名...

SELECT 
   OBJECT_NAME(f.parent_object_id) TableName,
   COL_NAME(fc.parent_object_id,fc.parent_column_id) ColName
FROM 
   sys.foreign_keys AS f
INNER JOIN 
   sys.foreign_key_columns AS fc 
      ON f.OBJECT_ID = fc.constraint_object_id
INNER JOIN 
   sys.tables t 
      ON t.OBJECT_ID = fc.referenced_object_id
WHERE 
   OBJECT_NAME (f.referenced_object_id) = 'TableName'

以下截图供您理解...

https://i.stack.imgur.com/OAx5u.png


i
irfandar

第一的

EXEC sp_fkeys 'Table', 'Schema'

然后使用 NimbleText 处理您的结果


M
Mark Varnas

上面有一些很好的答案。但我更喜欢一个问题的答案。这段代码取自 sys.sp_helpconstraint (sys proc)

如果有与 tbl 相关联的外键,Microsoft 就是这样查找的。

--setup variables. Just change 'Customer' to tbl you want
declare @objid int,
    @objname nvarchar(776)
select @objname = 'Customer'    
select @objid = object_id(@objname)

if exists (select * from sys.foreign_keys where referenced_object_id = @objid)
    select 'Table is referenced by foreign key' =
        db_name() + '.'
        + rtrim(schema_name(ObjectProperty(parent_object_id,'schemaid')))
        + '.' + object_name(parent_object_id)
        + ': ' + object_name(object_id)
    from sys.foreign_keys 
    where referenced_object_id = @objid 
    order by 1

答案将如下所示:test_db_name.dbo.Account: FK_Account_Customer


这实际上就像 4 个单独的查询语句......这在一个语句中实际上做了同样的事情:select db_name() + '.' + schema_name(ObjectProperty(parent_object_id,'schemaid')) + '.' + object_name(parent_object_id) + ': ' + object_name(object_id) AS "FK Reference" from sys.foreign_keys where referenced_object_id = object_id('Customer')
m
marc_s
 SELECT OBJECT_NAME(fk.parent_object_id) as ReferencingTable, 
        OBJECT_NAME(fk.constraint_object_id) as [FKContraint]
  FROM sys.foreign_key_columns as fk
 WHERE fk.referenced_object_id = OBJECT_ID('ReferencedTable', 'U')

这仅在是外键约束时才显示关系。我的数据库显然早于 FK 约束。一些表使用触发器来强制引用完整性,有时只有一个类似命名的列来指示关系(并且根本没有引用完整性)。

幸运的是,我们确实有一个一致的命名场景,所以我能够找到这样的引用表和视图:

SELECT OBJECT_NAME(object_id) from sys.columns where name like 'client_id'

我使用此选择作为生成脚本的基础,该脚本执行我需要在相关表上执行的操作。


V
Veer
SELECT
OBJECT_NAME(parent_object_id) 'Parent table',
c.NAME 'Parent column name',
OBJECT_NAME(referenced_object_id) 'Referenced table',
cref.NAME 'Referenced column name'
FROM 
sys.foreign_key_columns fkc 
INNER JOIN 
sys.columns c 
   ON fkc.parent_column_id = c.column_id 
      AND fkc.parent_object_id = c.object_id
INNER JOIN 
sys.columns cref 
   ON fkc.referenced_column_id = cref.column_id 
      AND fkc.referenced_object_id = cref.object_id  where   OBJECT_NAME(parent_object_id) = 'tablename'

如果要获取所有表的外键关系,请排除 where 子句,否则请编写您的表名而不是 tablename


M
Mashood Murtaza

@BankZ 的最佳答案

sp_help 'TableName'   

另外对于不同的模式

sp_help 'schemaName.TableName'   

谢谢。 sp_help 'TableName' 为我工作。
D
David

Mysql 服务器有 information_schema.REFERENTIAL_CONSTRAINTS 表仅供参考,您可以按表名或引用的表名对其进行过滤。


不适用于 Oracle
R
Raystorm

根据@Gishu 所做的工作,我能够在 SQL Server 2005 中生成和使用以下 SQL

SELECT t.name AS TableWithForeignKey, fk.constraint_column_id AS FK_PartNo, 
       c.name AS ForeignKeyColumn, o.name AS FK_Name 
  FROM sys.foreign_key_columns AS fk
       INNER JOIN sys.tables AS t ON fk.parent_object_id = t.object_id
       INNER JOIN sys.columns AS c ON fk.parent_object_id = c.object_id 
                                  AND fk.parent_column_id = c.column_id
       INNER JOIN sys.objects AS o ON fk.constraint_object_id = o.object_id
  WHERE fk.referenced_object_id = (SELECT object_id FROM sys.tables 
                                        WHERE name = 'TableOthersForeignKeyInto')
  ORDER BY TableWithForeignKey, FK_PartNo;

在 1 个查询中显示所有表、列和外键名称。


a
aked

确定数据库中所有表的主键和唯一键...

这应该列出所有约束,最后您可以放置过滤器

/* CAST IS DONE , SO THAT OUTPUT INTEXT FILE REMAINS WITH SCREEN LIMIT*/
WITH   ALL_KEYS_IN_TABLE (CONSTRAINT_NAME,CONSTRAINT_TYPE,PARENT_TABLE_NAME,PARENT_COL_NAME,PARENT_COL_NAME_DATA_TYPE,REFERENCE_TABLE_NAME,REFERENCE_COL_NAME) 
AS
(
SELECT  CONSTRAINT_NAME= CAST (PKnUKEY.name AS VARCHAR(30)) ,
        CONSTRAINT_TYPE=CAST (PKnUKEY.type_desc AS VARCHAR(30)) ,
        PARENT_TABLE_NAME=CAST (PKnUTable.name AS VARCHAR(30)) ,
        PARENT_COL_NAME=CAST ( PKnUKEYCol.name AS VARCHAR(30)) ,
        PARENT_COL_NAME_DATA_TYPE=  oParentColDtl.DATA_TYPE,        
        REFERENCE_TABLE_NAME='' ,
        REFERENCE_COL_NAME='' 

FROM sys.key_constraints as PKnUKEY
    INNER JOIN sys.tables as PKnUTable
            ON PKnUTable.object_id = PKnUKEY.parent_object_id
    INNER JOIN sys.index_columns as PKnUColIdx
            ON PKnUColIdx.object_id = PKnUTable.object_id
            AND PKnUColIdx.index_id = PKnUKEY.unique_index_id
    INNER JOIN sys.columns as PKnUKEYCol
            ON PKnUKEYCol.object_id = PKnUTable.object_id
            AND PKnUKEYCol.column_id = PKnUColIdx.column_id
     INNER JOIN INFORMATION_SCHEMA.COLUMNS oParentColDtl
            ON oParentColDtl.TABLE_NAME=PKnUTable.name
            AND oParentColDtl.COLUMN_NAME=PKnUKEYCol.name
UNION ALL
SELECT  CONSTRAINT_NAME= CAST (oConstraint.name AS VARCHAR(30)) ,
        CONSTRAINT_TYPE='FK',
        PARENT_TABLE_NAME=CAST (oParent.name AS VARCHAR(30)) ,
        PARENT_COL_NAME=CAST ( oParentCol.name AS VARCHAR(30)) ,
        PARENT_COL_NAME_DATA_TYPE= oParentColDtl.DATA_TYPE,     
        REFERENCE_TABLE_NAME=CAST ( oReference.name AS VARCHAR(30)) ,
        REFERENCE_COL_NAME=CAST (oReferenceCol.name AS VARCHAR(30)) 
FROM sys.foreign_key_columns FKC
    INNER JOIN sys.sysobjects oConstraint
            ON FKC.constraint_object_id=oConstraint.id 
    INNER JOIN sys.sysobjects oParent
            ON FKC.parent_object_id=oParent.id
    INNER JOIN sys.all_columns oParentCol
            ON FKC.parent_object_id=oParentCol.object_id /* ID of the object to which this column belongs.*/
            AND FKC.parent_column_id=oParentCol.column_id/* ID of the column. Is unique within the object.Column IDs might not be sequential.*/
    INNER JOIN sys.sysobjects oReference
            ON FKC.referenced_object_id=oReference.id
    INNER JOIN INFORMATION_SCHEMA.COLUMNS oParentColDtl
            ON oParentColDtl.TABLE_NAME=oParent.name
            AND oParentColDtl.COLUMN_NAME=oParentCol.name
    INNER JOIN sys.all_columns oReferenceCol
            ON FKC.referenced_object_id=oReferenceCol.object_id /* ID of the object to which this column belongs.*/
            AND FKC.referenced_column_id=oReferenceCol.column_id/* ID of the column. Is unique within the object.Column IDs might not be sequential.*/

)

select * from   ALL_KEYS_IN_TABLE
where   
    PARENT_TABLE_NAME  in ('YOUR_TABLE_NAME') 
    or REFERENCE_TABLE_NAME  in ('YOUR_TABLE_NAME')
ORDER BY PARENT_TABLE_NAME,CONSTRAINT_NAME;

供参考,请阅读 - http://blogs.msdn.com/b/sqltips/archive/2005/09/16/469136.aspx


对于所提出的问题,这包含太多信息。你能否包括一些解释(并删除额外的代码)来回答这个问题,好吗?您对两个不同的问题发布了这个确切的答案,每个问题只需要这个答案的一部分。
我编辑了答案 - 确定数据库中所有表的主键和唯一键......我认为这里的答案是合适的,因为问题适用于所有参考。
S
Steve Mangiameli

我在 2008 年及以后一直在使用它。它类似于列出的其他一些解决方案,但字段名称是正确大小写的以处理特定于大小写的 (LatBin) 排序规则。此外,您可以为其提供一个表名并仅检索该表的信息。

-->>SPECIFY THE DESIRED DB
USE ???
GO

/*********************************************************************************************

    LIST OUT ALL PRIMARY AND FOREIGN KEY CONSTRAINTS IN A DB OR FOR A SPECIFIED TABLE

*********************************************************************************************/
DECLARE @tblName VARCHAR(255) 

/*******************/

    SET @tblName = NULL-->NULL will return all PK/FK constraints for every table in the database

/*******************/

SELECT PKTABLE_QUALIFIER = CONVERT(SYSNAME,DB_NAME()), 
       PKTABLE_OWNER = CONVERT(SYSNAME,SCHEMA_NAME(O1.schema_id)), 
       PKTABLE_NAME = CONVERT(SYSNAME,O1.name), 
       PKCOLUMN_NAME = CONVERT(SYSNAME,C1.name), 
       FKTABLE_QUALIFIER = CONVERT(SYSNAME,DB_NAME()), 
       FKTABLE_OWNER = CONVERT(SYSNAME,SCHEMA_NAME(O2.schema_id)), 
       FKTABLE_NAME = CONVERT(SYSNAME,O2.name), 
       FKCOLUMN_NAME = CONVERT(SYSNAME,C2.name), 
       -- Force the column to be non-nullable (see SQL BU 325751) 
       KEY_SEQ             = isnull(convert(smallint,K.constraint_column_id),0), 
       UPDATE_RULE = CONVERT(SMALLINT,CASE OBJECTPROPERTY(F.object_id,'CnstIsUpdateCascade')  
                                        WHEN 1 THEN 0 
                                        ELSE 1 
                                      END), 
       DELETE_RULE = CONVERT(SMALLINT,CASE OBJECTPROPERTY(F.object_id,'CnstIsDeleteCascade')  
                                        WHEN 1 THEN 0 
                                        ELSE 1 
                                      END), 
       FK_NAME = CONVERT(SYSNAME,OBJECT_NAME(F.object_id)), 
       PK_NAME = CONVERT(SYSNAME,I.name), 
       DEFERRABILITY = CONVERT(SMALLINT,7)   -- SQL_NOT_DEFERRABLE 
FROM   sys.all_objects O1, 
       sys.all_objects O2, 
       sys.all_columns C1, 
       sys.all_columns C2, 
       sys.foreign_keys F 
       INNER JOIN sys.foreign_key_columns K 
         ON (K.constraint_object_id = F.object_id) 
       INNER JOIN sys.indexes I 
         ON (F.referenced_object_id = I.object_id 
             AND F.key_index_id = I.index_id) 
WHERE  O1.object_id = F.referenced_object_id 
       AND O2.object_id = F.parent_object_id 
       AND C1.object_id = F.referenced_object_id 
       AND C2.object_id = F.parent_object_id 
       AND C1.column_id = K.referenced_column_id
       AND C2.column_id = K.parent_column_id
       AND (   O1.name = @tblName 
            OR O2.name = @tblName
            OR @tblName IS null)
ORDER BY PKTABLE_NAME,FKTABLE_NAME

佚名

这将获取涉及所选表的任何外键。 *假定为 _FIRSTABLENAME_SECONDTABLENAME 格式。

 declare @tablename as varchar(MAX)
 SET @tablename = 'yourtablename'
 SELECT name
 FROM YOURDATABASE.sys.objects
 WHERE type_desc = 'FOREIGN_KEY_CONSTRAINT' and (name LIKE '%_' + @tablename + 'empdb_%' or name LIKE '%_' + @tablename )

这是更一般的形式:

 SELECT name
 FROM YOURDATABASE_PROD.sys.objects
 WHERE type_desc = 'FOREIGN_KEY_CONSTRAINT' and name LIKE '%' + @tablename + '%' and
 name NOT LIKE '[a-zA-Z0-9]' + @tablename + '%' and name NOT LIKE '%' + @tablename + '[a-zA-Z0-9]' 

A
ADM-IT

有如何计算所选 ID 的所有责任。只需更改@dbTableName 值、@dbRowId 值及其类型(如果 int,您需要删除第 82 行中的 '' (..SET @SQL = ..))。享受。

DECLARE @dbTableName varchar(max) = 'User'
DECLARE @dbRowId uniqueidentifier = '21d34ecd-c1fd-11e2-8545-002219a42e1c'

DECLARE @FK_ROWCOUNT int
DECLARE @SQL nvarchar(max)

DECLARE @PKTABLE_QUALIFIER sysname
DECLARE @PKTABLE_OWNER sysname
DECLARE @PKTABLE_NAME sysname
DECLARE @PKCOLUMN_NAME sysname
DECLARE @FKTABLE_QUALIFIER sysname
DECLARE @FKTABLE_OWNER sysname
DECLARE @FKTABLE_NAME sysname
DECLARE @FKCOLUMN_NAME sysname
DECLARE @UPDATE_RULE smallint
DECLARE @DELETE_RULE smallint
DECLARE @FK_NAME sysname
DECLARE @PK_NAME sysname
DECLARE @DEFERRABILITY sysname

IF OBJECT_ID('tempdb..#Temp1') IS NOT NULL
    DROP TABLE #Temp1;
CREATE TABLE #Temp1 ( 
    PKTABLE_QUALIFIER sysname,
    PKTABLE_OWNER sysname,
    PKTABLE_NAME sysname,
    PKCOLUMN_NAME sysname,
    FKTABLE_QUALIFIER sysname,
    FKTABLE_OWNER sysname,
    FKTABLE_NAME sysname,
    FKCOLUMN_NAME sysname,
    UPDATE_RULE smallint,
    DELETE_RULE smallint,
    FK_NAME sysname,
    PK_NAME sysname,
    DEFERRABILITY sysname,
    FK_ROWCOUNT int
    );
DECLARE FK_Counter_Cursor CURSOR FOR
    SELECT PKTABLE_QUALIFIER = CONVERT(SYSNAME,DB_NAME()),
       PKTABLE_OWNER = CONVERT(SYSNAME,SCHEMA_NAME(O1.SCHEMA_ID)),
       PKTABLE_NAME = CONVERT(SYSNAME,O1.NAME),
       PKCOLUMN_NAME = CONVERT(SYSNAME,C1.NAME),
       FKTABLE_QUALIFIER = CONVERT(SYSNAME,DB_NAME()),
       FKTABLE_OWNER = CONVERT(SYSNAME,SCHEMA_NAME(O2.SCHEMA_ID)),
       FKTABLE_NAME = CONVERT(SYSNAME,O2.NAME),
       FKCOLUMN_NAME = CONVERT(SYSNAME,C2.NAME),
       -- Force the column to be non-nullable (see SQL BU 325751)
       --KEY_SEQ             = isnull(convert(smallint,k.constraint_column_id), sysconv(smallint,0)),
       UPDATE_RULE = CONVERT(SMALLINT,CASE OBJECTPROPERTY(F.OBJECT_ID,'CnstIsUpdateCascade') 
                                        WHEN 1 THEN 0
                                        ELSE 1
                                      END),
       DELETE_RULE = CONVERT(SMALLINT,CASE OBJECTPROPERTY(F.OBJECT_ID,'CnstIsDeleteCascade') 
                                        WHEN 1 THEN 0
                                        ELSE 1
                                      END),
       FK_NAME = CONVERT(SYSNAME,OBJECT_NAME(F.OBJECT_ID)),
       PK_NAME = CONVERT(SYSNAME,I.NAME),
       DEFERRABILITY = CONVERT(SMALLINT,7)   -- SQL_NOT_DEFERRABLE
    FROM   SYS.ALL_OBJECTS O1,
           SYS.ALL_OBJECTS O2,
           SYS.ALL_COLUMNS C1,
           SYS.ALL_COLUMNS C2,
           SYS.FOREIGN_KEYS F
           INNER JOIN SYS.FOREIGN_KEY_COLUMNS K
             ON (K.CONSTRAINT_OBJECT_ID = F.OBJECT_ID)
           INNER JOIN SYS.INDEXES I
             ON (F.REFERENCED_OBJECT_ID = I.OBJECT_ID
                 AND F.KEY_INDEX_ID = I.INDEX_ID)
    WHERE  O1.OBJECT_ID = F.REFERENCED_OBJECT_ID
           AND O2.OBJECT_ID = F.PARENT_OBJECT_ID
           AND C1.OBJECT_ID = F.REFERENCED_OBJECT_ID
           AND C2.OBJECT_ID = F.PARENT_OBJECT_ID
           AND C1.COLUMN_ID = K.REFERENCED_COLUMN_ID
           AND C2.COLUMN_ID = K.PARENT_COLUMN_ID
           AND O1.NAME = @dbTableName
OPEN FK_Counter_Cursor;
FETCH NEXT FROM FK_Counter_Cursor INTO @PKTABLE_QUALIFIER, @PKTABLE_OWNER, @PKTABLE_NAME, @PKCOLUMN_NAME, @FKTABLE_QUALIFIER, @FKTABLE_OWNER, @FKTABLE_NAME, @FKCOLUMN_NAME, @UPDATE_RULE, @DELETE_RULE, @FK_NAME, @PK_NAME, @DEFERRABILITY;
WHILE @@FETCH_STATUS = 0
   BEGIN
        SET @SQL = 'SELECT @dbCountOut = COUNT(*) FROM [' + @FKTABLE_NAME + '] WHERE [' + @FKCOLUMN_NAME + '] = ''' + CAST(@dbRowId AS varchar(max)) + '''';
        EXECUTE sp_executesql @SQL, N'@dbCountOut int OUTPUT', @dbCountOut = @FK_ROWCOUNT OUTPUT;
        INSERT INTO #Temp1 (PKTABLE_QUALIFIER, PKTABLE_OWNER, PKTABLE_NAME, PKCOLUMN_NAME, FKTABLE_QUALIFIER, FKTABLE_OWNER, FKTABLE_NAME, FKCOLUMN_NAME, UPDATE_RULE, DELETE_RULE, FK_NAME, PK_NAME, DEFERRABILITY, FK_ROWCOUNT) VALUES (@FKTABLE_QUALIFIER, @PKTABLE_OWNER, @PKTABLE_NAME, @PKCOLUMN_NAME, @FKTABLE_QUALIFIER, @FKTABLE_OWNER, @FKTABLE_NAME, @FKCOLUMN_NAME, @UPDATE_RULE, @DELETE_RULE, @FK_NAME, @PK_NAME, @DEFERRABILITY, @FK_ROWCOUNT)
      FETCH NEXT FROM FK_Counter_Cursor INTO @PKTABLE_QUALIFIER, @PKTABLE_OWNER, @PKTABLE_NAME, @PKCOLUMN_NAME, @FKTABLE_QUALIFIER, @FKTABLE_OWNER, @FKTABLE_NAME, @FKCOLUMN_NAME, @UPDATE_RULE, @DELETE_RULE, @FK_NAME, @PK_NAME, @DEFERRABILITY;
   END;
CLOSE FK_Counter_Cursor;
DEALLOCATE FK_Counter_Cursor;
GO
SELECT * FROM #Temp1
GO

J
Jorge Santos Neill

以下解决方案对我有用:

--Eliminar las llaves foraneas
declare @query varchar(8000)
declare cursorRecorrerTabla cursor for

SELECT  'ALTER TABLE [PoaComFinH].['+sch.name+'].['+referencingTable.Name+'] DROP CONSTRAINT ['+foreignKey.name+']' 'query'
FROM PoaComFinH.sys.foreign_key_columns fk
JOIN PoaComFinH.sys.tables referencingTable ON fk.parent_object_id = referencingTable.object_id
JOIN PoaComFinH.sys.schemas sch ON referencingTable.schema_id = sch.schema_id
JOIN PoaComFinH.sys.objects foreignKey ON foreignKey.object_id = fk.constraint_object_id
JOIN PoaComFinH.sys.tables referencedTable ON fk.referenced_object_id = referencedTable.object_id


--3ro. abrir el cursor.
open cursorRecorrerTabla
fetch next from cursorRecorrerTabla
into @query
while @@fetch_status = 0
begin
--inicio cuerpo del cursor
    print @query
    exec(@query)
--fin cuerpo del cursor
fetch next from cursorRecorrerTabla
into @query
end
--cerrar cursor
close cursorRecorrerTabla
deallocate cursorRecorrerTabla

D
Dilip Oganiya

您可以通过以下查询找到:

 SELECT OBJECT_NAME (FK.referenced_object_id) 'Referenced Table', 
      OBJECT_NAME(FK.parent_object_id) 'Referring Table', FK.name 'Foreign Key', 
      COL_NAME(FK.referenced_object_id, FKC.referenced_column_id) 'Referenced Column',
      COL_NAME(FK.parent_object_id,FKC.parent_column_id) 'Referring Column'
     FROM sys.foreign_keys AS FK
             INNER JOIN sys.foreign_key_columns AS FKC 
                 ON FKC.constraint_object_id = FK.OBJECT_ID
     WHERE OBJECT_NAME (FK.referenced_object_id) = 'YourTableName'
     AND COL_NAME(FK.referenced_object_id, FKC.referenced_column_id) = 'YourColumnName'
     order by  OBJECT_NAME(FK.parent_object_id)

H
Hossein Narimani Rad

也试试。

EXEC sp_fkeys 'tableName', 'schemaName'

使用 sp_fkeys,您不仅可以通过 pk 表名和架构过滤结果,还可以使用 fk 表名和架构过滤结果。 link


S
Simas Joneliunas
with tab_list as (
    select t.name AS Table_Name, t.object_id, s.name AS Table_Schema  from sys.tables t, sys.schemas s 
     where t.schema_id = s.schema_id
       and s.name = 'your schema') 
select IIF(col.column_id = 1, tab.TABLE_SCHEMA + '.' + tab.TABLE_NAME, NULL) Table_Name,
       col.Name AS Column_Name, IIF(col.IS_NULLABLE= 0, 'NOT NULL', '') Nullable, st.name Type,
       CASE WHEN st.name = 'decimal' THEN CONVERT(NVARCHAR(4000), col.Precision) + ',' + CONVERT(NVARCHAR(4000), col.Scale) 
            WHEN col.max_length = -1 THEN 'max'
            WHEN st.name in ('int', 'bit', 'bigint', 'datetime2') THEN NULL
       ELSE CONVERT(NVARCHAR(4000), col.max_length / 2)
       END
       AS Length,
       ss.name + '.' + stab.name Referenced_Table, scol.name Referenced_Column 
from sys.COLUMNS col  
    INNER JOIN tab_list tab ON col.object_id = tab.object_id
    INNER JOIN sys.types st ON col.system_type_id = st.system_type_id AND col.user_type_id = st.user_type_id 
    LEFT JOIN [sys].[foreign_key_columns] sfkc ON col.object_id = sfkc.parent_object_id AND col.column_id = sfkc.parent_column_id
    LEFT JOIN sys.tables stab ON sfkc.referenced_object_id = stab.object_id
    LEFT JOIN sys.columns scol ON sfkc.referenced_object_id = scol.object_id AND sfkc.referenced_column_id = scol.column_id 
    LEFT JOIN sys.schemas ss ON ss.schema_id = stab.schema_id

这是一个非常大且多汁的 SQL。你能解释一下它是如何工作的,以便我们能够从中学习吗?
感谢@Simas JoneLiunas 编辑我凌乱的文本。我正在进行迁移项目,需要列出所有列的信息,包括关系(FK)。该脚本将向您显示有关架构级别的信息。为您的特定目的在 tab_list 视图中进行更多修改。如果我早点知道对象 id 的内置函数会更简单:(。
D
Dale K

甲骨文 SQL

select *
from
    all_constraints
where
    r_constraint_name in
    (select       constraint_name
    from
       all_constraints
    where
       table_name='PUT_THE_TABLE_NAME_HERE');

all_constraints 是 Oracle DB 中的固有表名。


C
CervEd

此答案构建 on,但格式类似于 sp_fkeys,适用于多个列并列出它们的顺序。

SELECT fk_obj.name    AS FK_NAME,
       pk_schema.name AS PKTABLE_OWNER,
       pk_table.name  AS PKTABLE_NAME,
       pk_column.name AS PKCOLUMN_NAME,
       fk_schema.name AS FKTABLE_OWNER,
       fk_table.name  AS FKTABLE_NAME,
       fk_column.name AS FKCOLUMN_NAME,
       ROW_NUMBER() over (
           PARTITION BY fk_obj.name, fk_schema.name
           ORDER BY fkc.constraint_column_id
           )          AS KEY_SEQ
FROM sys.foreign_key_columns fkc
         INNER JOIN sys.objects fk_obj
                    ON fk_obj.object_id = fkc.constraint_object_id
         INNER JOIN sys.tables fk_table
                    ON fk_table.object_id = fkc.parent_object_id
         INNER JOIN sys.schemas fk_schema
                    ON fk_table.schema_id = fk_schema.schema_id
         INNER JOIN sys.columns fk_column
                    ON fk_column.column_id = parent_column_id
                        AND fk_column.object_id = fk_table.object_id
         INNER JOIN sys.tables pk_table
                    ON pk_table.object_id = fkc.referenced_object_id
         INNER JOIN sys.schemas pk_schema
                    ON pk_table.schema_id = pk_schema.schema_id
         INNER JOIN sys.columns pk_column
                    ON pk_column.column_id = fkc.referenced_column_id
                        AND pk_column.object_id = pk_table.object_id;