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Check folder size in Bash

I'm trying to write a script that will calculate a directory size and if the size is less than 10GB, and greater then 2GB do some action. Where do I need to mention my folder name?

# 10GB
SIZE="1074747474"

# check the current size
CHECK="`du /data/sflow_log/`"
if [ "$CHECK" -gt "$SIZE" ]; then
  echo "DONE"
fi
And if you want to sort it: serverfault.com/questions/62411/…
Since this is a popular question - If any beginner is encountering the answers on this question and wants to learn more about what the heck du is and how everyone knows all these commands: You can type man du in your terminal to lookup the du command in the manual. This will display an output which you can view, and will summarize all the flags like -h, -c, -s, -b, -B, --apparent-size, etc. that answers are you suggesting you use. Then, you can decide for yourself how you best want to use du for your specific use case.

A
ADTC

You can do:

du -hs your_directory

which will give you a brief output of the size of your target directory. Using a wildcard like * can select multiple directories.

If you want a full listing of sizes for all files and sub-directories inside your target, you can do:

du -h your_directory

Tips:

Add the argument -c to see a Total line at the end. Example: du -hcs or du -hc.

Remove the argument -h to see the sizes in exact KiB instead of human-readable MiB or GiB formats. Example: du -s or du -cs.


You don't want human-readable numbers when you're trying to get a value for a script.
With no directory path specified it will default to the current working directory. so du -hs == du -hs ..
Also check out: du | sort -n it will sort the directories by its size
du -hcs dir_name/* includes the subfolders
du -h | tail -1 ?
B
Bruce Sun

if you just want to see the folder size and not the sub-folders, you can use:

du -hs /path/to/directory

Update:

You should know that du shows the used disk space; and not the file size.

You can use --apparent-size if u want to see sum of actual file sizes.

--apparent-size
      print  apparent  sizes,  rather  than  disk  usage; although the apparent size is usually smaller, it may be larger due to holes in ('sparse')
      files, internal fragmentation, indirect blocks, and the like

And of course theres no need for -h (Human readable) option inside a script.

Instead You can use -b for easier comparison inside script.

But You should Note that -b applies --apparent-size by itself. And it might not be what you need.

-b, --bytes
      equivalent to '--apparent-size --block-size=1'

so I think, you should use --block-size or -B

#!/bin/bash
SIZE=$(du -B 1 /path/to/directory | cut -f 1 -d "   ")    
# 2GB = 2147483648 bytes
# 10GB = 10737418240 bytes
if [[ $SIZE -gt 2147483648 && $SIZE -lt 10737418240 ]]; then
    echo 'Condition returned True'
fi

I know it's been a couple of years, but would you be so kind as to explain a little bit what is the purpose of regex and BASH_REMATCH in the conditionals? (or to provide some links as to the usage of those variables/commands/formats) I would have expected the code to just get the size of the file in a variable and compare that with 10 gb directly, what are those other things doing?
@Nordico yup. there was no need for regex and BASH_REMATCH so I updated the answer.
p
paddy

Use a summary (-s) and bytes (-b). You can cut the first field of the summary with cut. Putting it all together:

CHECK=$(du -sb /data/sflow_log | cut -f1)

I am new to shell scripting. Output of du command included directory name. I was unable to get only number part. "cut" in your answer solved the mystery!
s
siliconrockstar

To just get the size of the directory, nothing more:

du --max-depth=0 ./directory

output looks like

5234232       ./directory

--max-depth is very useful for usefully controlling the output! for example, to get a good notion of what's going on inside a directory: du -h --max-depth=1
D
Deepak Mahakale

To check the size of all of the directories within a directory, you can use:

du -h --max-depth=1

S
Sebastian

if you just want to see the aggregate size of the folder and probably in MB or GB format, please try the below script

$du -s --block-size=M /path/to/your/directory/

on os x, the flags are -g for 1-Gbyte and -m for 1-Mbyte counts. via man du
G
Gutz-Pilz
# 10GB
SIZE="10"


# check the current size
CHECK="`du -hs /media/662499e1-b699-19ad-57b3-acb127aa5a2b/Aufnahmen`"
CHECK=${CHECK%G*}
echo "Current Foldersize: $CHECK GB"

if (( $(echo "$CHECK > $SIZE" |bc -l) )); then
        echo "Folder is bigger than $SIZE GB"
else
        echo "Folder is smaller than $SIZE GB"
fi

two variables with the same name? (CHECK)
Becarefull : If your folder is lower than 1GB (ex 350 KB), then you ll have 350 GB as value
V
Vignesh Raja

If it helps, You can also create an alias in your .bashrc or .bash_profile.

function dsize()
{
    dir=$(pwd)
    if [ "$1" != "" ]; then
            dir=$1
    fi
    echo $(du -hs $dir)
}

This prints the size of the current directory or the directory you have passed as an argument.


This is a great answer
You should quote $dir when passing it to du to prevent word splitting for the value of $dir. Wrapping the call to du into echo $(…) seems redundant. Instead of calling pwd you can use the builtin Bash variable ${PWD}. For checking if a variable is set, I suggest [ -v varname ].