ChatGPT解决这个技术问题 Extra ChatGPT

如何通过 has_many 关联在 FactoryBot 中设置工厂

有人可以告诉我,如果我只是以错误的方式进行设置吗?

我有以下具有 has_many.through 关联的模型:

class Listing < ActiveRecord::Base
  attr_accessible ... 

  has_many :listing_features
  has_many :features, :through => :listing_features

  validates_presence_of ...
  ...  
end


class Feature < ActiveRecord::Base
  attr_accessible ...

  validates_presence_of ...
  validates_uniqueness_of ...

  has_many :listing_features
  has_many :listings, :through => :listing_features
end


class ListingFeature < ActiveRecord::Base
  attr_accessible :feature_id, :listing_id

  belongs_to :feature  
  belongs_to :listing
end

我正在使用 Rails 3.1.rc4、FactoryGirl 2.0.2、factory_girl_rails 1.1.0 和 rspec。这是我对 :listing 工厂的基本 rspec rspec 健全性检查:

it "creates a valid listing from factory" do
  Factory(:listing).should be_valid
end

这里是工厂(:listing)

FactoryGirl.define do
  factory :listing do
    headline    'headline'
    home_desc   'this is the home description'
    association :user, :factory => :user
    association :layout, :factory => :layout
    association :features, :factory => :feature
  end
end

:listing_feature:feature 工厂的设置类似。
如果 association :features 行被注释掉,那么我的所有测试都通过了。

association :features, :factory => :feature

错误消息是 undefined method 'each' for #<Feature>,我认为这对我来说很有意义,因为 listing.features 返回一个数组。所以我把它改成了

association :features, [:factory => :feature]

我现在得到的错误是ArgumentError: Not registered: features以这种方式生成工厂对象是不明智的,还是我错过了什么?非常感谢您的任何和所有输入!


J
JellicleCat

或者,您可以使用块并跳过 association 关键字。这样就可以在不保存到数据库的情况下构建对象(否则,has_many 关联会将您的记录保存到数据库中,即使您使用 build 函数而不是 create 也是如此)。

FactoryGirl.define do
  factory :listing_with_features, :parent => :listing do |listing|
    features { build_list :feature, 3 }
  end
end

这是猫的喵喵叫。 buildcreate 的能力使它成为最通用的模式。然后在测试 accepts_nested_attributes_for 的控制器操作时使用此自定义 FG 构建策略 gist.github.com/Bartuz/74ee5834a36803d712b7post nested_attributes_for
比公认的答案 IMO 更具可读性和通用性
从 FactoryBot 5 开始,association 关键字对父级和子级使用相同的构建策略。因此,它可以构建不保存到数据库的对象。
J
Jay Killeen

创建这些类型的关联需要使用 FactoryGirl 的回调。

可以在此处找到一组完美的示例。

https://thoughtbot.com/blog/aint-no-calla-back-girl

把它带回家你的例子。

Factory.define :listing_with_features, :parent => :listing do |listing|
  listing.after_create { |l| Factory(:feature, :listing => l)  }
  #or some for loop to generate X features
end

您最终是否使用了关联:特征,[:工厂=>:特征]?
e
ehoffmann

您可以使用 trait

FactoryGirl.define do
  factory :listing do
    ...

    trait :with_features do
      features { build_list :feature, 3 }
    end
  end
end

使用 callback,如果您需要创建数据库:

...

trait :with_features do
  after(:create) do |listing|
    create_list(:feature, 3, listing: listing)
  end
end

在您的规格中使用如下:

let(:listing) { create(:listing, :with_features) }

这将消除您工厂中的重复,并且更加可重用。

https://robots.thoughtbot.com/remove-duplication-with-factorygirls-traits


D
Dave Sag

我尝试了几种不同的方法,这是对我来说最可靠的方法(适用于您的情况)

FactoryGirl.define do
  factory :user do
    # some details
  end

  factory :layout do
    # some details
  end

  factory :feature do
    # some details
  end

  factory :listing do
    headline    'headline'
    home_desc   'this is the home description'
    association :user, factory: :user
    association :layout, factory: :layout
    after(:create) do |liztng|
      FactoryGirl.create_list(:feature, 1, listing: liztng)
    end
  end
end

t
thisismydesign

从 FactoryBot v5 开始,关联保留了构建策略。关联是解决此问题的最佳方式,docs have good examples for it

FactoryBot.define do
  factory :post do
    title { "Through the Looking Glass" }
    user
  end

  factory :user do
    name { "Taylor Kim" }

    factory :user_with_posts do
      posts { [association(:post)] }
    end
  end
end

或控制计数:

    transient do
      posts_count { 5 }
    end

    posts do
      Array.new(posts_count) { association(:post) }
    end

r
rii

这是我的设置方式:

# Model 1 PreferenceSet
class PreferenceSet < ActiveRecord::Base
  belongs_to :user
  has_many :preferences, dependent: :destroy
end

#Model 2 Preference

class Preference < ActiveRecord::Base    
  belongs_to :preference_set
end



# factories/preference_set.rb

FactoryGirl.define do
  factory :preference_set do
    user factory: :user
    filter_name "market, filter_structure"

    factory :preference_set_with_preferences do
      after(:create) do |preference|
        create(:preference, preference_set: preference)
        create(:filter_structure_preference, preference_set: preference)
      end
    end
  end

end

# factories/preference.rb

FactoryGirl.define do
  factory :preference do |p|
    filter_name "market"
    filter_value "12"
  end

  factory :filter_structure_preference, parent: :preference do
    filter_name "structure"
    filter_value "7"
  end
end

然后在您的测试中,您可以执行以下操作:

@preference_set = FactoryGirl.create(:preference_set_with_preferences)

希望有帮助。


s
sequielo

与 @thisismydesign 类似,但它在我的末端创建了一个额外的 post(FactoryBot v6.2)。

为了避免这种情况,我添加了关键字 instance,如下所示:

FactoryBot.define do
  factory :post do
    title { "Through the Looking Glass" }
    user
  end

  factory :user do
    name { "Taylor Kim" }

    factory :user_with_posts do
      posts { [association(:post, user: instance)] }
    end
  end
end

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