我目前正在努力使用反应路由器 v4 嵌套路由。
最接近的示例是 React-Router v4 Documentation 中的路由配置。
我想将我的应用分成 2 个不同的部分。
一个前端和一个管理区域。
我在想这样的事情:
<Match pattern="/" component={Frontpage}>
<Match pattern="/home" component={HomePage} />
<Match pattern="/about" component={AboutPage} />
</Match>
<Match pattern="/admin" component={Backend}>
<Match pattern="/home" component={Dashboard} />
<Match pattern="/users" component={UserPage} />
</Match>
<Miss component={NotFoundPage} />
前端的布局和样式与管理区域不同。所以在首页的路线首页,关于等应该是子路线。
/home
应呈现在 Frontpage 组件中,而 /admin/home
应呈现在 Backend 组件中。
我尝试了其他一些变体,但总是以没有点击 /home
或 /admin/home
结束。
最终解决方案:
这是我现在使用的最终解决方案。这个例子还有一个像传统 404 页面一样的全局错误组件。
import React, { Component } from 'react';
import { Switch, Route, Redirect, Link } from 'react-router-dom';
const Home = () => <div><h1>Home</h1></div>;
const User = () => <div><h1>User</h1></div>;
const Error = () => <div><h1>Error</h1></div>
const Frontend = props => {
console.log('Frontend');
return (
<div>
<h2>Frontend</h2>
<p><Link to="/">Root</Link></p>
<p><Link to="/user">User</Link></p>
<p><Link to="/admin">Backend</Link></p>
<p><Link to="/the-route-is-swiggity-swoute">Swiggity swooty</Link></p>
<Switch>
<Route exact path='/' component={Home}/>
<Route path='/user' component={User}/>
<Redirect to={{
state: { error: true }
}} />
</Switch>
<footer>Bottom</footer>
</div>
);
}
const Backend = props => {
console.log('Backend');
return (
<div>
<h2>Backend</h2>
<p><Link to="/admin">Root</Link></p>
<p><Link to="/admin/user">User</Link></p>
<p><Link to="/">Frontend</Link></p>
<p><Link to="/admin/the-route-is-swiggity-swoute">Swiggity swooty</Link></p>
<Switch>
<Route exact path='/admin' component={Home}/>
<Route path='/admin/user' component={User}/>
<Redirect to={{
state: { error: true }
}} />
</Switch>
<footer>Bottom</footer>
</div>
);
}
class GlobalErrorSwitch extends Component {
previousLocation = this.props.location
componentWillUpdate(nextProps) {
const { location } = this.props;
if (nextProps.history.action !== 'POP'
&& (!location.state || !location.state.error)) {
this.previousLocation = this.props.location
};
}
render() {
const { location } = this.props;
const isError = !!(
location.state &&
location.state.error &&
this.previousLocation !== location // not initial render
)
return (
<div>
{
isError
? <Route component={Error} />
: <Switch location={isError ? this.previousLocation : location}>
<Route path="/admin" component={Backend} />
<Route path="/" component={Frontend} />
</Switch>}
</div>
)
}
}
class App extends Component {
render() {
return <Route component={GlobalErrorSwitch} />
}
}
export default App;
previousLocation
逻辑。
在 react-router-v4 中,您不嵌套 <Routes />
。相反,您将它们放在另一个 <Component />
中。
例如
<Route path='/topics' component={Topics}>
<Route path='/topics/:topicId' component={Topic} />
</Route>
应该成为
<Route path='/topics' component={Topics} />
和
const Topics = ({ match }) => (
<div>
<h2>Topics</h2>
<Link to={`${match.url}/exampleTopicId`}>
Example topic
</Link>
<Route path={`${match.path}/:topicId`} component={Topic}/>
</div>
)
这是直接来自 react-router documentation 的 basic example。
反应路由器 v6
2022 年更新 - v6 包含 Just Work™ 的嵌套 Route
组件。
这个问题是关于 v4/v5 的,但现在最好的答案是尽可能使用 v6!
请参阅 this blog post 中的示例代码。但是,如果您还不能升级...
反应路由器 v4 & v5
确实,为了嵌套 Route,您需要将它们放置在 Route 的子组件中。
但是,如果您喜欢更内联的语法,而不是将您的 Route 拆分为多个组件,您可以为要嵌套在其下的 Route 的 render
属性提供一个功能组件。
<BrowserRouter>
<Route path="/" component={Frontpage} exact />
<Route path="/home" component={HomePage} />
<Route path="/about" component={AboutPage} />
<Route
path="/admin"
render={({ match: { url } }) => (
<>
<Route path={`${url}/`} component={Backend} exact />
<Route path={`${url}/home`} component={Dashboard} />
<Route path={`${url}/users`} component={UserPage} />
</>
)}
/>
</BrowserRouter>
如果您对为什么应该使用 render
属性而不是 component
属性感兴趣,那是因为它会阻止内联功能组件在每次渲染时重新安装。 See the documentation 了解更多详情。
请注意,该示例将嵌套路由包装在 Fragment 中。在 React 16 之前,您可以改用容器 <div>
。
match.path
,而不是 match.url
。前者通常用在 Route path
属性中;后者在您推送新路线时(例如 Link to
道具)
只是想提一下,自从发布/回答了这个问题以来,react-router v4 发生了根本性的变化。
不再有 <Match>
组件! <Switch>
是为了确保只呈现第一个匹配项。 <Redirect>
好 .. 重定向到另一条路线。使用或省略 exact
来输入或排除部分匹配。
请参阅文档。他们都是伟大的。 https://reacttraining.com/react-router/
这是一个例子,我希望可以用来回答你的问题。
<Router>
<div>
<Redirect exact from='/' to='/front'/>
<Route path="/" render={() => {
return (
<div>
<h2>Home menu</h2>
<Link to="/front">front</Link>
<Link to="/back">back</Link>
</div>
);
}} />
<Route path="/front" render={() => {
return (
<div>
<h2>front menu</h2>
<Link to="/front/help">help</Link>
<Link to="/front/about">about</Link>
</div>
);
}} />
<Route exact path="/front/help" render={() => {
return <h2>front help</h2>;
}} />
<Route exact path="/front/about" render={() => {
return <h2>front about</h2>;
}} />
<Route path="/back" render={() => {
return (
<div>
<h2>back menu</h2>
<Link to="/back/help">help</Link>
<Link to="/back/about">about</Link>
</div>
);
}} />
<Route exact path="/back/help" render={() => {
return <h2>back help</h2>;
}} />
<Route exact path="/back/about" render={() => {
return <h2>back about</h2>;
}} />
</div>
</Router>
希望它有帮助,让我知道。如果这个例子不能很好地回答你的问题,请告诉我,我会看看我是否可以修改它。
Redirect
上没有 exact
reacttraining.com/react-router/web/api/Redirect 这将比我正在做的 <Route exact path="/" render={() => <Redirect to="/path" />} />
干净得多。至少它不会让我使用 TypeScript。
我通过用 Switch
包装成功地定义了嵌套路由,并在根路由之前定义了嵌套路由。
<BrowserRouter>
<Switch>
<Route path="/staffs/:id/edit" component={StaffEdit} />
<Route path="/staffs/:id" component={StaffShow} />
<Route path="/staffs" component={StaffIndex} />
</Switch>
</BrowserRouter>
参考:https://github.com/ReactTraining/react-router/blob/master/packages/react-router/docs/api/Switch.md
使用钩子
钩子的最新更新是使用 useRouteMatch
。
主路由组件
export default function NestingExample() {
return (
<Router>
<Switch>
<Route path="/topics">
<Topics />
</Route>
</Switch>
</Router>
);
}
子组件
function Topics() {
// The `path` lets us build <Route> paths
// while the `url` lets us build relative links.
let { path, url } = useRouteMatch();
return (
<div>
<h2>Topics</h2>
<h5>
<Link to={`${url}/otherpath`}>/topics/otherpath/</Link>
</h5>
<ul>
<li>
<Link to={`${url}/topic1`}>/topics/topic1/</Link>
</li>
<li>
<Link to={`${url}/topic2`}>/topics/topic2</Link>
</li>
</ul>
// You can then use nested routing inside the child itself
<Switch>
<Route exact path={path}>
<h3>Please select a topic.</h3>
</Route>
<Route path={`${path}/:topicId`}>
<Topic />
</Route>
<Route path={`${path}/otherpath`>
<OtherPath/>
</Route>
</Switch>
</div>
);
}
像这样的东西。
从“反应”导入反应;从 'react-router-dom' 导入 { BrowserRouter as Router, Route, NavLink, Switch, Link };导入'../assets/styles/App.css'; const Home = () => HOME
关于
Help
root
Admin about
管理员帮助
React Router v6 或版本 6 的完整答案,以备不时之需。
import Dashboard from "./dashboard/Dashboard";
import DashboardDefaultContent from "./dashboard/dashboard-default-content";
import { Route, Routes } from "react-router";
import { useRoutes } from "react-router-dom";
/*Routes is used to be Switch*/
const Router = () => {
return (
<Routes>
<Route path="/" element={<LandingPage />} />
<Route path="games" element={<Games />} />
<Route path="game-details/:id" element={<GameDetails />} />
<Route path="dashboard" element={<Dashboard />}>
<Route path="/" element={<DashboardDefaultContent />} />
<Route path="inbox" element={<Inbox />} />
<Route path="settings-and-privacy" element={<SettingsAndPrivacy />} />
<Route path="*" element={<NotFound />} />
</Route>
<Route path="*" element={<NotFound />} />
</Routes>
);
};
export default Router;
import DashboardSidebarNavigation from "./dashboard-sidebar-navigation";
import { Grid } from "@material-ui/core";
import { Outlet } from "react-router";
const Dashboard = () => {
return (
<Grid
container
direction="row"
justify="flex-start"
alignItems="flex-start"
>
<DashboardSidebarNavigation />
<Outlet />
</Grid>
);
};
export default Dashboard;
Github 仓库在这里。 https://github.com/webmasterdevlin/react-router-6-demo
反应路由器 v6
允许使用嵌套路由(如在 v3 中)和单独的拆分路由(v4、v5)。
嵌套路由
为中小型应用保留所有路线 in one place:
<Routes>
<Route path="/" element={<Home />} >
<Route path="user" element={<User />} />
<Route path="dash" element={<Dashboard />} />
</Route>
</Routes>
const App = () => { return (
URL 路径: {location.pathname}
user dashboard
备选方案:通过 useRoutes
将您的路线定义为纯 JavaScript 对象。
单独的路线
您可以使用 separates routes 来满足代码拆分等大型应用的要求:
// inside App.jsx:
<Routes>
<Route path="/*" element={<Home />} />
</Routes>
// inside Home.jsx:
<Routes>
<Route path="user" element={<User />} />
<Route path="dash" element={<Dashboard />} />
</Routes>
const App = () => { return (
URL 路径:{location.pathname}
user< /Link> dashboard
Routes
和 Route
是旧方法,我喜欢这种方法,我在 AngularJS 中也使用了相同的方法,谢谢
您可以尝试类似 Routes.js
import React, { Component } from 'react'
import { BrowserRouter as Router, Route } from 'react-router-dom';
import FrontPage from './FrontPage';
import Dashboard from './Dashboard';
import AboutPage from './AboutPage';
import Backend from './Backend';
import Homepage from './Homepage';
import UserPage from './UserPage';
class Routes extends Component {
render() {
return (
<div>
<Route exact path="/" component={FrontPage} />
<Route exact path="/home" component={Homepage} />
<Route exact path="/about" component={AboutPage} />
<Route exact path="/admin" component={Backend} />
<Route exact path="/admin/home" component={Dashboard} />
<Route exact path="/users" component={UserPage} />
</div>
)
}
}
export default Routes
应用程序.js
import React, { Component } from 'react';
import logo from './logo.svg';
import './App.css';
import { BrowserRouter as Router, Route } from 'react-router-dom'
import Routes from './Routes';
class App extends Component {
render() {
return (
<div className="App">
<Router>
<Routes/>
</Router>
</div>
);
}
}
export default App;
我认为你也可以从这里实现同样的目标。
React Router v5 的完整答案。
const Router = () => {
return (
<Switch>
<Route path={"/"} component={LandingPage} exact />
<Route path={"/games"} component={Games} />
<Route path={"/game-details/:id"} component={GameDetails} />
<Route
path={"/dashboard"}
render={({ match: { path } }) => (
<Dashboard>
<Switch>
<Route
exact
path={path + "/"}
component={DashboardDefaultContent}
/>
<Route path={`${path}/inbox`} component={Inbox} />
<Route
path={`${path}/settings-and-privacy`}
component={SettingsAndPrivacy}
/>
<Redirect exact from={path + "/*"} to={path} />
</Switch>
</Dashboard>
)}
/>
<Route path="/not-found" component={NotFound} />
<Redirect exact from={"*"} to={"/not-found"} />
</Switch>
);
};
export default Router;
const Dashboard = ({ children }) => {
return (
<Grid
container
direction="row"
justify="flex-start"
alignItems="flex-start"
>
<DashboardSidebarNavigation />
{children}
</Grid>
);
};
export default Dashboard;
Github 仓库在这里。 https://github.com/webmasterdevlin/react-router-5-demo
我更喜欢使用反应功能。该解决方案简短且更具可读性
const MainAppRoutes = () => (
<Switch>
<Route exact path='/' component={HomePage} />
{AdminRoute()}
{SampleRoute("/sample_admin")}
</Switch>
);
/*first implementation: without params*/
const AdminRoute = () => ([
<Route path='/admin/home' component={AdminHome} />,
<Route path='/admin/about' component={AdminAbout} />
]);
/*second implementation: with params*/
const SampleRoute = (main) => ([
<Route path={`${main}`} component={MainPage} />,
<Route path={`${main}/:id`} component={MainPage} />
]);
**This code worked for me with v6**
index.js
ReactDOM.render(
<React.StrictMode>
<BrowserRouter>
<Routes>
<Route path="/" element={<App />}>
<Route path="login" element={<Login />} />
<Route path="home" element={<Home />} />
</Route>
</Routes>
</BrowserRouter>
</React.StrictMode>,
document.getElementById('root')
);
应用程序.js:
function App(props) {
useEffect(() => {
console.log('reloaded');
// Checking, if Parent component re-rendering or not *it should not be, in the sense of performance*, this code doesn't re-render parent component while loading children
});
return (
<div className="App">
<Link to="login">Login</Link>
<Link to="home">Home</Link>
<Outlet /> // This line is important, otherwise we will be shown with empty component
</div>
);
}
登录.js:
const Login = () => {
return (
<div>
Login Component
</div>
)
};
主页.js:
const Home= () => {
return (
<div>
Home Component
</div>
)
};
interface IDefaultLayoutProps {
children: React.ReactNode
}
const DefaultLayout: React.SFC<IDefaultLayoutProps> = ({children}) => {
return (
<div className="DefaultLayout">
{children}
</div>
);
}
const LayoutRoute: React.SFC<IDefaultLayoutRouteProps & RouteProps> = ({component: Component, layout: Layout, ...rest}) => {
const handleRender = (matchProps: RouteComponentProps<{}, StaticContext>) => (
<Layout>
<Component {...matchProps} />
</Layout>
);
return (
<Route {...rest} render={handleRender}/>
);
}
const ScreenRouter = () => (
<BrowserRouter>
<div>
<Link to="/">Home</Link>
<Link to="/counter">Counter</Link>
<Switch>
<LayoutRoute path="/" exact={true} layout={DefaultLayout} component={HomeScreen} />
<LayoutRoute path="/counter" layout={DashboardLayout} component={CounterScreen} />
</Switch>
</div>
</BrowserRouter>
);
${match.url}
隐含的to="exampleTopicId"
。