如何在 Oracle 中获取主键列？

SELECT cols.table_name, cols.column_name, cols.position, cons.status, cons.owner
FROM all_constraints cons, all_cons_columns cols
WHERE cols.table_name = 'TABLE_NAME'
AND cons.constraint_type = 'P'
AND cons.constraint_name = cols.constraint_name
AND cons.owner = cols.owner
ORDER BY cols.table_name, cols.position;

确保“TABLE_NAME”是大写的，因为 Oracle 以大写形式存储表名。

与“Richie”的答案相同，但更简洁一些。

仅查询用户约束 SELECT column_name FROM all_cons_columns WHERE constraint_name = ( SELECT constraint_name FROM user_constraints WHERE UPPER(table_name) = UPPER('tableName') AND CONSTRAINT_TYPE = 'P' );查询所有约束 SELECT column_name FROM all_cons_columns WHERE constraint_name = ( SELECT constraint_name FROM all_constraints WHERE UPPER(table_name) = UPPER('tableName') AND CONSTRAINT_TYPE = 'P' );

Select constraint_name,constraint_type from user_constraints where table_name** **= ‘TABLE_NAME’ ;

（这将列出主键，然后）

Select column_name,position from user_cons_columns where constraint_name=’PK_XYZ’; 

（这会给你列，这里 PK_XYZ 是主键名称）

试试这个代码在这里我创建了一个表，用于在 oracle 中获取主键列，称为测试然后查询

create table test
(
id int,
name varchar2(20),
city varchar2(20),
phone int,
constraint pk_id_name_city primary key (id,name,city)
);

SELECT cols.table_name, cols.column_name, cols.position, cons.status, cons.owner FROM all_constraints cons, all_cons_columns cols WHERE cols.table_name = 'TEST' AND cons.constraint_type = 'P' AND cons.constraint_name = cols.constraint_name AND cons.owner = cols.owner  ORDER BY cols.table_name, cols.position;

将以下脚本另存为 findPK.sql 之类的文件。

set verify off
accept TABLE_NAME char prompt 'Table name>'

SELECT cols.column_name
FROM all_constraints cons NATURAL JOIN all_cons_columns cols
WHERE cons.constraint_type = 'P' AND table_name = UPPER('&TABLE_NAME');

然后可以使用

@findPK