Django: Display Choice Value
models.py:
class Person(models.Model):
name = models.CharField(max_length=200)
CATEGORY_CHOICES = (
('M', 'Male'),
('F', 'Female'),
)
gender = models.CharField(max_length=200, choices=CATEGORY_CHOICES)
to_be_listed = models.BooleanField(default=True)
description = models.CharField(max_length=20000, blank=True)
views.py:
def index(request):
latest_person_list2 = Person.objects.filter(to_be_listed=True)
return object_list(request, template_name='polls/schol.html',
queryset=latest_person_list, paginate_by=5)
On the template, when I call person.gender, I get 'M' or 'F' instead of 'Male' or 'Female'.
How to display the value ('Male' or 'Female') instead of the code ('M'/'F')?
200. With max_lenght=1 is enough, will make your site more efficient and you will ensure that you wont have wrong data. :)
It looks like you were on the right track - get_FOO_display() is most certainly what you want:
In templates, you don't include () in the name of a method. Do the following:
{{ person.get_gender_display }}
For every field that has choices set, the object will have a get_FOO_display() method, where FOO is the name of the field. This method returns the “human-readable” value of the field.
In Views
person = Person.objects.filter(to_be_listed=True)
context['gender'] = person.get_gender_display()
In Template
{{ person.get_gender_display }}
Documentation of get_FOO_display()
Others have pointed out that a get_FOO_display method is what you need. I'm using this:
def get_type(self):
return [i[1] for i in Item._meta.get_field('type').choices if i[0] == self.type][0]
which iterates over all of the choices that a particular item has until it finds the one that matches the items type
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{{ person.get_gender_display() }}