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C++ template typedef

I have a class

template<size_t N, size_t M>
class Matrix {
    // ....
};

I want to make a typedef which creates a Vector (column vector) which is equivalent to a Matrix with sizes N and 1. Something like that:

typedef Matrix<N,1> Vector<N>;

Which produces compile error. The following creates something similar, but not exactly what I want:

template <size_t N>
class Vector: public Matrix<N,1>
{ };

Is there a solution or a not too expensive workaround / best-practice for it?


G
GManNickG

C++11 added alias declarations, which are generalization of typedef, allowing templates:

template <size_t N>
using Vector = Matrix<N, 1>;

The type Vector<3> is equivalent to Matrix<3, 1>.

In C++03, the closest approximation was:

template <size_t N>
struct Vector
{
    typedef Matrix<N, 1> type;
};

Here, the type Vector<3>::type is equivalent to Matrix<3, 1>.


Oh great, I hadn't seen this part of C++0x and I've been bitching about templated typedef for a while... guess I should have a more thorough read of the final draft.
Will inheriting constructors make the OP's original solution are more viable solution?
@StackedCrooked: Depends on his goals. I avoid inheritance when composition will do (and yeah, inheriting constructors will make both of these easier), but I also avoid composition when a typedef will do.
using does not support specialization if I'm not wrong, so the second option is still useful in many cases.
@UtkarshBhardwaj Notice you can combine the two, similar to the way that <type_traits> contains alias declarations such as std::remove_reference_t the refer to various specializations of std:::remove_reference.