How to draw polygons on an HTML5 canvas?

Create a path with moveTo and lineTo (live demo):

var ctx = canvas.getContext('2d');
ctx.fillStyle = '#f00';
ctx.beginPath();
ctx.moveTo(0, 0);
ctx.lineTo(100,50);
ctx.lineTo(50, 100);
ctx.lineTo(0, 90);
ctx.closePath();
ctx.fill();

from http://www.scienceprimer.com/drawing-regular-polygons-javascript-canvas:

The following code will draw a hexagon. Change the number of sides to create different regular polygons.

var ctx = document.getElementById('hexagon').getContext('2d'); // hexagon var numberOfSides = 6, size = 20, Xcenter = 25, Ycenter = 25; ctx.beginPath(); ctx.moveTo (Xcenter + size * Math.cos(0), Ycenter + size * Math.sin(0)); for (var i = 1; i <= numberOfSides;i += 1) { ctx.lineTo (Xcenter + size * Math.cos(i * 2 * Math.PI / numberOfSides), Ycenter + size * Math.sin(i * 2 * Math.PI / numberOfSides)); } ctx.strokeStyle = "#000000"; ctx.lineWidth = 1; ctx.stroke(); #hexagon { border: thin dashed red; }

//poly [x,y, x,y, x,y.....];
var poly=[ 5,5, 100,50, 50,100, 10,90 ];
var canvas=document.getElementById("canvas")
var ctx = canvas.getContext('2d');
ctx.fillStyle = '#f00';

ctx.beginPath();
ctx.moveTo(poly[0], poly[1]);
for(let item=2 ; item < poly.length-1 ; item+=2 ){ctx.lineTo( poly[item] , poly[item+1] )}
 
ctx.closePath();
ctx.fill();

//create and fill polygon
CanvasRenderingContext2D.prototype.fillPolygon = function (pointsArray, fillColor,     strokeColor) {
    if (pointsArray.length <= 0) return;
    this.moveTo(pointsArray[0][0], pointsArray[0][1]);
    for (var i = 0; i < pointsArray.length; i++) {
        this.lineTo(pointsArray[i][0], pointsArray[i][1]);
    }
    if (strokeColor != null && strokeColor != undefined)
        this.strokeStyle = strokeColor;

    if (fillColor != null && fillColor != undefined) {
        this.fillStyle = fillColor;
        this.fill();
    }
}
//And you can use this method as 
var polygonPoints = [[10,100],[20,75],[50,100],[100,100],[10,100]];
context.fillPolygon(polygonPoints, '#F00','#000');

Here is a function that even supports clockwise/anticlockwise drawing do that you control fills with the non-zero winding rule.

Here is a full article on how it works and more.

// Defines a path for any regular polygon with the specified number of sides and radius, 
// centered on the provide x and y coordinates.
// optional parameters: startAngle and anticlockwise

function polygon(ctx, x, y, radius, sides, startAngle, anticlockwise) {
  if (sides < 3) return;
  var a = (Math.PI * 2)/sides;
  a = anticlockwise?-a:a;
  ctx.save();
  ctx.translate(x,y);
  ctx.rotate(startAngle);
  ctx.moveTo(radius,0);
  for (var i = 1; i < sides; i++) {
    ctx.lineTo(radius*Math.cos(a*i),radius*Math.sin(a*i));
  }
  ctx.closePath();
  ctx.restore();
}

// Example using the function.
// Define a path in the shape of a pentagon and then fill and stroke it.
context.beginPath();
polygon(context,125,125,100,5,-Math.PI/2);
context.fillStyle="rgba(227,11,93,0.75)";
context.fill();
context.stroke();

In addition to @canvastag, use a while loop with shift I think is more concise:

var canvas = document.getElementById('canvas');
var ctx = canvas.getContext('2d');

var poly = [5, 5, 100, 50, 50, 100, 10, 90];

// copy array
var shape = poly.slice(0);

ctx.fillStyle = '#f00'
ctx.beginPath();
ctx.moveTo(shape.shift(), shape.shift());
while(shape.length) {
  ctx.lineTo(shape.shift(), shape.shift());
}
ctx.closePath();
ctx.fill();

You can use the lineTo() method same as: var objctx = canvas.getContext('2d');

        objctx.beginPath();
        objctx.moveTo(75, 50);
        objctx.lineTo(175, 50);
        objctx.lineTo(200, 75);
        objctx.lineTo(175, 100);
        objctx.lineTo(75, 100);
        objctx.lineTo(50, 75);
        objctx.closePath();
        objctx.fillStyle = "rgb(200,0,0)";
        objctx.fill();

if you not want to fill the polygon use the stroke() method in the place of fill()

You can also check the following: http://www.authorcode.com/draw-and-fill-a-polygon-and-triangle-in-html5/

thanks

For the people looking for regular polygons:

function regPolyPath(r,p,ctx){ //Radius, #points, context
  //Azurethi was here!
  ctx.moveTo(r,0);
  for(i=0; i<p+1; i++){
    ctx.rotate(2*Math.PI/p);
    ctx.lineTo(r,0);
  }
  ctx.rotate(-2*Math.PI/p);
}

Use:

//Get canvas Context
var c = document.getElementById("myCanvas");
var ctx = c.getContext("2d");

ctx.translate(60,60);    //Moves the origin to what is currently 60,60
//ctx.rotate(Rotation);  //Use this if you want the whole polygon rotated
regPolyPath(40,6,ctx);   //Hexagon with radius 40
//ctx.rotate(-Rotation); //remember to 'un-rotate' (or save and restore)
ctx.stroke();

To make a simple hexagon without the need for a loop, Just use the beginPath() function. Make sure your canvas.getContext('2d') is the equal to ctx if not it will not work.

I also like to add a variable called times that I can use to scale the object if I need to.This what I don't need to change each number.

     // Times Variable 

     var times = 1;

    // Create a shape

    ctx.beginPath();
    ctx.moveTo(99*times, 0*times);
    ctx.lineTo(99*times, 0*times);
    ctx.lineTo(198*times, 50*times);
    ctx.lineTo(198*times, 148*times);
    ctx.lineTo(99*times, 198*times);
    ctx.lineTo(99*times, 198*times);
    ctx.lineTo(1*times, 148*times);
    ctx.lineTo(1*times,57*times);
    ctx.closePath();
    ctx.clip();
    ctx.stroke();

Let's do that with HTML and get that down to this:

<!DOCTYPE html>
 <html>
 <head>
   <title> SVG hexagon </title>
 </head>

 <body>
   <svg width="300" height="110" >
     <polygon point="50 3, 100 28, 100 75, 50 100, 3 75, 3 25" stroke="red" fill="lime" stroke-width="5"/>
   </svg>
 </body>
</html>

var ctx = document.getElementById('hexagon').getContext('2d'); // hexagon var numberOfSides = 4, size = 25, Xcenter = 40, Ycenter = 40; ctx.beginPath(); ctx.moveTo (Xcenter + size * Math.cos(0), Ycenter + size * Math.sin(0)); for (var i = 1; i <= numberOfSides;i += 1) { ctx.lineTo (Xcenter + size * Math.cos(i * 2 * Math.PI / numberOfSides), Ycenter + size * Math.sin(i * 2 * Math.PI / numberOfSides)); } ctx.strokeStyle = "#000000"; ctx.lineWidth = 1; ctx.stroke(); #hexagon { border: thin dashed red; }