How can I delay a method call for 1 second?

performSelector:withObject:afterDelay:

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You could also use a block

dispatch_after(dispatch_time(DISPATCH_TIME_NOW, 1 * NSEC_PER_SEC), dispatch_get_main_queue(), ^{
    [object method]; 
});

Most of time you will want to use dispatch_get_main_queue, although if there is no UI in the method you could use a global queue.

Edit:

Swift 3 version:

DispatchQueue.main.asyncAfter(deadline: .now() + 1) {
    object.method()
}

Equally, DispatchQueue.global().asyncAfter(... might also be a good option.

Best way to do is :

[self performSelector:@selector(YourFunctionName) 
           withObject:(can be Self or Object from other Classes) 
           afterDelay:(Time Of Delay)];

you can also pass nil as withObject parameter.

example :

[self performSelector:@selector(subscribe) withObject:self afterDelay:3.0 ];

There are already a lot of answers and they are all correct. In case you want to use the dispatch_after you should be looking for the snippet which is included inside the Code Snippet Library at the right bottom (where you can select the UI elements).

https://i.stack.imgur.com/OSIvz.png

So you just need to call this snippet by writing dispatch in code:

https://i.stack.imgur.com/UP6gM.png

You can use the perform selector for after the 0.1 sec delay method is call for that following code to do this.

[self performSelector:@selector(InsertView)  withObject:nil afterDelay:0.1]; 

You can also:

[UIView animateWithDuration:1.0
                 animations:^{ self.view.alpha = 1.1; /* Some fake chages */ }
                 completion:^(BOOL finished)
{
    NSLog(@"A second lapsed.");
}];

This case you have to fake some changes to some view to get the animation work. It is hacky indeed, but I love the block based stuff. Or wrap up @mcfedr answer below.

waitFor(1.0, ^
{
    NSLog(@"A second lapsed");
});

typedef void (^WaitCompletionBlock)();
void waitFor(NSTimeInterval duration, WaitCompletionBlock completion)
{
    dispatch_after(dispatch_time(DISPATCH_TIME_NOW, duration * NSEC_PER_SEC),
                   dispatch_get_main_queue(), ^
    { completion(); });
}

You can do this

[self performSelector:@selector(MethodToExecute) withObject:nil afterDelay:1.0 ];

Swift 2.x

let delayTime = dispatch_time(DISPATCH_TIME_NOW, Int64(1 * Double(NSEC_PER_SEC)))
 dispatch_after(delayTime, dispatch_get_main_queue()) {
 print("do some work")
}

Swift 3.x --&-- Swift 4

DispatchQueue.main.asyncAfter(deadline: .now() + 1.0) {
    print("do some work")
}

or pass a escaping closure

func delay(seconds: Double, completion: @escaping()-> Void) {
    DispatchQueue.main.asyncAfter(deadline: .now() + seconds, execute: completion)
}

There is a Swift 3 solution from the checked solution :

self.perform(#selector(self.targetMethod), with: self, afterDelay: 1.0)

And there is the method

@objc fileprivate func targetMethod(){

}

Use in Swift 3

perform(<Selector>, with: <object>, afterDelay: <Time in Seconds>)

NOTE: this will pause your whole thread, not just the one method. Make a call to sleep/wait/halt for 1000 ms just before calling your method?

Sleep(1000); // does nothing the next 1000 mSek

Methodcall(params); // now do the real thing

Edit: The above answer applies to the general question "How can I delay a method call for 1 second?", which was the question asked at the time of the answer (infact the answer was given within 7 minutes of the original question :-)). No Info was given about the language at that time, so kindly stop bitching about the proper way of using sleep i XCode og the lack of classes...