Is there any way to convert Java String
to a byte[]
(not the boxed Byte[]
)?
In trying this:
System.out.println(response.split("\r\n\r\n")[1]);
System.out.println("******");
System.out.println(response.split("\r\n\r\n")[1].getBytes().toString());
and I'm getting separate outputs. Unable to display 1st output as it is a gzip string.
<A Gzip String>
******
[B@38ee9f13
The second is an address. Is there anything I'm doing wrong? I need the result in a byte[]
to feed it to gzip decompressor, which is as follows.
String decompressGZIP(byte[] gzip) throws IOException {
java.util.zip.Inflater inf = new java.util.zip.Inflater();
java.io.ByteArrayInputStream bytein = new java.io.ByteArrayInputStream(gzip);
java.util.zip.GZIPInputStream gzin = new java.util.zip.GZIPInputStream(bytein);
java.io.ByteArrayOutputStream byteout = new java.io.ByteArrayOutputStream();
int res = 0;
byte buf[] = new byte[1024];
while (res >= 0) {
res = gzin.read(buf, 0, buf.length);
if (res > 0) {
byteout.write(buf, 0, res);
}
}
byte uncompressed[] = byteout.toByteArray();
return (uncompressed.toString());
}
String.getBytes()
does indeed return a byte array, but your belief that the toString()
of a byte array will return a useful result is incorrect.
The object your method decompressGZIP()
needs is a byte[]
.
So the basic, technical answer to the question you have asked is:
byte[] b = string.getBytes();
byte[] b = string.getBytes(Charset.forName("UTF-8"));
byte[] b = string.getBytes(StandardCharsets.UTF_8); // Java 7+ only
However the problem you appear to be wrestling with is that this doesn't display very well. Calling toString()
will just give you the default Object.toString()
which is the class name + memory address. In your result [B@38ee9f13
, the [B
means byte[]
and 38ee9f13
is the memory address, separated by an @
.
For display purposes you can use:
Arrays.toString(bytes);
But this will just display as a sequence of comma-separated integers, which may or may not be what you want.
To get a readable String
back from a byte[]
, use:
String string = new String(byte[] bytes, Charset charset);
The reason the Charset
version is favoured, is that all String
objects in Java are stored internally as UTF-16. When converting to a byte[]
you will get a different breakdown of bytes for the given glyphs of that String
, depending upon the chosen charset.
String example = "Convert Java String";
byte[] bytes = example.getBytes();
Simply:
String abc="abcdefghight";
byte[] b = abc.getBytes();
abc
contains non US-ASCII characters, like "greater than 2³² − 1"
or just binary data (like "�A���b2")?
�
this string has only 5 characters. However when I use getBytes()
i got 7 characters.
Try using String.getBytes(). It returns a byte[] representing string data. Example:
String data = "sample data";
byte[] byteData = data.getBytes();
You can use String.getBytes()
which returns the byte[]
array.
You might wanna try return new String(byteout.toByteArray(Charset.forName("UTF-8")))
It is not necessary to change java as a String parameter. You have to change the c code to receive a String without a pointer and in its code:
Bool DmgrGetVersion (String szVersion);
Char NewszVersion [200];
Strcpy (NewszVersion, szVersion.t_str ());
.t_str () applies to builder c ++ 2010
I know I'm a little late tothe party but thisworks pretty neat (our professor gave it to us)
public static byte[] asBytes (String s) {
String tmp;
byte[] b = new byte[s.length() / 2];
int i;
for (i = 0; i < s.length() / 2; i++) {
tmp = s.substring(i * 2, i * 2 + 2);
b[i] = (byte)(Integer.parseInt(tmp, 16) & 0xff);
}
return b; //return bytes
}
Success story sharing
string.getBytes(StandardCharsets.UTF_8)
can also be used, and it is the same asstring.getBytes(Charset.forName("UTF-8"))
StandardCharsets
is new with Java 7Charset.forName("UTF-8")
makes or why it's important.