Removing whitespace from strings in Java

st.replaceAll("\\s+","") removes all whitespaces and non-visible characters (e.g., tab, \n).

st.replaceAll("\\s+","") and st.replaceAll("\\s","") produce the same result.

The second regex is 20% faster than the first one, but as the number consecutive spaces increases, the first one performs better than the second one.

Assign the value to a variable, if not used directly:

st = st.replaceAll("\\s+","")

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replaceAll("\\s","")

\w = Anything that is a word character

\W = Anything that isn't a word character (including punctuation etc)

\s = Anything that is a space character (including space, tab characters etc)

\S = Anything that isn't a space character (including both letters and numbers, as well as punctuation etc)

(Edit: As pointed out, you need to escape the backslash if you want \s to reach the regex engine, resulting in \\s.)

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The most correct answer to the question is:

String mysz2 = mysz.replaceAll("\\s","");

I just adapted this code from the other answers. I'm posting it because besides being exactly what the question requested, it also demonstrates that the result is returned as a new string, the original string is not modified as some of the answers sort of imply.

(Experienced Java developers might say "of course, you can't actually modify a String", but the target audience for this question may well not know this.)

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How about replaceAll("\\s", ""). Refer here.

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One way to handle String manipulations is StringUtils from Apache commons.

String withoutWhitespace = StringUtils.deleteWhitespace(whitespaces);

You can find it here. commons-lang includes lots more and is well supported.

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If you need to remove unbreakable spaces too, you can upgrade your code like this :

st.replaceAll("[\\s|\\u00A0]+", "");

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You should use

s.replaceAll("\\s+", "");

instead of:

s.replaceAll("\\s", "");

This way, it will work with more than one spaces between each string. The + sign in the above regex means "one or more \s"

--\s = Anything that is a space character (including space, tab characters etc). Why do we need s+ here?

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If you prefer utility classes to regexes, there is a method trimAllWhitespace(String) in StringUtils in the Spring Framework.

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You've already got the correct answer from Gursel Koca but I believe that there's a good chance that this is not what you really want to do. How about parsing the key-values instead?

import java.util.Enumeration;
import java.util.Hashtable;

class SplitIt {
  public static void main(String args[])  {

    String person = "name=john age=13 year=2001";

    for (String p : person.split("\\s")) {
      String[] keyValue = p.split("=");
      System.out.println(keyValue[0] + " = " + keyValue[1]);
    }
  }
}

output: name = john age = 13 year = 2001

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The easiest way to do this is by using the org.apache.commons.lang3.StringUtils class of commons-lang3 library such as "commons-lang3-3.1.jar" for example.

Use the static method "StringUtils.deleteWhitespace(String str)" on your input string & it will return you a string after removing all the white spaces from it. I tried your example string "name=john age=13 year=2001" & it returned me exactly the string that you wanted - "name=johnage=13year=2001". Hope this helps.

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You can do it so simply by

String newMysz = mysz.replace(" ","");

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public static void main(String[] args) {        
    String s = "name=john age=13 year=2001";
    String t = s.replaceAll(" ", "");
    System.out.println("s: " + s + ", t: " + t);
}

Output:
s: name=john age=13 year=2001, t: name=johnage=13year=2001

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I am trying an aggregation answer where I test all ways of removing all whitespaces in a string. Each method is ran 1 million times and then then the average is taken. Note: Some compute will be used on summing up all the runs.

Results:

1st place from @jahir 's answer

StringUtils with short text: 1.21E-4 ms (121.0 ms)

StringUtils with long text: 0.001648 ms (1648.0 ms)

2nd place

String builder with short text: 2.48E-4 ms (248.0 ms)

String builder with long text: 0.00566 ms (5660.0 ms)

3rd place

Regex with short text: 8.36E-4 ms (836.0 ms)

Regex with long text: 0.008877 ms (8877.0 ms)

4th place

For loop with short text: 0.001666 ms (1666.0 ms)

For loop with long text: 0.086437 ms (86437.0 ms)

Here is the code:

public class RemoveAllWhitespaces {
    public static String Regex(String text){
        return text.replaceAll("\\s+", "");
    }

    public static String ForLoop(String text) {
        for (int i = text.length() - 1; i >= 0; i--) {
            if(Character.isWhitespace(text.codePointAt(i))) {
                text = text.substring(0, i) + text.substring(i + 1);
            }
        }

        return text;
    }

    public static String StringBuilder(String text){
        StringBuilder builder = new StringBuilder(text);
        for (int i = text.length() - 1; i >= 0; i--) {
            if(Character.isWhitespace(text.codePointAt(i))) {
                builder.deleteCharAt(i);
            }
        }

        return builder.toString();
    }
}

Here are the tests:

import org.junit.jupiter.api.Test;

import java.util.function.Function;
import java.util.stream.IntStream;

import static org.junit.jupiter.api.Assertions.*;

public class RemoveAllWhitespacesTest {
    private static final String longText = "123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222123 123 \t 1adc \n 222";
    private static final String expected = "1231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc2221231231adc222";

    private static final String shortText = "123 123 \t 1adc \n 222";
    private static final String expectedShortText = "1231231adc222";

    private static final int numberOfIterations = 1000000;

    @Test
    public void Regex_LongText(){
        RunTest("Regex_LongText", text -> RemoveAllWhitespaces.Regex(text), longText, expected);
    }

    @Test
    public void Regex_ShortText(){
        RunTest("Regex_LongText", text -> RemoveAllWhitespaces.Regex(text), shortText, expectedShortText);

    }

    @Test
    public void For_LongText(){
        RunTest("For_LongText", text -> RemoveAllWhitespaces.ForLoop(text), longText, expected);
    }

    @Test
    public void For_ShortText(){
        RunTest("For_LongText", text -> RemoveAllWhitespaces.ForLoop(text), shortText, expectedShortText);
    }

    @Test
    public void StringBuilder_LongText(){
        RunTest("StringBuilder_LongText", text -> RemoveAllWhitespaces.StringBuilder(text), longText, expected);
    }

    @Test
    public void StringBuilder_ShortText(){
        RunTest("StringBuilder_ShortText", text -> RemoveAllWhitespaces.StringBuilder(text), shortText, expectedShortText);
    }

    private void RunTest(String testName, Function<String,String> func, String input, String expected){
        long startTime = System.currentTimeMillis();
        IntStream.range(0, numberOfIterations)
                .forEach(x -> assertEquals(expected, func.apply(input)));
        double totalMilliseconds = (double)System.currentTimeMillis() - (double)startTime;
        System.out.println(
                String.format(
                        "%s: %s ms (%s ms)",
                        testName,
                        totalMilliseconds / (double)numberOfIterations,
                        totalMilliseconds
                )
        );
    }
}

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mysz = mysz.replace(" ","");

First with space, second without space.

Then it is done.

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String a="string with                multi spaces ";
//or this 
String b= a.replaceAll("\\s+"," ");
String c= a.replace("    "," ").replace("   "," ").replace("  "," ").replace("   "," ").replace("  "," ");

//it work fine with any spaces *don't forget space in sting b

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Use mysz.replaceAll("\\s+","");

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Use apache string util class is better to avoid NullPointerException

org.apache.commons.lang3.StringUtils.replace("abc def ", " ", "")

Output

abcdef

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\W means "non word character". The pattern for whitespace characters is \s. This is well documented in the Pattern javadoc.

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In java we can do following operation:

String pattern="[\\s]";
String replace="";
part="name=john age=13 year=2001";
Pattern p=Pattern.compile(pattern);
Matcher m=p.matcher(part);
part=m.replaceAll(replace);
System.out.println(part);

for this you need to import following packages to your program:

import java.util.regex.Matcher;
import java.util.regex.Pattern;

i hope it will help you.

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Using Pattern And Matcher it is more Dynamic.

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class RemovingSpace {

    /**
     * @param args
     * Removing Space Using Matcher
     */
    public static void main(String[] args) {
        String str= "jld fdkjg jfdg ";
        String pattern="[\\s]";
        String replace="";

        Pattern p= Pattern.compile(pattern);
        Matcher m=p.matcher(str);

        str=m.replaceAll(replace);
        System.out.println(str);    
    }
}

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When using st.replaceAll("\\s+","") in Kotlin, make sure you wrap "\\s+" with Regex:

"myString".replace(Regex("\\s+"), "")

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import java.util.*;
public class RemoveSpace {
    public static void main(String[] args) {
        String mysz = "name=john age=13 year=2001";
        Scanner scan = new Scanner(mysz);

        String result = "";
        while(scan.hasNext()) {
            result += scan.next();
        }
        System.out.println(result);
    }
}

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To remove spaces in your example, this is another way to do it:

String mysz = "name=john age=13 year=2001";
String[] test = mysz.split(" ");
mysz = String.join("", mysz);

What this does is it converts it into an array with the spaces being the separators, and then it combines the items in the array together without the spaces.

It works pretty well and is easy to understand.

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there are many ways to solve this problem. you can use split function or replace function of Strings.

for more info refer smilliar problem http://techno-terminal.blogspot.in/2015/10/how-to-remove-spaces-from-given-string.html

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There are others space char too exists in strings.. So space char we may need to replace from strings.

Ex: NO-BREAK SPACE, THREE-PER-EM SPACE, PUNCTUATION SPACE

Here is the list of space char http://jkorpela.fi/chars/spaces.html

So we need to modify

\u2004 us for THREE-PER-EM SPACE

s.replaceAll("[\u0020\u2004]","")

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package com.sanjayacchana.challangingprograms;

public class RemoveAllWhiteSpacesInString {

    public static void main(String[] args) {
        
        String str = "name=john age=13 year=2001";
        
        str = str.replaceAll("\\s", ""); 
        
        System.out.println(str);
        
        
    }

}

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White space can remove using isWhitespace function from Character Class.

public static void main(String[] args) {
    String withSpace = "Remove white space from line";
    StringBuilder removeSpace = new StringBuilder();

    for (int i = 0; i<withSpace.length();i++){
        if(!Character.isWhitespace(withSpace.charAt(i))){
            removeSpace=removeSpace.append(withSpace.charAt(i));
        }
    }
    System.out.println(removeSpace);
}

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Separate each group of text into its own substring and then concatenate those substrings:

public Address(String street, String city, String state, String zip ) {
    this.street = street;
    this.city = city;
    // Now checking to make sure that state has no spaces...
    int position = state.indexOf(" ");
    if(position >=0) {
        //now putting state back together if it has spaces...
        state = state.substring(0, position) + state.substring(position + 1);  
    }
}

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public static String removeWhiteSpaces(String str){
    String s = "";
    char[] arr = str.toCharArray();
    for (int i = 0; i < arr.length; i++) {
        int temp = arr[i];
        if(temp != 32 && temp != 9) { // 32 ASCII for space and 9 is for Tab
            s += arr[i];
        }
    }
    return s;
}

This might help.

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You can also take a look at the below Java code. Following codes does not use any "built-in" methods.

/**
 * Remove all characters from an alphanumeric string.
 */
public class RemoveCharFromAlphanumerics {

    public static void main(String[] args) {

        String inp = "01239Debashish123Pattn456aik";

        char[] out = inp.toCharArray();

        int totint=0;

        for (int i = 0; i < out.length; i++) {
            System.out.println(out[i] + " : " + (int) out[i]);
            if ((int) out[i] >= 65 && (int) out[i] <= 122) {
                out[i] = ' ';
            }
            else {
                totint+=1;
            }

        }

        System.out.println(String.valueOf(out));
        System.out.println(String.valueOf("Length: "+ out.length));

        for (int c=0; c<out.length; c++){

            System.out.println(out[c] + " : " + (int) out[c]);

            if ( (int) out[c] == 32) {
                System.out.println("Its Blank");
                 out[c] = '\'';
            }

        }

        System.out.println(String.valueOf(out));

        System.out.println("**********");
        System.out.println("**********");
        char[] whitespace = new char[totint];
        int t=0;
        for (int d=0; d< out.length; d++) {

            int fst =32;



            if ((int) out[d] >= 48 && (int) out[d] <=57 ) {

                System.out.println(out[d]);
                whitespace[t]= out[d];
                t+=1;

            }

        }

        System.out.println("**********");
        System.out.println("**********");

        System.out.println("The String is: " + String.valueOf(whitespace));

    }
}

Input:

String inp = "01239Debashish123Pattn456aik";

Output:

The String is: 01239123456

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