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How to restrict UITextField to take only numbers in Swift?

I want the user to only enter numeric values in a UITextField. On iPhone we can show the numeric keyboard, but on iPad the user can switch to any keyboard.

Is there any way to restrict user to enter only numeric values in a UITextField?

you have to alter the entered text.
yes , but in ipad user can enter alphabet even after if we set numeric keyboard
What do you mean by altering the text?

א
אורי orihpt

Solution for swift 3.0 and above

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
    let allowedCharacters = CharacterSet.decimalDigits
    let characterSet = CharacterSet(charactersIn: string)
    return allowedCharacters.isSuperset(of: characterSet)
}

Your view controller should conform UITextFieldDelegate, in viewDidLoad put yourNumbersTextField.delegate = self
what is range?.
why you didn't mention UITextFieldDelegate??
@user924 range is returned by UITextField delegate method
@user924 mention of UITextFieldDelegate is basic requirement
S
SahyadriChava

Here is my 2 Cents. (Tested on Swift 2 Only)

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {

  let aSet = NSCharacterSet(charactersInString:"0123456789").invertedSet
  let compSepByCharInSet = string.componentsSeparatedByCharactersInSet(aSet)
  let numberFiltered = compSepByCharInSet.joinWithSeparator("")
  return string == numberFiltered

}

This is just a little bit more strict. No decimal point either.

Hope it helps :)

PS: I assumed you looked after the delegate anyway.

Update: Swift 3.0 :

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {

    let aSet = NSCharacterSet(charactersIn:"0123456789").inverted
    let compSepByCharInSet = string.components(separatedBy: aSet)
    let numberFiltered = compSepByCharInSet.joined(separator: "")
    return string == numberFiltered
}

How would I restrict the UITextfield to only receive numbers and limit the amount of numbers between 6 and 8?
You can set aSet to just be CharacterSet.decimalDigits.invertedSet
Perfect for my needs. Thanks.
why you didn't mention UITextFieldDelegate??
You should also add a check for text == "" so the user can delete text backwards.
N
Naresh

In swift 4.1 and Xcode 9.4.1

Add UITextFieldDelegate to your class

class YourViewController: UIViewController, UITextFieldDelegate

Then write this code in your viewDidLoad()

mobileNoTF.delegate = self

Write this textfield delegate function

//MARK - UITextField Delegates
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
    //For mobile numer validation
    if textField == mobileNoTF {
        let allowedCharacters = CharacterSet(charactersIn:"+0123456789 ")//Here change this characters based on your requirement
        let characterSet = CharacterSet(charactersIn: string)
        return allowedCharacters.isSuperset(of: characterSet)
    }
    return true
}

how do i fix Binary operator '==' cannot be applied to operands of type 'UITextField' and '() -> ()'
@iOS, how does it works? I've added everything, but I still can type anything. The field allows any characters and the textField function is not triggered.
d
derdida

Swift 2.0

For only allowing numbers and one "." decimal in uitextfield.

func textField(textField: UITextField,shouldChangeCharactersInRange range: NSRange,replacementString string: String) -> Bool
{
    let newCharacters = NSCharacterSet(charactersInString: string)
    let boolIsNumber = NSCharacterSet.decimalDigitCharacterSet().isSupersetOfSet(newCharacters)
    if boolIsNumber == true {
        return true
    } else {
        if string == "." {
            let countdots = textField.text!.componentsSeparatedByString(".").count - 1
            if countdots == 0 {
                return true
            } else {
                if countdots > 0 && string == "." {
                    return false
                } else {
                    return true
                }
            }
        } else {
            return false
        }
    }
}

Thanks - that is great (i was looking for a solution to just allow 1 ".")
J
Jamil Hasnine Tamim

IPhone only solution

In whatever UITextField you're getting these values from, you can specify the kind of keyboard you want to appear when somebody touches inside the text field.

E.G. a numeric-only keyboard.

Like this screenshot:

https://i.stack.imgur.com/bOib8.png

Ipad

The iPad does not support the numeric keyboard, so your options are to either not support the iPad, validate the field post submit, or follow one of the other suggestions here to create same behaviors while running on an iPad.


This doesn't answer the question. Even when using the Number Pad, iOS would allow a user to paste non-numeric values into the UITextField or allow iPads to switch keyboards away from numeric.
This is simple answer of this question!! Not proper answer! I know!
It's not any answer to the question, neither simple nor proper. The question isn't asking for how to change the keyboard type. The question is asking how to restrict the input. Those are different.
Question is: How to restrict UITextField to take only numbers in Swift? So when your keyboard type is number pad, obviously it's fulfill the requirements.
The OP asks explicitly for another solution than changing keyboard type. "On iPhone we can show the numeric keyboard, but on iPad the user can switch to any keyboard."
R
Raj Joshi

Accept decimal values in text fields with single (.)dot in Swift 3

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
    let inverseSet = NSCharacterSet(charactersIn:"0123456789").inverted

    let components = string.components(separatedBy: inverseSet)

    let filtered = components.joined(separator: "")

    if filtered == string {
        return true
    } else {
        if string == "." {
            let countdots = textField.text!.components(separatedBy:".").count - 1
            if countdots == 0 {
                return true
            }else{
                if countdots > 0 && string == "." {
                    return false
                } else {
                    return true
                }
            }
        }else{
            return false
        }
    }
}

This is the only one (that restricts to one decimal) I could get working, awesome!
Actually I revised it to allow for one comma as well (as per FR)
Please note, that not all locales use the "." as a decimal separator. You might want to use Locale.current.decimalSeparator instead.
n
ndmeiri
func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    // return true if the replacementString only contains numeric characters
    let digits = NSCharacterSet.decimalDigitCharacterSet()
    for c in string {
        if !digits.characterIsMember(c) {
            return false
        }
    }

    return true
}

This solution will work even if the user switches keyboards or tries to paste a non-numeric string into the text field.

Make sure to set the delegate property of the appropriate text field.


Using [string intValue] as suggested in a previous answer will not work because that property could be true (non-zero) even if string contains non-numeric characters. According to the docs, intValue is 0 only if "the string doesn’t begin with a valid decimal text representation of a number."
S
SPatel

Use number formatter

Swift 4.x

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
      let s = NSString(string: textField.text ?? "").replacingCharacters(in: range, with: string)
      guard !s.isEmpty else { return true }
      let numberFormatter = NumberFormatter()
      numberFormatter.numberStyle = .none
      return numberFormatter.number(from: s)?.intValue != nil
 }

Thanks! This one is better than many others because it allows decimal numbers but not arbitrary use of the decimal.
s
shbli

Here is a simple solution, you need to connect the event "Editing changed" to this method in your controller

Swift 4

@IBAction func valueChanged(_ sender: UITextField) {
    if let last = sender.text?.last {
        let zero: Character = "0"
        let num: Int = Int(UnicodeScalar(String(last))!.value - UnicodeScalar(String(zero))!.value)
        if (num < 0 || num > 9) {
            //remove the last character as it is invalid
            sender.text?.removeLast()
        }
    }
}

A great solution if the delegate is already being consumed by Rx.
it will crash if i add space or symbols
z
zeeshan

Extend your view controller like this:

class MyViewController: UIViewController, UITextFieldDelegate

In the viewDidLoad function extend to your text field like this:

myTextField.delegate = self

And then use the following function:

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
    let isNumber = CharacterSet.decimalDigits.isSuperset(of: CharacterSet(charactersIn: string))
    let withDecimal = (
        string == NumberFormatter().decimalSeparator &&
        textField.text?.contains(string) == false
    )
    return isNumber || withDecimal
}

This will now make sure the user can enter only decimal digits.

Swift 4 + Accepts Number only and accepts one separator


A
Akbar Khan

1st you have to inherit the UITextFieldDelegate class with you own class

class ViewController: UIViewController, UITextFieldDelegate {

2nd add an IBOutlet

@IBOutlet weak var firstName: UITextField!

3rd you have to assure this object is using

override func viewDidLoad() {
        super.viewDidLoad()
   firstName.delegate = self
}


func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
    if textField == firstName {
                let allowedCharacters = "1234567890"
                let allowedCharacterSet = CharacterSet(charactersIn: allowedCharacters)
                let typedCharacterSet = CharacterSet(charactersIn: string)
                let alphabet = allowedCharacterSet.isSuperset(of: typedCharacterSet)
                return alphabet


      }
  }

佚名

While most of these solutions will work, be aware that in some localisations a decimals are separated with a "," and not a "."

The cleaner way to do this would be

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    let decimalCharacter = NSNumberFormatter().decimalSeparator
    let characterSet = NSMutableCharacterSet.decimalDigitCharacterSet()
    characterSet.addCharactersInString(decimalCharacter)

    return replacementString.rangeOfCharacterFromSet(characterSet.invertedSet) == nil
}

R
Rafael Ruiz Muñoz

Tested in swift 3.0

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool

{         
    let numberOnly = NSCharacterSet.init(charactersIn: "0123456789")
    let stringFromTextField = NSCharacterSet.init(charactersIn: string)
    let strValid = numberOnly.isSuperset(of: stringFromTextField as CharacterSet)

     return strValid
 }

B
Brian Nezhad

Here's an cleaner solution:

 guard CharacterSet(charactersIn: "123456789").isSuperset(of: CharacterSet(charactersIn: string)) else {
     return false
 }
 return true

For decimals just add ., example 123456789.


It's little bit nice, but compare to this use UITextfiled delegate.
J
Jagadeesh K

Set KeyboardType Property :- Number Pad TextField Delegate please write below code

  func textField(_ textField: UITextField, shouldChangeCharactersIn 
  range: NSRange, replacementString string: String) -> Bool {

    if textField.text?.count == 0 && string == "0" {
        return false
    }
    return string == string.filter("0123456789".contains)
}

Number should not start from 0 and entered number +ve.


k
keshav

//instead of these you can simply change your keyboard to number type

yourtextfield.keyboardType = UIKeyboardType.numberPad

This cannot resolve this problem, as the user can paste non-numeric characters into the text field.
then you can use number extension
s
sgib

I had actually done this when working through the Big Nerd Ranch book, my solution is:

func textField(textField: UITextField, 
    shouldChangeCharactersInRange range: NSRange, 
    replacementString string: String) -> Bool {

    let newCharacters = NSCharacterSet(charactersInString: string)
    return NSCharacterSet.decimalDigitCharacterSet().isSupersetOfSet(newCharacters)
}

this only allows the numbers 0-9, to allow the "." as well is more complicated as you can only allow one "."


l
likarson
func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    if let numRange = string.rangeOfCharacterFromSet(NSCharacterSet.letterCharacterSet()) {
        return false
    } else {
        return true
    }
   }

h
hprione

To allow only numbers and just one decimal operator, you can use this solution:

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    let isNumber = NSCharacterSet.decimalDigitCharacterSet().isSupersetOfSet(NSCharacterSet(charactersInString: string))

    return isNumber || (string == NSNumberFormatter().decimalSeparator && textField.text?.containsString(string) == false)
}

R
Ramprasath Selvam
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool

        {
            let textString = (textField.text! as NSString).replacingCharacters(in: range, with: string)

            if textField == self.phoneTextField  && string.characters.count > 0{
                let numberOnly = NSCharacterSet.decimalDigits
                let strValid = numberOnly.contains(UnicodeScalar.init(string)!)
                return strValid && textString.characters.count <= 10
            }
            return true
        }

in above code is working in swift 3
NSCharacterSet.decimalDigits
You are also use letters only
NSCharacterSet.Letters
and uppercase,Lowercaseand,alphanumerics,whitespaces is used same code or See the Link


L
Lukas

I think you can force change the keyboard type by implementing UITextInputTraits protocol, optional var keyboardType

//class ViewController: UIViewController, UITextInputTraits {

@IBOutlet weak var textFieldKeyboardType: UITextField!{
    didSet{
        textFieldKeyboardType.keyboardType = UIKeyboardType.NumberPad
    }
}
var keyboardType: UIKeyboardType { 
    get{ 
        return textFieldKeyboardType.keyboardType
    } 
    set{ 
        if newValue != UIKeyboardType.NumberPad{
            self.keyboardType = UIKeyboardType.NumberPad
        }
    } 
}

E
Enraged

This is a more readable version that will do "0-9" plus ".":

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {

    let existingTextHasDecimal = textField.text?.rangeOfString(".")
    let replacementTextHasDecimal = string.rangeOfString(".")
    let replacementTextAllCharacters = NSCharacterSet(charactersInString: string)
    let replacementTextOnlyDigits = NSCharacterSet.decimalDigitCharacterSet().isSupersetOfSet(replacementTextAllCharacters)

    if replacementTextHasDecimal != nil && existingTextHasDecimal != nil {
        return false
    }else{
        if replacementTextOnlyDigits == true {
            return true
        }else if replacementTextHasDecimal != nil{
            return true
        }else{
            return false
        }
    }
}

D
David

As if there aren't enough answers, here's mine. I think every example allowed for decimal separators is flawed in either localization, backspaces, or copy/paste.

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    if string.isEmpty {return true} //allow for backspace

    let decimalSeparator = NSNumberFormatter().decimalSeparator ?? "."
    let validChars = NSMutableCharacterSet(charactersInString: decimalSeparator)
    validChars.formUnionWithCharacterSet(NSCharacterSet.decimalDigitCharacterSet())

    if validChars.isSupersetOfSet(NSCharacterSet(charactersInString: string)){
        switch string.componentsSeparatedByString(decimalSeparator).count-1 {
        case 0: //no decimals
            return true

        case 1: //if adding decimal, only allow if no existing decimal
            if let existingText = textField.text{
                return existingText.componentsSeparatedByString(decimalSeparator).count <= 1
            }
            else {return true}

        default: //invalid decimals
            return false
        }
    }

    return false
}

C
ChinLoong

The following is the code I used in Swift 3.0 adapted from Mr H's code. Differences are because:

a) Delegate function declaration has changed in Swift 3.0. New declaration here

b) NSCharacterSet declaration has changed.

func textField(_ shouldChangeCharactersIntextField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool
{

        let inverseSet = NSCharacterSet(charactersIn:"0123456789").inverted

        let components = string.components(separatedBy: inverseSet)

        let filtered = components.joined(separator: "")

        return string == filtered

}

M
Matthijs

I have edited Raj Joshi's version to allow one dot or one comma:

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {

    let inverseSet = CharacterSet(charactersIn:"0123456789").inverted
    let components = string.components(separatedBy: inverseSet)
    let filtered = components.joined(separator: "")

    if filtered == string {
        return true
    } else {
        if string == "." || string == "," {
            let countDots = textField.text!.components(separatedBy:".").count - 1
            let countCommas = textField.text!.components(separatedBy:",").count - 1

            if countDots == 0 && countCommas == 0 {
                return true
            } else {
                return false
            }
        } else  {
            return false
        }
    }
}

f
feca

You can use this code if you want to allow decimal separator and/or negative numbers. But this code allows example: "34." (decimal separator at the end) while changing text. So you have to add some code example: textFieldShouldReturn or textFieldShouldEndEditing delegate functions.

The code written in Swift 4 but I assueme this is compatible with Swift 3.

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
    guard let text = textField.text else {
        return true
    }

    let replaced = (text as NSString).replacingCharacters(in: range, with: string)
    let decimalSeparator = NSLocale.current.decimalSeparator ?? ""

    // When user wants to delete las character
    if replaced == "" || replaced == "-" || replaced == "-0" {
        textField.text = "0"
        return false
    }

    // When text contains 0 before replace except "0."
    if replaced != "0" + decimalSeparator && replaced.hasPrefix("0") && text.underestimatedCount == 1 {
        textField.text = replaced.substring(from: replaced.index(after: replaced.startIndex))
        return false
    }

    // When user wants to delete minus sign
    if text.hasPrefix("-") && text.substring(from: text.index(after: text.startIndex)) == replaced {
        return false
    }

    // When user wants to delete before decimal separator
    if replaced.hasPrefix(decimalSeparator) || replaced.hasPrefix("-" + decimalSeparator) {
        return false
    }

    // When user wants to add zero the beginning of number... but allowing "0." or "-0." numbers
    let testReplaced = replaced.hasPrefix("-") ? replaced.substring(from: replaced.index(after: replaced.startIndex)) : replaced
    if testReplaced.count >= 2 && testReplaced.hasPrefix("0") && !testReplaced.hasPrefix("0" + decimalSeparator) {
        return false
    }

    // Every other cases
    let allowDecimal = self.allowFloat ? (decimalSeparator == "." ? "\\.?" : decimalSeparator + "?") : ""
    let allowSign = self.allowSigned ? "-?" : ""
    let pattern = "\(allowSign)[0-9]+\(allowDecimal)([0-9]+)?"

    do {
        let regexRange = (replaced as NSString).range(of: replaced)
        let regex = try NSRegularExpression(pattern: pattern, options: [])
        let matches = regex.matches(in: replaced, options: [], range: regexRange)
        return matches.count == 1 && matches.first!.range == regexRange
    }
    catch {}

    return false
}

If you don't want to allow decimal or negative numbers you have to replace tow variable with next line

let allowDecimal = ""
let allowSign = ""

I
Ilesh P

For allow some charactors

func CheckAddress(string:String) -> Bool  {
        let numberOnly = NSCharacterSet.init(charactersIn: "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz-@,&#/")
        let stringFromTextField = NSCharacterSet.init(charactersIn: string)
        return numberOnly.isSuperset(of: stringFromTextField as CharacterSet)
    }

print("\(CheckAddress(string: "123"))") //True
print("\(CheckAddress(string: "asdf-"))") //True
print("\(CheckAddress(string: "asd123$"))") //false

T
Tony

The following solution has two benefits:

It is a one line code It restricts the input so that the overall text in the input field is a valid number. Other solutions restricts the digits to valid numbers but this results in the user is able to enter "4...5"

    func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
        return NumberFormatter().numberFrom(text: (textField.text ?? "") + string) != nil
    }

E
Edison
Swift 2.0

func textField(textField: UITextField,
    shouldChangeCharactersInRange range: NSRange,
    replacementString string: String) -> Bool {

        let inverseSet = NSCharacterSet(charactersInString:"0123456789").invertedSet

        let components = string.componentsSeparatedByCharactersInSet(inverseSet)

        let filtered = components.joinWithSeparator("")

        return string == filtered

  }

d
den330
func isValidNumber(str:String) -> Bool{
    if str.isEmpty {
        return false
    }
    let newChar = NSCharacterSet(charactersInString: str)
    let boolValid = NSCharacterSet.decimalDigitCharacterSet().isSupersetOfSet(newChar)
    if boolValid{
        return true
    }else{
        let lst = str.componentsSeparatedByString(".")
        let newStr = lst.joinWithSeparator("")
        let currentChar = NSCharacterSet(charactersInString: newStr)
        if lst.count == 2 && !lst.contains("") && NSCharacterSet.decimalDigitCharacterSet().isSupersetOfSet(currentChar){
            return true
        }
        return false
    }
}

Put this function in your "Submit" or "Save" method if there is one.