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Delete all lines beginning with a # from a file

All of the lines with comments in a file begin with #. How can I delete all of the lines (and only those lines) which begin with #? Other lines containing #, but not at the beginning of the line should be ignored.

Does it have to work with the common convention that #blah \<nl>blah counts as a single "logical line" because the backslash escapes the newline?
@sarnold: apart from make, which utilities use the 'backslash splices lines before ending a comment'? The shells (bash and ksh tested) don't. C and C++ do handle newline splicing before other processing of preprocessor directives, but they're directives rather than comments.
@Jonathan: Awesome. I had assumed that the common \<nl> escaping would also work on comments. But wow I was wrong. I haven't been able to find another example yet... :) Thanks!

V
Vlad

This can be done with a sed one-liner:

sed '/^#/d'

This says, "find all lines that start with # and delete them, leaving everything else."


shorter version: sed /^#/d
For linux noobs like me: sed '/^#/ d' < inputFile.txt > outputFile.txt
Shortest version: sed -i '/^#/d' filepath.
And sed -i '' '/^#/d' filepath on Mac (because the -i suffix is mandatory)
@Viesturs Try this: awk '/^#/ && !first { first=1 ; next } { print $0}'
K
Keith Thompson

I'm a little surprised nobody has suggested the most obvious solution:

grep -v '^#' filename

This solves the problem as stated.

But note that a common convention is for everything from a # to the end of a line to be treated as a comment:

sed 's/#.*$//' filename

though that treats, for example, a # character within a string literal as the beginning of a comment (which may or may not be relevant for your case) (and it leaves empty lines).

A line starting with arbitrary whitespace followed by # might also be treated as a comment:

grep -v '^ *#' filename

if whitespace is only spaces, or

grep -v '^[  ]#' filename

where the two spaces are actually a space followed by a literal tab character (type "control-v tab").

For all these commands, omit the filename argument to read from standard input (e.g., as part of a pipe).


I have added a new answer which builds upon this answer.
I had troubles using grep in this way on Windows. The solution is to replace ' by ", e.g. grep -v "^#" filename
a
ata

The opposite of Raymond's solution:

sed -n '/^#/!p'

"don't print anything, except for lines that DON'T start with #"


ok and what's the advantage here?
@lacostenycoder It's about the same as any other option presented here, which is enough merit to mention it.
r
rubo77

you can directly edit your file with

sed -i '/^#/ d'

If you want also delete comment lines that start with some whitespace use

sed -i '/^\s*#/ d'

Usually, you want to keep the first line of your script, if it is a sha-bang, so sed should not delete lines starting with #!. also it should delete lines, that just contain only a hash but no text. put it all together:

sed -i '/^\s*\(#[^!].*\|#$\)/d'

To be conform with all sed variants you need to add a backup extension to the -i option:

sed -i.bak '/^\s*#/ d' $file
rm -Rf $file.bak

plus 1 for the one which space
j
jaypal singh

You can use the following for an awk solution -

awk '/^#/ {sub(/#.*/,"");getline;}1' inputfile

C
Community

This answer builds upon the earlier answer by Keith.

egrep -v "^[[:blank:]]*#" should filter out comment lines.

egrep -v "^[[:blank:]]*(#|$)" should filter out both comments and empty lines, as is frequently useful.

For information about [:blank:] and other character classes, refer to https://en.wikipedia.org/wiki/Regular_expression#Character_classes.


Assuming your egrep supports that syntax; older versions might not.
A
Ahmed Khaled

You also might want to remove empty lines as well

sed -E '/(^$|^#)/d' inputfile

M
Mohsen Abasi

Delete all empty lines and also all lines starting with a # after any spaces:

sed -E '/^$|^\s*#/d' inputfile

For example, see the following 3 deleted lines (including just line numbers!):

1. # first comment
2.
3.         # second comment

After testing the command above, you can use option -i to edit the input file in place.

Just this!


f
filmor

Here is it with a loop for all files with some extension:

ll -ltr *.filename_extension > list.lst

for i in $(cat list.lst | awk '{ print $8 }') # validate if it is the 8 column on ls 
do
    echo $i
    sed -i '/^#/d' $i
done