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How do I concatenate items in a list to a single string?

How do I concatenate a list of strings into a single string?

['this', 'is', 'a', 'sentence']    →    'this-is-a-sentence'

w
wjandrea

Use str.join:

>>> sentence = ['this', 'is', 'a', 'sentence']
>>> '-'.join(sentence)
'this-is-a-sentence'
>>> ' '.join(sentence)
'this is a sentence'

Didn't understand, what's the '-' on the left supposed to be??
@LawrenceDeSouza The string you want to be joined; see the documentation, or this answer which goes into a bit more detail.
I kind of expected sentence.join(" ") to work as well, since the reverse operation is list.split(" "). Any idea if this is going to be added to Python's methods for lists?
@Wouter, it will not. On the one hand, only lists of strings can be joined; so list.join would be inappropriate for an arbitrary list. On the other, the argument of str.join can be any "iterable" sequence of strings, not just a list. The only thing that would make sense is a built-in function join(list, sep); there's one in the (basically obsolete) string module if you really want it.
@Leo ' '.join(['this', 'is', 'a', 'sentence'])
M
Mateen Ulhaq

A more generic way to convert python lists to strings would be:

>>> xs = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>> ''.join(map(str, xs))
'12345678910'

why is list comprehension necessary when the input is string? also map(str, my_lst) would be enough without enumerating the list =)
Most of the answers to this question are considering the case when the list has strings in it. Mine is a generic way to convert lists to strings. In my example, the list is of type int but it could be any type that can be represented as a string.
To add to this, map would also be useful when used with a lambda function. For example ' '.join(map(lambda x: ' $'+ str(x), my_lst)) would return '$1 $2 $3 $4 $5 $6 $7 $8 $9 $10'
adding a map actually helps with datatypes apart from string. Great!
h
heilala

It's very useful for beginners to know why join is a string method.

It's very strange at the beginning, but very useful after this.

The result of join is always a string, but the object to be joined can be of many types (generators, list, tuples, etc).

.join is faster because it allocates memory only once. Better than classical concatenation (see, extended explanation).

Once you learn it, it's very comfortable and you can do tricks like this to add parentheses.

>>> ",".join("12345").join(("(",")"))
Out:
'(1,2,3,4,5)'

>>> list = ["(",")"]
>>> ",".join("12345").join(list)
Out:
'(1,2,3,4,5)'

can someone explain what the second join() i.e. join(("(",")")) does? its like magic
("(",")") is a tuple of two strings - the open parenthesis "(" and the close parenthesis ")". So the second join() joins those two strings using the output of the first join() as the separator (i.e., '1,2,3,4,5').
Is this correct? "The result of join is always a string, but the object to be joined can be of many types (generators, list, tuples, etc)." The answer by Aaron S suggests that this is not true, you have to use map(str, ) if there are other types in the list.
A
Anupam

Edit from the future: Please don't use the answer below. This function was removed in Python 3 and Python 2 is dead. Even if you are still using Python 2 you should write Python 3 ready code to make the inevitable upgrade easier.

Although @Burhan Khalid's answer is good, I think it's more understandable like this:

from str import join

sentence = ['this','is','a','sentence']

join(sentence, "-") 

The second argument to join() is optional and defaults to " ".


This function is deprecated in 2.x and going to be removed in 3.x. That being the case, I wouldn't recommend using this over the other answer provided.
@Mathew Green this answer and Burhan Khalid's answer use the same function in different ways, so his answer is deprecated as well. But thanks for pointing that out, gota figure out how to join in 3.x. But if you're using 2.x, it's not going away.
His isn't deprecated though. Your recommendation uses a function from Lib/string.py which is wholly different and deprecated whereas @BurhanKhalid answer uses the built-in string method which is not deprecated. His answer is the most correct one now and going forward whereas this is only good for now on 2.x.
All that to say that if you want to promote this alternative you should also include a warning that this is not recommended for the reasons outlined in my previous comments.
J
Jonathan Fortin
list_abc = ['aaa', 'bbb', 'ccc']

string = ''.join(list_abc)
print(string)
>>> aaabbbccc

string = ','.join(list_abc)
print(string)
>>> aaa,bbb,ccc

string = '-'.join(list_abc)
print(string)
>>> aaa-bbb-ccc

string = '\n'.join(list_abc)
print(string)
>>> aaa
>>> bbb
>>> ccc

n
nnnmmm

We can also use Python's reduce function:

from functools import reduce

sentence = ['this','is','a','sentence']
out_str = str(reduce(lambda x,y: x+"-"+y, sentence))
print(out_str)

Too much-unneeded complexity, why not just using join?
A
Abhishek V

We can specify how we have to join the string. Instead of '-', we can use ' '

sentence = ['this','is','a','sentence']
s=(" ".join(sentence))
print(s)

w
wiredcontrol

If you have mixed content list. And want to stringify it. Here is one way:

Consider this list:

>>> aa
[None, 10, 'hello']

Convert it to string:

>>> st = ', '.join(map(str, map(lambda x: f'"{x}"' if isinstance(x, str) else x, aa)))
>>> st = '[' + st + ']'
>>> st
'[None, 10, "hello"]'

If required, convert back to list:

>>> ast.literal_eval(st)
[None, 10, 'hello']

Why such overcomplication? str(aa) also gives "[None, 10, 'hello']"...
T
Tomerikoo

If you want to generate a string of strings separated by commas in final result, you can use something like this:

sentence = ['this','is','a','sentence']
sentences_strings = "'" + "','".join(sentence) + "'"
print (sentences_strings) # you will get "'this','is','a','sentence'"

P
Paul Roub
def eggs(someParameter):
    del spam[3]
    someParameter.insert(3, ' and cats.')


spam = ['apples', 'bananas', 'tofu', 'cats']
eggs(spam)
spam =(','.join(spam))
print(spam)

While this code snippet may be the solution, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion.
A
Abdulmecid Pamuk

Without .join() method you can use this method:

my_list=["this","is","a","sentence"]

concenated_string=""
for string in range(len(my_list)):
    if string == len(my_list)-1:
        concenated_string+=my_list[string]
    else:
        concenated_string+=f'{my_list[string]}-'
print([concenated_string])
    >>> ['this-is-a-sentence']

So, range based for loop in this example , when the python reach the last word of your list, it should'nt add "-" to your concenated_string. If its not last word of your string always append "-" string to your concenated_string variable.