ChatGPT解决这个技术问题 Extra ChatGPT

How can I download and save a file from the Internet using Java?

There is an online file (such as http://www.example.com/information.asp) I need to grab and save to a directory. I know there are several methods for grabbing and reading online files (URLs) line-by-line, but is there a way to just download and save the file using Java?


J
Jan Nielsen

Give Java NIO a try:

URL website = new URL("http://www.website.com/information.asp");
ReadableByteChannel rbc = Channels.newChannel(website.openStream());
FileOutputStream fos = new FileOutputStream("information.html");
fos.getChannel().transferFrom(rbc, 0, Long.MAX_VALUE);

Using transferFrom() is potentially much more efficient than a simple loop that reads from the source channel and writes to this channel. Many operating systems can transfer bytes directly from the source channel into the filesystem cache without actually copying them.

Check more about it here.

Note: The third parameter in transferFrom is the maximum number of bytes to transfer. Integer.MAX_VALUE will transfer at most 2^31 bytes, Long.MAX_VALUE will allow at most 2^63 bytes (larger than any file in existence).


Close all three with Java 7 try-with-resource: try (InputStream inputStream = website.openStream(); ReadableByteChannel readableByteChannel = Channels.newChannel(inputStream); FileOutputStream fileOutputStream = new FileOutputStream(outputFileName)) { fileOutputStream.getChannel().transferFrom(readableByteChannel, 0, 1 << 24); }
This will only download the first 16MB of a file: stackoverflow.com/questions/8405062/downloading-files-with-java
@kirdie and if I want more than 8388608 TB?
A single call isn't adequate. transferFrom() isnt' specified to complete the entire transfer in a single call. That's why it returns a count. You have to loop.
Why was this answer even accepted? URL::openStream()returns just a regular stream, meaning the entire traffic is still being copied through Java byte[] arrays instead of remaining in native buffers. Only fos.getChannel()is actually a native channel, so the overhead remains in full. That's zero gains from using NIO in this case. Apart from being broken, as EJP and Ben MacCann correctly noticed.
P
Peter Mortensen

Use Apache Commons IO. It is just one line of code:

FileUtils.copyURLToFile(URL, File)

Nice! Just what I'm looking for! I knew Apache libraries would already cover this. BTW, it's recommended to use the overloaded version with timeout parameters!
...and when using that overloaded version, remember that the timeouts are specified in milliseconds, not seconds.
Take note that copyURLToFile with timeout parameter is only available since version 2.0 of Commons IO library. See Java docs
what if basic authentication header has to be added to the request? is there a workaround?
Although this is "short", it's actually very slow.
P
Peter Mortensen

Simpler non-blocking I/O usage:

URL website = new URL("http://www.website.com/information.asp");
try (InputStream in = website.openStream()) {
    Files.copy(in, target, StandardCopyOption.REPLACE_EXISTING);
}

Unfortunately this silently fails (downloads 0 bytes) in case there is a redirect such as "302 Found".
@AlexanderK But why would you blindly download such a resource anyway?
Despite the fact this is an elegant solution, behind the scenes this approach could silently betray you. Files.copy( InputStream, Paths, FileOption) delegates the copy process to the Files.copy( InputStream, OutputStream ). This last method does not check for the end of stream (-1) but checks for no byte read (0). It means that, if your network had a little pause, it could read 0 bytes and end the copy process, even if the stream isn't finished to be downloaded by the OS.
@Miere It is impossible for InputStream.read() to return zero unless you provided a zero length buffer or count, 'little pause' or otherwise. It will block until at least one byte has been transferred or end of stream or an error occurs. Your claim about the internals of Files.copy() is baseless.
I have an unit test that reads a binary file with 2.6TiB. Using Files.copy it always fails on my HDD storage server (XFS) but it fails only a few times my SSH one. Looking at JDK 8 the code of File.copy I've identified that it checks for '> 0' to leave the 'while' loop. I just copied the exactly same code with the -1 and both unit tests never stopped again. Once InputStream can represent Network and local file descriptors, and both IO operations are subject to OS context switching, I cant see why my claim is baseless. One may claim it be working by luck, but it gave no headaches any more.
J
Jared Burrows
public void saveUrl(final String filename, final String urlString)
        throws MalformedURLException, IOException {
    BufferedInputStream in = null;
    FileOutputStream fout = null;
    try {
        in = new BufferedInputStream(new URL(urlString).openStream());
        fout = new FileOutputStream(filename);

        final byte data[] = new byte[1024];
        int count;
        while ((count = in.read(data, 0, 1024)) != -1) {
            fout.write(data, 0, count);
        }
    } finally {
        if (in != null) {
            in.close();
        }
        if (fout != null) {
            fout.close();
        }
    }
}

You'll need to handle exceptions, probably external to this method.


How to download very faster? Like download accelerator?
If in.close throws an exception, fout.close is not called.
@ComFreek That is simply untrue. Using a BufferedInputStream has precisely zero effect on socket timeouts. I had already refuted that as 'urban myth' in my comments to the 'background details' you cited. Three years earlier.
@EJP Thank you for the correction! I removed my comment (for the archive: I linked to this answer stating that BufferedInputStream "can cause unpredictable failures").
+1 My only objection to this answer (and others here) is that the caller cannot distinguish the event "not found" from some connection error (upon which you might want to retry).
J
Jan Nielsen

Here is a concise, readable, JDK-only solution with properly closed resources:

static long download(String url, String fileName) throws IOException {
    try (InputStream in = URI.create(url).toURL().openStream()) {
        return Files.copy(in, Paths.get(fileName));
    }
}

Two lines of code and no dependencies.

Here's a complete file downloader example program with output, error checking, and command line argument checks:

package so.downloader;

import java.io.IOException;
import java.io.InputStream;
import java.net.URI;
import java.nio.file.Files;
import java.nio.file.Paths;

public class Application {
    public static void main(String[] args) throws IOException {
        if (2 != args.length) {
            System.out.println("USAGE: java -jar so-downloader.jar <source-URL> <target-filename>");
            System.exit(1);
        }

        String sourceUrl = args[0];
        String targetFilename = args[1];

        long bytesDownloaded = download(sourceUrl, targetFilename);

        System.out.println(String.format("Downloaded %d bytes from %s to %s.", bytesDownloaded, sourceUrl, targetFilename));
    }

    static long download(String url, String fileName) throws IOException {
        try (InputStream in = URI.create(url).toURL().openStream()) {
            return Files.copy(in, Paths.get(fileName));
        }
    }    
}

As noted in the so-downloader repository README:

To run file download program:

java -jar so-downloader.jar <source-URL> <target-filename>

For example:

java -jar so-downloader.jar https://github.com/JanStureNielsen/so-downloader/archive/main.zip so-downloader-source.zip

P
Peter Mortensen

Downloading a file requires you to read it. Either way, you will have to go through the file in some way. Instead of line by line, you can just read it by bytes from the stream:

BufferedInputStream in = new BufferedInputStream(new URL("http://www.website.com/information.asp").openStream())
byte data[] = new byte[1024];
int count;
while((count = in.read(data, 0, 1024)) != -1)
{
    out.write(data, 0, count);
}

P
Peter Mortensen

This answer is almost exactly like the selected answer, but with two enhancements: it's a method and it closes out the FileOutputStream object:

    public static void downloadFileFromURL(String urlString, File destination) {
        try {
            URL website = new URL(urlString);
            ReadableByteChannel rbc;
            rbc = Channels.newChannel(website.openStream());
            FileOutputStream fos = new FileOutputStream(destination);
            fos.getChannel().transferFrom(rbc, 0, Long.MAX_VALUE);
            fos.close();
            rbc.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

A single call isn't adequate. transferFrom() isnt' specified to complete the entire transfer in a single call. That's why it returns a count. You have to loop.
And your code doesn't close anything if there is an exception.
P
Peter Mortensen

When using Java 7+, use the following method to download a file from the Internet and save it to some directory:

private static Path download(String sourceURL, String targetDirectory) throws IOException
{
    URL url = new URL(sourceURL);
    String fileName = sourceURL.substring(sourceURL.lastIndexOf('/') + 1, sourceURL.length());
    Path targetPath = new File(targetDirectory + File.separator + fileName).toPath();
    Files.copy(url.openStream(), targetPath, StandardCopyOption.REPLACE_EXISTING);

    return targetPath;
}

Documentation is here.


C
Community
import java.io.*;
import java.net.*;

public class filedown {
    public static void download(String address, String localFileName) {
        OutputStream out = null;
        URLConnection conn = null;
        InputStream in = null;

        try {
            URL url = new URL(address);
            out = new BufferedOutputStream(new FileOutputStream(localFileName));
            conn = url.openConnection();
            in = conn.getInputStream();
            byte[] buffer = new byte[1024];

            int numRead;
            long numWritten = 0;

            while ((numRead = in.read(buffer)) != -1) {
                out.write(buffer, 0, numRead);
                numWritten += numRead;
            }

            System.out.println(localFileName + "\t" + numWritten);
        } 
        catch (Exception exception) { 
            exception.printStackTrace();
        } 
        finally {
            try {
                if (in != null) {
                    in.close();
                }
                if (out != null) {
                    out.close();
                }
            } 
            catch (IOException ioe) {
            }
        }
    }

    public static void download(String address) {
        int lastSlashIndex = address.lastIndexOf('/');
        if (lastSlashIndex >= 0 &&
        lastSlashIndex < address.length() - 1) {
            download(address, (new URL(address)).getFile());
        } 
        else {
            System.err.println("Could not figure out local file name for "+address);
        }
    }

    public static void main(String[] args) {
        for (int i = 0; i < args.length; i++) {
            download(args[i]);
        }
    }
}

If in.close throws an exception, out.close is not called.
b
belgariontheking

Personally, I've found Apache's HttpClient to be more than capable of everything I've needed to do with regards to this. Here is a great tutorial on using HttpClient


also commons-io is a great library
P
Peter Mortensen

This is another Java 7 variant based on Brian Risk's answer with usage of a try-with statement:

public static void downloadFileFromURL(String urlString, File destination) throws Throwable {

    URL website = new URL(urlString);
    try(
        ReadableByteChannel rbc = Channels.newChannel(website.openStream());
        FileOutputStream fos = new FileOutputStream(destination);
       ) {

        fos.getChannel().transferFrom(rbc, 0, Long.MAX_VALUE);
    }
}

A single call isn't adequate. transferFrom() isnt' specified to complete the entire transfer in a single call. That's why it returns a count. You have to loop.
I don't know why you're addressing that stupid question to me. It doesn't have anything to do with what I said, and I really decline to have words put into my mouth.
l
leonbloy

There are many elegant and efficient answers here. But the conciseness can make us lose some useful information. In particular, one often does not want to consider a connection error an Exception, and one might want to treat differently some kind of network-related errors - for example, to decide if we should retry the download.

Here's a method that does not throw Exceptions for network errors (only for truly exceptional problems, as malformed url or problems writing to the file)

/**
 * Downloads from a (http/https) URL and saves to a file. 
 * Does not consider a connection error an Exception. Instead it returns:
 *  
 *    0=ok  
 *    1=connection interrupted, timeout (but something was read)
 *    2=not found (FileNotFoundException) (404) 
 *    3=server error (500...) 
 *    4=could not connect: connection timeout (no internet?) java.net.SocketTimeoutException
 *    5=could not connect: (server down?) java.net.ConnectException
 *    6=could not resolve host (bad host, or no internet - no dns)
 * 
 * @param file File to write. Parent directory will be created if necessary
 * @param url  http/https url to connect
 * @param secsConnectTimeout Seconds to wait for connection establishment
 * @param secsReadTimeout Read timeout in seconds - trasmission will abort if it freezes more than this 
 * @return See above
 * @throws IOException Only if URL is malformed or if could not create the file
 */
public static int saveUrl(final Path file, final URL url, 
  int secsConnectTimeout, int secsReadTimeout) throws IOException {
    Files.createDirectories(file.getParent()); // make sure parent dir exists , this can throw exception
    URLConnection conn = url.openConnection(); // can throw exception if bad url
    if( secsConnectTimeout > 0 ) conn.setConnectTimeout(secsConnectTimeout * 1000);
    if( secsReadTimeout > 0 ) conn.setReadTimeout(secsReadTimeout * 1000);
    int ret = 0;
    boolean somethingRead = false;
    try (InputStream is = conn.getInputStream()) {
        try (BufferedInputStream in = new BufferedInputStream(is); OutputStream fout = Files
                .newOutputStream(file)) {
            final byte data[] = new byte[8192];
            int count;
            while((count = in.read(data)) > 0) {
                somethingRead = true;
                fout.write(data, 0, count);
            }
        }
    } catch(java.io.IOException e) { 
        int httpcode = 999;
        try {
            httpcode = ((HttpURLConnection) conn).getResponseCode();
        } catch(Exception ee) {}
        if( somethingRead && e instanceof java.net.SocketTimeoutException ) ret = 1;
        else if( e instanceof FileNotFoundException && httpcode >= 400 && httpcode < 500 ) ret = 2; 
        else if( httpcode >= 400 && httpcode < 600 ) ret = 3; 
        else if( e instanceof java.net.SocketTimeoutException ) ret = 4; 
        else if( e instanceof java.net.ConnectException ) ret = 5; 
        else if( e instanceof java.net.UnknownHostException ) ret = 6;  
        else throw e;
    }
    return ret;
}

P
Peter Mortensen

It's possible to download the file with with Apache's HttpComponents instead of Commons IO. This code allows you to download a file in Java according to its URL and save it at the specific destination.

public static boolean saveFile(URL fileURL, String fileSavePath) {

    boolean isSucceed = true;

    CloseableHttpClient httpClient = HttpClients.createDefault();

    HttpGet httpGet = new HttpGet(fileURL.toString());
    httpGet.addHeader("User-Agent", "Mozilla/5.0 (Windows NT 6.3; WOW64; rv:34.0) Gecko/20100101 Firefox/34.0");
    httpGet.addHeader("Referer", "https://www.google.com");

    try {
        CloseableHttpResponse httpResponse = httpClient.execute(httpGet);
        HttpEntity fileEntity = httpResponse.getEntity();

        if (fileEntity != null) {
            FileUtils.copyInputStreamToFile(fileEntity.getContent(), new File(fileSavePath));
        }

    } catch (IOException e) {
        isSucceed = false;
    }

    httpGet.releaseConnection();

    return isSucceed;
}

In contrast to the single line of code:

FileUtils.copyURLToFile(fileURL, new File(fileSavePath),
                        URLS_FETCH_TIMEOUT, URLS_FETCH_TIMEOUT);

This code will give you more control over a process and let you specify not only time-outs, but User-Agent and Referer values, which are critical for many websites.


P
Peter Mortensen

Below is the sample code to download a movie from the Internet with Java code:

URL url = new
URL("http://103.66.178.220/ftp/HDD2/Hindi%20Movies/2018/Hichki%202018.mkv");
    BufferedInputStream bufferedInputStream = new  BufferedInputStream(url.openStream());
    FileOutputStream stream = new FileOutputStream("/home/sachin/Desktop/test.mkv");

    int count = 0;
    byte[] b1 = new byte[100];

    while((count = bufferedInputStream.read(b1)) != -1) {
        System.out.println("b1:" + b1 + ">>" + count + ">> KB downloaded:" + new File("/home/sachin/Desktop/test.mkv").length()/1024);
        stream.write(b1, 0, count);
    }

Generally, answers are much more helpful if they include an explanation of what the code is intended to do, and why that solves the problem without introducing others.
This code never closes anything, and uses a ridiculously small buffer,
4
4 revs, 2 users 66%

To summarize (and somehow polish and update) previous answers. The three following methods are practically equivalent. (I added explicit timeouts, because I think they are a must. Nobody wants a download to freeze forever when the connection is lost.)

public static void saveUrl1(final Path file, final URL url,
    int secsConnectTimeout, int secsReadTimeout))
    throws MalformedURLException, IOException {

    // Files.createDirectories(file.getParent()); // Optional, make sure parent directory exists
    try (BufferedInputStream in = new BufferedInputStream(
         streamFromUrl(url, secsConnectTimeout,secsReadTimeout));
         OutputStream fout = Files.newOutputStream(file)) {

            final byte data[] = new byte[8192];
            int count;
            while((count = in.read(data)) > 0)
                fout.write(data, 0, count);
        }
}

public static void saveUrl2(final Path file, final URL url,
    int secsConnectTimeout, int secsReadTimeout))
    throws MalformedURLException, IOException {

    // Files.createDirectories(file.getParent()); // Optional, make sure parent directory exists
    try (ReadableByteChannel rbc = Channels.newChannel(
             streamFromUrl(url, secsConnectTimeout, secsReadTimeout)
        );
        FileChannel channel = FileChannel.open(file,
             StandardOpenOption.CREATE,
             StandardOpenOption.TRUNCATE_EXISTING,
             StandardOpenOption.WRITE)
        ) {

        channel.transferFrom(rbc, 0, Long.MAX_VALUE);
    }
}

public static void saveUrl3(final Path file, final URL url,
    int secsConnectTimeout, int secsReadTimeout))
    throws MalformedURLException, IOException {

    // Files.createDirectories(file.getParent()); // Optional, make sure parent directory exists
    try (InputStream in = streamFromUrl(url, secsConnectTimeout,secsReadTimeout) ) {
        Files.copy(in, file, StandardCopyOption.REPLACE_EXISTING);
    }
}

public static InputStream streamFromUrl(URL url,int secsConnectTimeout,int secsReadTimeout) throws IOException {
    URLConnection conn = url.openConnection();
    if(secsConnectTimeout>0)
        conn.setConnectTimeout(secsConnectTimeout*1000);
    if(secsReadTimeout>0)
        conn.setReadTimeout(secsReadTimeout*1000);
    return conn.getInputStream();
}

I don't find significant differences, and all seem right to me. They are safe and efficient. (Differences in speed seem hardly relevant - I write 180 MB from the local server to a SSD disk in times that fluctuate around 1.2 to 1.5 secs). They don't require external libraries. All work with arbitrary sizes and (to my experience) HTTP redirections.

Additionally, all throw FileNotFoundException if the resource is not found (error 404, typically), and java.net.UnknownHostException if the DNS resolution failed; other IOException correspond to errors during transmission.


V
Valentyn Kolesnikov

There is a method, U.fetch(url), in the underscore-java library.

File pom.xml:

<dependency>
  <groupId>com.github.javadev</groupId>
  <artifactId>underscore</artifactId>
  <version>1.74</version>
</dependency>

Code example:

import com.github.underscore.U;
import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Paths;

public class Download {
    public static void main(String[] args) throws IOException {
        Files.write(Paths.get("data.bin"),
            U.fetch("https://stackoverflow.com/questions"
                + "/921262/how-to-download-and-save-a-file-from-internet-using-java").blob());
    }
}

how useful is this answer, when the link becomes invalid? Please look at How to Answer
You code won't compiles. Question ask for solution in Java, but your answer look like JavaScript
@talex I added pom.xml section and improved code example.
The question is about saving data to a file in a directory, not reading it all into a string, which is invalid in the case of binary data.
@user207421 I added example with saving binary file. Files.write(Paths.get("data.bin"), U.fetch(url).blob()).
P
Peter Mortensen

You can do this in one line using netloader for Java:

new NetFile(new File("my/zips/1.zip"), "https://example.com/example.zip", -1).load(); // Returns true if succeed, otherwise false.

P
Peter Mortensen

This can read a file on the Internet and write it into a file.

import java.net.URL;
import java.io.FileOutputStream;
import java.io.File;

public class Download {
    public static void main(String[] args) throws Exception {
         URL url = new URL("https://www.google.com/images/branding/googlelogo/1x/googlelogo_color_272x92dp.png");  // Input URL
         FileOutputStream out = new FileOutputStream(new File("out.png"));  // Output file
         out.write(url.openStream().readAllBytes());
         out.close();
    }
}

r
ruslanKhodzhaev

Solution on java.net.http.HttpClient using Authorization:

HttpClient client = HttpClient.newHttpClient();

HttpRequest request = HttpRequest.newBuilder()
        .GET()
        .header("Accept", "application/json")
        // .header("Authorization", "Basic ci5raG9kemhhZXY6NDdiYdfjlmNUM=") if you need
        .uri(URI.create("https://jira.google.ru/secure/attachment/234096/screenshot-1.png"))
        .build();

HttpResponse<InputStream> response = client.send(request, HttpResponse.BodyHandlers.ofInputStream());

try (InputStream in = response.body()) {
    Files.copy(in, Paths.get(target + "screenshot-1.png"), StandardCopyOption.REPLACE_EXISTING);
}

"Authorization" is commented out. What is its role (in light of the first sentence's "...using Authorization")?
This doesn't even compile (also indicated by the syntax highligting) - near "screenshot-1.png"".
@PeterMortensen If resource is free, you don't need Authorization. Syntax error has been fixed.
P
Peter Mortensen

There is an issue with simple usage of:

org.apache.commons.io.FileUtils.copyURLToFile(URL, File)

if you need to download and save very large files, or in general if you need automatic retries in case connection is dropped.

I suggest Apache HttpClient in such cases, along with org.apache.commons.io.FileUtils. For example:

GetMethod method = new GetMethod(resource_url);
try {
    int statusCode = client.executeMethod(method);
    if (statusCode != HttpStatus.SC_OK) {
        logger.error("Get method failed: " + method.getStatusLine());
    }
    org.apache.commons.io.FileUtils.copyInputStreamToFile(
        method.getResponseBodyAsStream(), new File(resource_file));
    } catch (HttpException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    } finally {
    method.releaseConnection();
}

This code doesn't handle retries any better than any other answer or comment here: that is to say, it doesn't do them at all.
P
Peter Mortensen

First method using the new channel

ReadableByteChannel aq = Channels.newChannel(new url("https//asd/abc.txt").openStream());
FileOutputStream fileOS = new FileOutputStream("C:Users/local/abc.txt")
FileChannel writech = fileOS.getChannel();

Second method using FileUtils

FileUtils.copyURLToFile(new url("https//asd/abc.txt", new local file on system("C":/Users/system/abc.txt"));

Third method using

InputStream xy = new ("https//asd/abc.txt").openStream();

This is how we can download file by using basic Java code and other third-party libraries. These are just for quick reference. Please google with the above keywords to get detailed information and other options.


3rd method does not compile. Neither the 1st nor the 3rd woudl actually copy anything.
P
Peter Mortensen

If you are behind a proxy, you can set the proxies in the Java program as below:

Properties systemSettings = System.getProperties();
systemSettings.put("proxySet", "true");
systemSettings.put("https.proxyHost", "HTTPS proxy of your org");
systemSettings.put("https.proxyPort", "8080");

If you are not behind a proxy, don't include the lines above in your code. Full working code to download a file when you are behind a proxy.

public static void main(String[] args) throws IOException {
    String url = "https://raw.githubusercontent.com/bpjoshi/fxservice/master/src/test/java/com/bpjoshi/fxservice/api/TradeControllerTest.java";
    OutputStream outStream = null;
    URLConnection connection = null;
    InputStream is = null;
    File targetFile = null;
    URL server = null;

    // Setting up proxies
    Properties systemSettings = System.getProperties();
        systemSettings.put("proxySet", "true");
        systemSettings.put("https.proxyHost", "HTTPS proxy of my organisation");
        systemSettings.put("https.proxyPort", "8080");
        // The same way we could also set proxy for HTTP
        System.setProperty("java.net.useSystemProxies", "true");
        // Code to fetch file
    try {
        server = new URL(url);
        connection = server.openConnection();
        is = connection.getInputStream();
        byte[] buffer = new byte[is.available()];
        is.read(buffer);

        targetFile = new File("src/main/resources/targetFile.java");
        outStream = new FileOutputStream(targetFile);
        outStream.write(buffer);
    } catch (MalformedURLException e) {
        System.out.println("THE URL IS NOT CORRECT ");
        e.printStackTrace();
    } catch (IOException e) {
        System.out.println("I/O exception");
        e.printStackTrace();
    }
    finally{
        if(outStream != null)
            outStream.close();
    }
}

systemSettings.put("proxySet", "true"); is an urban myth deriving from the HotJava bean that became defunct in 1998. In any Sun or Oracle JDK it does exactly nothing. Proof: set it to false in any situation when you need the other proxy settings and watch it continue to work.
hmm interesting, gonna check more about it. thanks
g
galkin
public class DownloadManager {

    static String urls = "[WEBSITE NAME]";

    public static void main(String[] args) throws IOException{
        URL url = verify(urls);
        HttpURLConnection connection = (HttpURLConnection) url.openConnection();
        InputStream in = null;
        String filename = url.getFile();
        filename = filename.substring(filename.lastIndexOf('/') + 1);
        FileOutputStream out = new FileOutputStream("C:\\Java2_programiranje/Network/DownloadTest1/Project/Output" + File.separator + filename);
        in = connection.getInputStream();
        int read = -1;
        byte[] buffer = new byte[4096];
        while((read = in.read(buffer)) != -1){
            out.write(buffer, 0, read);
            System.out.println("[SYSTEM/INFO]: Downloading file...");
        }
        in.close();
        out.close();
        System.out.println("[SYSTEM/INFO]: File Downloaded!");
    }
    private static URL verify(String url){
        if(!url.toLowerCase().startsWith("http://")) {
            return null;
        }
        URL verifyUrl = null;

        try{
            verifyUrl = new URL(url);
        }catch(Exception e){
            e.printStackTrace();
        }
        return verifyUrl;
    }
}

You can improve your answer by providing information how does your code work instead of just dumping it.
and by fixing it to close resources if there is an exception.