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How to convert OutputStream to InputStream?

I am on the stage of development, where I have two modules and from one I got output as a OutputStream and second one, which accepts only InputStream. Do you know how to convert OutputStream to InputStream (not vice versa, I mean really this way) that I will be able to connect these two parts?

Thanks

@c0mrade, the op wants something like IOUtils.copy, only in the other direction. When someone writes into an OutputStream, it becomes available for someone else to use in an InputStream. This is basically what PipedOutputStream/PipedInputStream do. Unfortunately the Piped streams can't be built from other streams.
so the PipedOutputStream/PipedInputStream is the solution?
Basically in order for PipedStreams to work in your case, your OutputStream would need to be constructed like new YourOutputStream(thePipedOutputStream) and new YourInputStream(thePipedInputStream) which probably is not the way your stream works. So I don't think this is the solution.

m
mikeho

There seem to be many links and other such stuff, but no actual code using pipes. The advantage of using java.io.PipedInputStream and java.io.PipedOutputStream is that there is no additional consumption of memory. ByteArrayOutputStream.toByteArray() returns a copy of the original buffer, so that means that whatever you have in memory, you now have two copies of it. Then writing to an InputStream means you now have three copies of the data.

The code using lambdas (hat-tip to @John Manko from the comments):

PipedInputStream in = new PipedInputStream();
final PipedOutputStream out = new PipedOutputStream(in);
// in a background thread, write the given output stream to the
// PipedOutputStream for consumption
((Runnable)() -> {originalByteArrayOutputStream.writeTo(out);}).run();

One thing that @John Manko noted is that in certain cases, when you don't have control of the creation of the OutputStream, you may end up in a situation where the creator may clean up the OutputStream object prematurely. If you are getting the ClosedPipeException, then you should try inverting the constructors:

PipedInputStream in = new PipedInputStream(out);
((Runnable)() -> {originalByteArrayOutputStream.writeTo(out);}).run();

Note you can invert the constructors for the examples below too.

The code using try-with-resources:

// take the copy of the stream and re-write it to an InputStream
PipedInputStream in = new PipedInputStream();
    new Thread(new Runnable() {
        public void run () {
            // try-with-resources here
            // putting the try block outside the Thread will cause the
            // PipedOutputStream resource to close before the Runnable finishes
            try (final PipedOutputStream out = new PipedOutputStream(in)) {
                // write the original OutputStream to the PipedOutputStream
                // note that in order for the below method to work, you need
                // to ensure that the data has finished writing to the
                // ByteArrayOutputStream
                originalByteArrayOutputStream.writeTo(out);
            }
            catch (IOException e) {
                // logging and exception handling should go here
            }
        }
    }).start();

The original code I wrote:

// take the copy of the stream and re-write it to an InputStream
PipedInputStream in = new PipedInputStream();
final PipedOutputStream out = new PipedOutputStream(in);
new Thread(new Runnable() {
    public void run () {
        try {
            // write the original OutputStream to the PipedOutputStream
            // note that in order for the below method to work, you need
            // to ensure that the data has finished writing to the
            // ByteArrayOutputStream
            originalByteArrayOutputStream.writeTo(out);
        }
        catch (IOException e) {
            // logging and exception handling should go here
        }
        finally {
            // close the PipedOutputStream here because we're done writing data
            // once this thread has completed its run
            if (out != null) {
                // close the PipedOutputStream cleanly
                out.close();
            }
        }   
    }
}).start();

This code assumes that the originalByteArrayOutputStream is a ByteArrayOutputStream as it is usually the only usable output stream, unless you're writing to a file. I hope this helps! The great thing about this is that since it's in a separate thread, it also is working in parallel, so whatever is consuming your input stream will be streaming out of your old output stream too. That is beneficial because the buffer can remain smaller and you'll have less latency and less memory usage.

If you don't have a ByteArrayOutputStream, then instead of using writeTo(), you will have to use one of the write() methods in the java.io.OutputStream class or one of the other methods available in a subclass.


I voted this up, but it's better to pass out to in's constructor, otherwise you might get a closed pipe exception on in due to race condition (which I experienced). Using Java 8 Lambdas: PipedInputStream in = new PipedInputStream(out); ((Runnable)() -> {originalOutputStream.writeTo(out);}).run(); return in;
No, my case stems from when I store PDFs in Mongo GridFS, and then stream to the client using Jax-RS. MongoDB supplies an OutputStream, but Jax-RS requires an InputStream. My path method would return to the container with an InputStream before the OutputStream was fully established, it seems (perhaps the buffer hadn't been cached yet). Anyway, Jax-RS would throw of pipe closed exception on the InputStream. Odd, but that's what happened half the time. Changing to the code above prevents that.
@JohnManko I was looking into this more and I saw from the PipedInputStream Javadocs: A pipe is said to be broken if a thread that was providing data bytes to the connected piped output stream is no longer alive. So what I'm suspecting is that if you're using the example above, the thread is completing before Jax-RS is consuming the input stream. At the same time, I looked at the MongoDB Javadocs. GridFSDBFile has an input stream, so why not just pass that to Jax-RS?
@JohnManko At the same time, the order of the initialization shouldn't really matter, so I will update the answer to clarify that point. My other comment was intended to find the root cause of your problem, because the initialization order really shouldn't matter. (I know that it works for you. That suggest to me that there's a timing problem between the input stream and the output stream. As your system takes on more load or other factors, those timings will change and you may run into the problem again. Flipping the initialization shouldn't be a real fix — from what the Javadocs tell me.)
@DennisCheung yeah, of course. Nothing's free, but it's certainly going to be smaller than a 15MB copy. Optimizations would include using a thread pool instead to reduce the GC churn with constant thread/object creation.
m
malana

An OutputStream is one where you write data to. If some module exposes an OutputStream, the expectation is that there is something reading at the other end.

Something that exposes an InputStream, on the other hand, is indicating that you will need to listen to this stream, and there will be data that you can read.

So it is possible to connect an InputStream to an OutputStream

InputStream----read---> intermediateBytes[n] ----write----> OutputStream

As someone metioned, this is what the copy() method from IOUtils lets you do. It does not make sense to go the other way... hopefully this makes some sense

UPDATE:

Of course the more I think of this, the more I can see how this actually would be a requirement. I know some of the comments mentioned Piped input/ouput streams, but there is another possibility.

If the output stream that is exposed is a ByteArrayOutputStream, then you can always get the full contents by calling the toByteArray() method. Then you can create an input stream wrapper by using the ByteArrayInputStream sub-class. These two are pseudo-streams, they both basically just wrap an array of bytes. Using the streams this way, therefore, is technically possible, but to me it is still very strange...


copy() do this IS to OS according to API, I need it to do backwards
The usecase is very simple: Imagine you have a serialization library (for example, serializing to JSON) and a transport layer (say, Tomcat) which takes an InputStream. So you need to pipe the OutputStream from JSON over an HTTP connection which wants to read from an InputStream.
This is useful when unit testing and you are super pedantic about avoiding touching the file system.
@JBCP 's comment is spot on. Another use case is using PDFBox to build PDFs during an HTTP request. PDFBox using an OutputStream to save a PDF object, and the REST API accepts an InputStream to reply to the client. Hence, an OutputStream -> InputStream is a very real-world use case.
"you can always get the full contents by calling the toByteArray() method" the point of using streams is to not load the whole content into memory!!
K
KlimczakM

As input and output streams are just start and end point, the solution is to temporary store data in byte array. So you must create intermediate ByteArrayOutputStream, from which you create byte[] that is used as input for new ByteArrayInputStream.

public void doTwoThingsWithStream(InputStream inStream, OutputStream outStream){ 
  //create temporary bayte array output stream
  ByteArrayOutputStream baos = new ByteArrayOutputStream();
  doFirstThing(inStream, baos);
  //create input stream from baos
  InputStream isFromFirstData = new ByteArrayInputStream(baos.toByteArray()); 
  doSecondThing(isFromFirstData, outStream);
}

Hope it helps.


baos.toByteArray() creates a copy with System.arraycopy. Thanks to @mikeho for pointing out developer.classpath.org/doc/java/io/…
V
Vijay
ByteArrayOutputStream buffer = (ByteArrayOutputStream) aOutputStream;
byte[] bytes = buffer.toByteArray();
InputStream inputStream = new ByteArrayInputStream(bytes);

You should not use this since toByteArray() method body is like this return Arrays.copyOf(buf, count); which returns a new array.
java.io.FileOutputStream cannot be cast to java.io.ByteArrayOutputStream
R
Rob Whelan

You will need an intermediate class which will buffer between. Each time InputStream.read(byte[]...) is called, the buffering class will fill the passed in byte array with the next chunk passed in from OutputStream.write(byte[]...). Since the sizes of the chunks may not be the same, the adapter class will need to store a certain amount until it has enough to fill the read buffer and/or be able to store up any buffer overflow.

This article has a nice breakdown of a few different approaches to this problem:

http://blog.ostermiller.org/convert-java-outputstream-inputstream


thanks @mckamey, the method based on Circular Buffers is exactly what i need !
k
koppor

The easystream open source library has direct support to convert an OutputStream to an InputStream: http://io-tools.sourceforge.net/easystream/tutorial/tutorial.html

// create conversion
final OutputStreamToInputStream<Void> out = new OutputStreamToInputStream<Void>() {
    @Override
    protected Void doRead(final InputStream in) throws Exception {
           LibraryClass2.processDataFromInputStream(in);
           return null;
        }
    };
try {   
     LibraryClass1.writeDataToTheOutputStream(out);
} finally {
     // don't miss the close (or a thread would not terminate correctly).
     out.close();
}

They also list other options: http://io-tools.sourceforge.net/easystream/outputstream_to_inputstream/implementations.html

Write the data the data into a memory buffer (ByteArrayOutputStream) get the byteArray and read it again with a ByteArrayInputStream. This is the best approach if you're sure your data fits into memory.

Copy your data to a temporary file and read it back.

Use pipes: this is the best approach both for memory usage and speed (you can take full advantage of the multi-core processors) and also the standard solution offered by Sun.

Use InputStreamFromOutputStream and OutputStreamToInputStream from the easystream library.


Yes!, use easystream!
N
Nick Russler

I encountered the same problem with converting a ByteArrayOutputStream to a ByteArrayInputStream and solved it by using a derived class from ByteArrayOutputStream which is able to return a ByteArrayInputStream that is initialized with the internal buffer of the ByteArrayOutputStream. This way no additional memory is used and the 'conversion' is very fast:

package info.whitebyte.utils;
import java.io.ByteArrayInputStream;
import java.io.ByteArrayOutputStream;

/**
 * This class extends the ByteArrayOutputStream by 
 * providing a method that returns a new ByteArrayInputStream
 * which uses the internal byte array buffer. This buffer
 * is not copied, so no additional memory is used. After
 * creating the ByteArrayInputStream the instance of the
 * ByteArrayInOutStream can not be used anymore.
 * <p>
 * The ByteArrayInputStream can be retrieved using <code>getInputStream()</code>.
 * @author Nick Russler
 */
public class ByteArrayInOutStream extends ByteArrayOutputStream {
    /**
     * Creates a new ByteArrayInOutStream. The buffer capacity is
     * initially 32 bytes, though its size increases if necessary.
     */
    public ByteArrayInOutStream() {
        super();
    }

    /**
     * Creates a new ByteArrayInOutStream, with a buffer capacity of
     * the specified size, in bytes.
     *
     * @param   size   the initial size.
     * @exception  IllegalArgumentException if size is negative.
     */
    public ByteArrayInOutStream(int size) {
        super(size);
    }

    /**
     * Creates a new ByteArrayInputStream that uses the internal byte array buffer 
     * of this ByteArrayInOutStream instance as its buffer array. The initial value 
     * of pos is set to zero and the initial value of count is the number of bytes 
     * that can be read from the byte array. The buffer array is not copied. This 
     * instance of ByteArrayInOutStream can not be used anymore after calling this
     * method.
     * @return the ByteArrayInputStream instance
     */
    public ByteArrayInputStream getInputStream() {
        // create new ByteArrayInputStream that respects the current count
        ByteArrayInputStream in = new ByteArrayInputStream(this.buf, 0, this.count);

        // set the buffer of the ByteArrayOutputStream 
        // to null so it can't be altered anymore
        this.buf = null;

        return in;
    }
}

I put the stuff on github: https://github.com/nickrussler/ByteArrayInOutStream


what if the content does not fit into the buffer?
Then you should not use a ByteArrayInputStream in the first place.
This solution will have all bytes in memory. For small files this will be ok but then you can also use getBytes() on ByteArrayOutput Stream
If you mean toByteArray this would cause the internal buffer to be copied, which would take twice as much memory as my approach. Edit: Ah i understand, for small files this works of course..
Waste of time. ByteArrayOutputStream has a writeTo method to transfer content to another output stream
D
Dave Moten

The library io-extras may be useful. For example if you want to gzip an InputStream using GZIPOutputStream and you want it to happen synchronously (using the default buffer size of 8192):

InputStream is = ...
InputStream gz = IOUtil.pipe(is, o -> new GZIPOutputStream(o));

Note that the library has 100% unit test coverage (for what that's worth of course!) and is on Maven Central. The Maven dependency is:

<dependency>
  <groupId>com.github.davidmoten</groupId>
  <artifactId>io-extras</artifactId>
  <version>0.1</version>
</dependency>

Be sure to check for a later version.


L
Luc Vaillant

From my point of view, java.io.PipedInputStream/java.io.PipedOutputStream is the best option to considere. In some situations you may want to use ByteArrayInputStream/ByteArrayOutputStream. The problem is that you need to duplicate the buffer to convert a ByteArrayOutputStream to a ByteArrayInputStream. Also ByteArrayOutpuStream/ByteArrayInputStream are limited to 2GB. Here is an OutpuStream/InputStream implementation I wrote to bypass ByteArrayOutputStream/ByteArrayInputStream limitations (Scala code, but easily understandable for java developpers):

import java.io.{IOException, InputStream, OutputStream}

import scala.annotation.tailrec

/** Acts as a replacement for ByteArrayOutputStream
  *
  */
class HugeMemoryOutputStream(capacity: Long) extends OutputStream {
  private val PAGE_SIZE: Int = 1024000
  private val ALLOC_STEP: Int = 1024

  /** Pages array
    *
    */
  private var streamBuffers: Array[Array[Byte]] = Array.empty[Array[Byte]]

  /** Allocated pages count
    *
    */
  private var pageCount: Int = 0

  /** Allocated bytes count
    *
    */
  private var allocatedBytes: Long = 0

  /** Current position in stream
    *
    */
  private var position: Long = 0

  /** Stream length
    *
    */
  private var length: Long = 0

  allocSpaceIfNeeded(capacity)

  /** Gets page count based on given length
    *
    * @param length   Buffer length
    * @return         Page count to hold the specified amount of data
    */
  private def getPageCount(length: Long) = {
    var pageCount = (length / PAGE_SIZE).toInt + 1

    if ((length % PAGE_SIZE) == 0) {
      pageCount -= 1
    }

    pageCount
  }

  /** Extends pages array
    *
    */
  private def extendPages(): Unit = {
    if (streamBuffers.isEmpty) {
      streamBuffers = new Array[Array[Byte]](ALLOC_STEP)
    }
    else {
      val newStreamBuffers = new Array[Array[Byte]](streamBuffers.length + ALLOC_STEP)
      Array.copy(streamBuffers, 0, newStreamBuffers, 0, streamBuffers.length)
      streamBuffers = newStreamBuffers
    }

    pageCount = streamBuffers.length
  }

  /** Ensures buffers are bug enough to hold specified amount of data
    *
    * @param value  Amount of data
    */
  private def allocSpaceIfNeeded(value: Long): Unit = {
    @tailrec
    def allocSpaceIfNeededIter(value: Long): Unit = {
      val currentPageCount = getPageCount(allocatedBytes)
      val neededPageCount = getPageCount(value)

      if (currentPageCount < neededPageCount) {
        if (currentPageCount == pageCount) extendPages()

        streamBuffers(currentPageCount) = new Array[Byte](PAGE_SIZE)
        allocatedBytes = (currentPageCount + 1).toLong * PAGE_SIZE

        allocSpaceIfNeededIter(value)
      }
    }

    if (value < 0) throw new Error("AllocSpaceIfNeeded < 0")
    if (value > 0) {
      allocSpaceIfNeededIter(value)

      length = Math.max(value, length)
      if (position > length) position = length
    }
  }

  /**
    * Writes the specified byte to this output stream. The general
    * contract for <code>write</code> is that one byte is written
    * to the output stream. The byte to be written is the eight
    * low-order bits of the argument <code>b</code>. The 24
    * high-order bits of <code>b</code> are ignored.
    * <p>
    * Subclasses of <code>OutputStream</code> must provide an
    * implementation for this method.
    *
    * @param      b the <code>byte</code>.
    */
  @throws[IOException]
  override def write(b: Int): Unit = {
    val buffer: Array[Byte] = new Array[Byte](1)

    buffer(0) = b.toByte

    write(buffer)
  }

  /**
    * Writes <code>len</code> bytes from the specified byte array
    * starting at offset <code>off</code> to this output stream.
    * The general contract for <code>write(b, off, len)</code> is that
    * some of the bytes in the array <code>b</code> are written to the
    * output stream in order; element <code>b[off]</code> is the first
    * byte written and <code>b[off+len-1]</code> is the last byte written
    * by this operation.
    * <p>
    * The <code>write</code> method of <code>OutputStream</code> calls
    * the write method of one argument on each of the bytes to be
    * written out. Subclasses are encouraged to override this method and
    * provide a more efficient implementation.
    * <p>
    * If <code>b</code> is <code>null</code>, a
    * <code>NullPointerException</code> is thrown.
    * <p>
    * If <code>off</code> is negative, or <code>len</code> is negative, or
    * <code>off+len</code> is greater than the length of the array
    * <code>b</code>, then an <tt>IndexOutOfBoundsException</tt> is thrown.
    *
    * @param      b   the data.
    * @param      off the start offset in the data.
    * @param      len the number of bytes to write.
    */
  @throws[IOException]
  override def write(b: Array[Byte], off: Int, len: Int): Unit = {
    @tailrec
    def writeIter(b: Array[Byte], off: Int, len: Int): Unit = {
      val currentPage: Int = (position / PAGE_SIZE).toInt
      val currentOffset: Int = (position % PAGE_SIZE).toInt

      if (len != 0) {
        val currentLength: Int = Math.min(PAGE_SIZE - currentOffset, len)
        Array.copy(b, off, streamBuffers(currentPage), currentOffset, currentLength)

        position += currentLength

        writeIter(b, off + currentLength, len - currentLength)
      }
    }

    allocSpaceIfNeeded(position + len)
    writeIter(b, off, len)
  }

  /** Gets an InputStream that points to HugeMemoryOutputStream buffer
    *
    * @return InputStream
    */
  def asInputStream(): InputStream = {
    new HugeMemoryInputStream(streamBuffers, length)
  }

  private class HugeMemoryInputStream(streamBuffers: Array[Array[Byte]], val length: Long) extends InputStream {
    /** Current position in stream
      *
      */
    private var position: Long = 0

    /**
      * Reads the next byte of data from the input stream. The value byte is
      * returned as an <code>int</code> in the range <code>0</code> to
      * <code>255</code>. If no byte is available because the end of the stream
      * has been reached, the value <code>-1</code> is returned. This method
      * blocks until input data is available, the end of the stream is detected,
      * or an exception is thrown.
      *
      * <p> A subclass must provide an implementation of this method.
      *
      * @return the next byte of data, or <code>-1</code> if the end of the
      *         stream is reached.
      */
    @throws[IOException]
    def read: Int = {
      val buffer: Array[Byte] = new Array[Byte](1)

      if (read(buffer) == 0) throw new Error("End of stream")
      else buffer(0)
    }

    /**
      * Reads up to <code>len</code> bytes of data from the input stream into
      * an array of bytes.  An attempt is made to read as many as
      * <code>len</code> bytes, but a smaller number may be read.
      * The number of bytes actually read is returned as an integer.
      *
      * <p> This method blocks until input data is available, end of file is
      * detected, or an exception is thrown.
      *
      * <p> If <code>len</code> is zero, then no bytes are read and
      * <code>0</code> is returned; otherwise, there is an attempt to read at
      * least one byte. If no byte is available because the stream is at end of
      * file, the value <code>-1</code> is returned; otherwise, at least one
      * byte is read and stored into <code>b</code>.
      *
      * <p> The first byte read is stored into element <code>b[off]</code>, the
      * next one into <code>b[off+1]</code>, and so on. The number of bytes read
      * is, at most, equal to <code>len</code>. Let <i>k</i> be the number of
      * bytes actually read; these bytes will be stored in elements
      * <code>b[off]</code> through <code>b[off+</code><i>k</i><code>-1]</code>,
      * leaving elements <code>b[off+</code><i>k</i><code>]</code> through
      * <code>b[off+len-1]</code> unaffected.
      *
      * <p> In every case, elements <code>b[0]</code> through
      * <code>b[off]</code> and elements <code>b[off+len]</code> through
      * <code>b[b.length-1]</code> are unaffected.
      *
      * <p> The <code>read(b,</code> <code>off,</code> <code>len)</code> method
      * for class <code>InputStream</code> simply calls the method
      * <code>read()</code> repeatedly. If the first such call results in an
      * <code>IOException</code>, that exception is returned from the call to
      * the <code>read(b,</code> <code>off,</code> <code>len)</code> method.  If
      * any subsequent call to <code>read()</code> results in a
      * <code>IOException</code>, the exception is caught and treated as if it
      * were end of file; the bytes read up to that point are stored into
      * <code>b</code> and the number of bytes read before the exception
      * occurred is returned. The default implementation of this method blocks
      * until the requested amount of input data <code>len</code> has been read,
      * end of file is detected, or an exception is thrown. Subclasses are encouraged
      * to provide a more efficient implementation of this method.
      *
      * @param      b   the buffer into which the data is read.
      * @param      off the start offset in array <code>b</code>
      *                 at which the data is written.
      * @param      len the maximum number of bytes to read.
      * @return the total number of bytes read into the buffer, or
      *         <code>-1</code> if there is no more data because the end of
      *         the stream has been reached.
      * @see java.io.InputStream#read()
      */
    @throws[IOException]
    override def read(b: Array[Byte], off: Int, len: Int): Int = {
      @tailrec
      def readIter(acc: Int, b: Array[Byte], off: Int, len: Int): Int = {
        val currentPage: Int = (position / PAGE_SIZE).toInt
        val currentOffset: Int = (position % PAGE_SIZE).toInt

        val count: Int = Math.min(len, length - position).toInt

        if (count == 0 || position >= length) acc
        else {
          val currentLength = Math.min(PAGE_SIZE - currentOffset, count)
          Array.copy(streamBuffers(currentPage), currentOffset, b, off, currentLength)

          position += currentLength

          readIter(acc + currentLength, b, off + currentLength, len - currentLength)
        }
      }

      readIter(0, b, off, len)
    }

    /**
      * Skips over and discards <code>n</code> bytes of data from this input
      * stream. The <code>skip</code> method may, for a variety of reasons, end
      * up skipping over some smaller number of bytes, possibly <code>0</code>.
      * This may result from any of a number of conditions; reaching end of file
      * before <code>n</code> bytes have been skipped is only one possibility.
      * The actual number of bytes skipped is returned. If <code>n</code> is
      * negative, the <code>skip</code> method for class <code>InputStream</code> always
      * returns 0, and no bytes are skipped. Subclasses may handle the negative
      * value differently.
      *
      * The <code>skip</code> method of this class creates a
      * byte array and then repeatedly reads into it until <code>n</code> bytes
      * have been read or the end of the stream has been reached. Subclasses are
      * encouraged to provide a more efficient implementation of this method.
      * For instance, the implementation may depend on the ability to seek.
      *
      * @param      n the number of bytes to be skipped.
      * @return the actual number of bytes skipped.
      */
    @throws[IOException]
    override def skip(n: Long): Long = {
      if (n < 0) 0
      else {
        position = Math.min(position + n, length)
        length - position
      }
    }
  }
}

Easy to use, no buffer duplication, no 2GB memory limit

val out: HugeMemoryOutputStream = new HugeMemoryOutputStream(initialCapacity /*may be 0*/)

out.write(...)
...

val in1: InputStream = out.asInputStream()

in1.read(...)
...

val in2: InputStream = out.asInputStream()

in2.read(...)
...

M
Michael Wyraz

If you want to make an OutputStream from an InputStream there is one basic problem. A method writing to an OutputStream blocks until it is done. So the result is available when the writing method is finished. This has 2 consequences:

If you use only one thread, you need to wait until everything is written (so you need to store the stream's data in memory or disk). If you want to access the data before it is finished, you need a second thread.

Variant 1 can be implemented using byte arrays or filed. Variant 1 can be implemented using pipies (either directly or with extra abstraction - e.g. RingBuffer or the google lib from the other comment).

Indeed with standard java there is no other way to solve the problem. Each solution is an implementataion of one of these.

There is one concept called "continuation" (see wikipedia for details). In this case basically this means:

there is a special output stream that expects a certain amount of data

if the ammount is reached, the stream gives control to it's counterpart which is a special input stream

the input stream makes the amount of data available until it is read, after that, it passes back the control to the output stream

While some languages have this concept built in, for java you need some "magic". For example "commons-javaflow" from apache implements such for java. The disadvantage is that this requires some special bytecode modifications at build time. So it would make sense to put all the stuff in an extra library whith custom build scripts.


k
kleopatra

Old post but might help others, Use this way:

OutputStream out = new ByteArrayOutputStream();
...
out.write();
...
ObjectInputStream ois = new ObjectInputStream(new ByteArrayInputStream(out.toString().getBytes()));

to String --> size problem
Besides, calling toString().getBytes() on a stream *will not return the contents of the stream.
R
Ranjit Aneesh

Though you cannot convert an OutputStream to an InputStream, java provides a way using PipedOutputStream and PipedInputStream that you can have data written to a PipedOutputStream to become available through an associated PipedInputStream.
Sometime back I faced a similar situation when dealing with third party libraries that required an InputStream instance to be passed to them instead of an OutputStream instance.
The way I fixed this issue is to use the PipedInputStream and PipedOutputStream.
By the way they are tricky to use and you must use multithreading to achieve what you want. I recently published an implementation on github which you can use.
Here is the link . You can go through the wiki to understand how to use it.