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How to program a delay in Swift 3

In earlier versions of Swift, one could create a delay with the following code:

let time = dispatch_time(dispatch_time_t(DISPATCH_TIME_NOW), 4 * Int64(NSEC_PER_SEC))
dispatch_after(time, dispatch_get_main_queue()) {
    //put your code which should be executed with a delay here
}

But now, in Swift 3, Xcode automatically changes 6 different things but then the following error appears: "Cannot convert DispatchTime.now to expected value dispatch_time_t aka UInt64."

How can one create a delay before running a sequence of code in Swift 3?


D
Daniel Storm

After a lot of research, I finally figured this one out.

DispatchQueue.main.asyncAfter(deadline: .now() + 2.0) { // Change `2.0` to the desired number of seconds.
   // Code you want to be delayed
}

This creates the desired "wait" effect in Swift 3 and Swift 4.

Inspired by a part of this answer.


Useful contribution, thanks! Updating for the most recent Swift 3: DispatchQueue.main.asyncAfter(deadline: when)
You could make your code a bit more swifty by replacing "+ 2" with "+ .seconds(2)". Or, for the ultimate in swiftyness, you could drop the first line and replace "deadline: when" with "deadline: .now() + .seconds(2)".
Still working 3/12/2017. Thank you very much for this :)
"After a lot of research, I finally figured this one out"... the question and the answer has the same datetime lol
Literally my most visited post on SO. Its easier to find this post than actually remember it or find it elsewhere in my code ;)
b
byaruhaf

I like one-line notation for GCD, it's more elegant:

    DispatchQueue.main.asyncAfter(deadline: .now() + 42.0) {
        // do stuff 42 seconds later
    }

Also, in iOS 10 we have new Timer methods, e.g. block initializer:

(so delayed action may be canceled)

    let timer = Timer.scheduledTimer(withTimeInterval: 42.0, repeats: false) { (timer) in
        // do stuff 42 seconds later
    }

Btw, keep in mind: by default, timer is added to the default run loop mode. It means timer may be frozen when the user is interacting with the UI of your app (for example, when scrolling a UIScrollView) You can solve this issue by adding the timer to the specific run loop mode:

RunLoop.current.add(timer, forMode: .common)

At this blog post you can find more details.


Good catch! I hadn't see this yet.
plus one for the Timer comparison and the disclaimer about the main runloop!
Nice catch! This is engineering.
V
Vakas

Try the following function implemented in Swift 3.0 and above

func delayWithSeconds(_ seconds: Double, completion: @escaping () -> ()) {
    DispatchQueue.main.asyncAfter(deadline: .now() + seconds) { 
        completion()
    }
}

Usage

delayWithSeconds(1) {
   //Do something
}

You basically just copied this answer but yes this is good, thanks.
How to cancel this?
P
Peter

Try the below code for delay

//MARK: First Way

func delayForWork() {
    delay(3.0) {
        print("delay for 3.0 second")
    }
}

delayForWork()

// MARK: Second Way

DispatchQueue.main.asyncAfter(deadline: .now() + 0.5) {
    // your code here delayed by 0.5 seconds
}

First way displays have error "Use of unresolved identifier 'delay'"
This programmer is working with a helper method in his code base and has for a long time. So delay was code he has used for a while not knowing it is not apart of Apple's SDK.
Z
Zohaib Brohi

One way is to use DispatchQueue.main.asyncAfter as a lot of people have answered.

Another way is to use perform(_:with:afterDelay:). More details here

perform(#selector(delayedFunc), with: nil, afterDelay: 3)

@IBAction func delayedFunc() {
    // implement code
}

P
Paul B

Most common things to use are asyncAfter() and Timer. But if blocking thread is OK, then there is an option:

sleep(3) // in seconds
usleep   // in 1/million of second 

For asynchronous programming (Swift 5.5) pausing in func looks like this:

func someAsyncFunc() async {
    await Task.sleep(2_000_000_000)  // Two seconds
    // Code to be executed with a delay here
}

P
Pratyush Pratik

//Runs function after x seconds

public static func runThisAfterDelay(seconds: Double, after: @escaping () -> Void) {
    runThisAfterDelay(seconds: seconds, queue: DispatchQueue.main, after: after)
}

public static func runThisAfterDelay(seconds: Double, queue: DispatchQueue, after: @escaping () -> Void) {
    let time = DispatchTime.now() + Double(Int64(seconds * Double(NSEC_PER_SEC))) / Double(NSEC_PER_SEC)
    queue.asyncAfter(deadline: time, execute: after)
}

//Use:-

runThisAfterDelay(seconds: x){
  //write your code here
}