I have two shell scripts, a.sh and b.sh.
How can I call b.sh from within the shell script a.sh?
b.sh did not have executable permissions. It might be a good thing to check.
./ before the script name, example, instead: b.sh, use: ./b.sh
No such file or directory error stackoverflow.com/a/2920431/1356559
There are a couple of different ways you can do this:
Make the other script executable, add the #!/bin/bash line at the top, and the path where the file is to the $PATH environment variable. Then you can call it as a normal command; Or call it with the source command (alias is .), like this: source /path/to/script Or use the bash command to execute it, like: /bin/bash /path/to/script
The first and third approaches execute the script as another process, so variables and functions in the other script will not be accessible. The second approach executes the script in the first script's process, and pulls in variables and functions from the other script (so they are usable from the calling script).
In the second method, if you are using exit in second script, it will exit the first script as well. Which will not happen in first and third methods.
chmod a+x /path/to/fileor else it's not going to be executable. Only applies to the ./script method.