Java how to replace 2 or more spaces with single space in string and delete leading and trailing spaces

Try this:

String after = before.trim().replaceAll(" +", " ");

See also

String.trim() Returns a copy of the string, with leading and trailing whitespace omitted.

Returns a copy of the string, with leading and trailing whitespace omitted.

regular-expressions.info/Repetition

No trim() regex

It's also possible to do this with just one replaceAll, but this is much less readable than the trim() solution. Nonetheless, it's provided here just to show what regex can do:

    String[] tests = {
        "  x  ",          // [x]
        "  1   2   3  ",  // [1 2 3]
        "",               // []
        "   ",            // []
    };
    for (String test : tests) {
        System.out.format("[%s]%n",
            test.replaceAll("^ +| +$|( )+", "$1")
        );
    }

There are 3 alternates:

^_+ : any sequence of spaces at the beginning of the string Match and replace with $1, which captures the empty string

Match and replace with $1, which captures the empty string

_+$ : any sequence of spaces at the end of the string Match and replace with $1, which captures the empty string

Match and replace with $1, which captures the empty string

(_)+ : any sequence of spaces that matches none of the above, meaning it's in the middle Match and replace with $1, which captures a single space

Match and replace with $1, which captures a single space

See also

regular-expressions.info/Anchors

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You just need a:

replaceAll("\\s{2,}", " ").trim();

where you match one or more spaces and replace them with a single space and then trim whitespaces at the beginning and end (you could actually invert by first trimming and then matching to make the regex quicker as someone pointed out).

To test this out quickly try:

System.out.println(new String(" hello     there   ").trim().replaceAll("\\s{2,}", " "));

and it will return:

"hello there"

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Use the Apache commons StringUtils.normalizeSpace(String str) method. See docs here

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This worked perfectly for me : sValue = sValue.trim().replaceAll("\\s+", " ");

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The following code will compact any whitespace between words and remove any at the string's beginning and end

String input = "\n\n\n  a     string with     many    spaces,    \n"+
               " a \t tab and a newline\n\n";
String output = input.trim().replaceAll("\\s+", " ");
System.out.println(output);

This will output a string with many spaces, a tab and a newline

Note that any non-printable characters including spaces, tabs and newlines will be compacted or removed

For more information see the respective documentation:

String#trim() method

String#replaceAll(String regex, String replacement) method

For information about Java's regular expression implementation see the documentation of the Pattern class

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"[ ]{2,}"

This will match more than one space.

String mytext = " hello     there   ";
//without trim -> " hello there"
//with trim -> "hello there"
mytext = mytext.trim().replaceAll("[ ]{2,}", " ");
System.out.println(mytext);

OUTPUT:

hello there

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trim() method removes the leading and trailing spaces and using replaceAll("regex", "string to replace") method with regex "\s+" matches more than one space and will replace it with a single space

myText = myText.trim().replaceAll("\\s+"," ");

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To eliminate spaces at the beginning and at the end of the String, use String#trim() method. And then use your mytext.replaceAll("( )+", " ").

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You can first use String.trim(), and then apply the regex replace command on the result.

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Try this one.

Sample Code

String str = " hello     there   ";
System.out.println(str.replaceAll("( +)"," ").trim());

OUTPUT

hello there

First it will replace all the spaces with single space. Than we have to supposed to do trim String because Starting of the String and End of the String it will replace the all space with single space if String has spaces at Starting of the String and End of the String So we need to trim them. Than you get your desired String.

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String blogName = "how to   do    in  java   .         com"; 
 
String nameWithProperSpacing = blogName.replaceAll("\\\s+", " ");

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trim()

Removes only the leading & trailing spaces.

From Java Doc, "Returns a string whose value is this string, with any leading and trailing whitespace removed."

System.out.println(" D ev  Dum my ".trim());

"D ev Dum my"

replace(), replaceAll()

Replaces all the empty strings in the word,

System.out.println(" D ev  Dum my ".replace(" ",""));

System.out.println(" D ev  Dum my ".replaceAll(" ",""));

System.out.println(" D ev  Dum my ".replaceAll("\\s+",""));

Output:

"DevDummy"

"DevDummy"

"DevDummy"

Note: "\s+" is the regular expression similar to the empty space character.

Reference : https://www.codedjava.com/2018/06/replace-all-spaces-in-string-trim.html

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A lot of correct answers been provided so far and I see lot of upvotes. However, the mentioned ways will work but not really optimized or not really readable. I recently came across the solution which every developer will like.

String nameWithProperSpacing = StringUtils.normalizeSpace( stringWithLotOfSpaces );

You are done. This is readable solution.

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In Kotlin it would look like this

val input = "\n\n\n  a     string with     many    spaces,    \n"
val cleanedInput = input.trim().replace(Regex("(\\s)+"), " ")

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You could use lookarounds also.

test.replaceAll("^ +| +$|(?<= ) ", "");

OR

test.replaceAll("^ +| +$| (?= )", "")

<space>(?= ) matches a space character which is followed by another space character. So in consecutive spaces, it would match all the spaces except the last because it isn't followed by a space character. This leaving you a single space for consecutive spaces after the removal operation.

Example:

    String[] tests = {
            "  x  ",          // [x]
            "  1   2   3  ",  // [1 2 3]
            "",               // []
            "   ",            // []
        };
        for (String test : tests) {
            System.out.format("[%s]%n",
                test.replaceAll("^ +| +$| (?= )", "")
            );
        }

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String str = " hello world"

reduce spaces first

str = str.trim().replaceAll(" +", " ");

capitalize the first letter and lowercase everything else

str = str.substring(0,1).toUpperCase() +str.substring(1,str.length()).toLowerCase();

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you should do it like this

String mytext = " hello     there   ";
mytext = mytext.replaceAll("( +)", " ");

put + inside round brackets.

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String str = "  this is string   ";
str = str.replaceAll("\\s+", " ").trim();

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See String.replaceAll.

Use the regex "\s" and replace with " ".

Then use String.trim.

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This worked for me

scan= filter(scan, " [\\s]+", " ");
scan= sac.trim();

where filter is following function and scan is the input string:

public String filter(String scan, String regex, String replace) {
    StringBuffer sb = new StringBuffer();

    Pattern pt = Pattern.compile(regex);
    Matcher m = pt.matcher(scan);

    while (m.find()) {
        m.appendReplacement(sb, replace);
    }

    m.appendTail(sb);

    return sb.toString();
}

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The simplest method for removing white space anywhere in the string.

 public String removeWhiteSpaces(String returnString){
    returnString = returnString.trim().replaceAll("^ +| +$|( )+", " ");
    return returnString;
}

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check this...

public static void main(String[] args) {
    String s = "A B  C   D    E F      G\tH I\rJ\nK\tL";
    System.out.println("Current      : "+s);
    System.out.println("Single Space : "+singleSpace(s));
    System.out.println("Space  count : "+spaceCount(s));
    System.out.format("Replace  all = %s", s.replaceAll("\\s+", ""));

    // Example where it uses the most.
    String s = "My name is yashwanth . M";
    String s2 = "My nameis yashwanth.M";

    System.out.println("Normal  : "+s.equals(s2));
    System.out.println("Replace : "+s.replaceAll("\\s+", "").equals(s2.replaceAll("\\s+", "")));

} 

If String contains only single-space then replace() will not-replace,

If spaces are more than one, Then replace() action performs and removes spacess.

public static String singleSpace(String str){
    return str.replaceAll("  +|   +|\t|\r|\n","");
}

To count the number of spaces in a String.

public static String spaceCount(String str){
    int i = 0;
    while(str.indexOf(" ") > -1){
      //str = str.replaceFirst(" ", ""+(i++));
        str = str.replaceFirst(Pattern.quote(" "), ""+(i++)); 
    }
    return str;
}

Pattern.quote("?") returns literal pattern String.

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My method before I found the second answer using regex as a better solution. Maybe someone needs this code.

private String replaceMultipleSpacesFromString(String s){
    if(s.length() == 0 ) return "";

    int timesSpace = 0;
    String res = "";

    for (int i = 0; i < s.length(); i++) {
        char c = s.charAt(i);

        if(c == ' '){
            timesSpace++;
            if(timesSpace < 2)
                res += c;
        }else{
            res += c;
            timesSpace = 0;
        }
    }

    return res.trim();
}

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Stream version, filters spaces and tabs.

Stream.of(str.split("[ \\t]")).filter(s -> s.length() > 0).collect(Collectors.joining(" "))

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String myText = "   Hello     World   ";
myText = myText.trim().replace(/ +(?= )/g,'');


// Output: "Hello World"

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string.replaceAll("\s+", " ");

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If you already use Guava (v. 19+) in your project you may want to use this:

CharMatcher.whitespace().trimAndCollapseFrom(input, ' ');

or, if you need to remove exactly SPACE symbol ( or U+0020, see more whitespaces) use:

CharMatcher.anyOf(" ").trimAndCollapseFrom(input, ' ');

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public class RemoveExtraSpacesEfficient {

    public static void main(String[] args) {

        String s = "my    name is    mr    space ";

        char[] charArray = s.toCharArray();

        char prev = s.charAt(0);

        for (int i = 0; i < charArray.length; i++) {
            char cur = charArray[i];
            if (cur == ' ' && prev == ' ') {

            } else {
                System.out.print(cur);
            }
            prev = cur;
        }
    }
}

The above solution is the algorithm with the complexity of O(n) without using any java function.

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Please use below code

package com.myjava.string;

import java.util.StringTokenizer;

public class MyStrRemoveMultSpaces {

    public static void main(String a[]){

        String str = "String    With Multiple      Spaces";

        StringTokenizer st = new StringTokenizer(str, " ");

        StringBuffer sb = new StringBuffer();

        while(st.hasMoreElements()){
            sb.append(st.nextElement()).append(" ");
        }

        System.out.println(sb.toString().trim());
    }
}

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Hello sorry for the delay! Here is the best and the most efficiency answer that you are looking for:

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class MyPatternReplace {

public String replaceWithPattern(String str,String replace){

    Pattern ptn = Pattern.compile("\\s+");
    Matcher mtch = ptn.matcher(str);
    return mtch.replaceAll(replace);
}

public static void main(String a[]){
    String str = "My    name    is  kingkon.  ";
    MyPatternReplace mpr = new MyPatternReplace();
    System.out.println(mpr.replaceWithPattern(str, " "));
}

So your output of this example will be: My name is kingkon.

However this method will remove also the "\n" that your string may has. So if you do not want that just use this simple method:

while (str.contains("  ")){  //2 spaces
str = str.replace("  ", " "); //(2 spaces, 1 space) 
}

And if you want to strip the leading and trailing spaces too just add:

str = str.trim();

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